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91Ó°ÊÓ

Write just the form of the partial fraction decomposition. Do not solve for the constants. $$\frac{3 x-2}{2 x^{4}+4 x^{3}+2 x^{2}}$$

Short Answer

Expert verified
The form of the partial fraction decomposition is \(\frac{A}{x} + \frac{B}{x^2} + \frac{C}{x+1} + \frac{D}{(x+1)^2}\).

Step by step solution

01

Factorization of the denominator

Doing the factorization of the denominator of the given function which is \(2x^{4}+4x^{3}+2x^{2}\), it can be partially factored and written as follows: \(2x^2(x^2 + 2x + 1)\). The term inside the bracket is a perfect square. So, the fully factored form of the denominator is \(2x^2(x + 1)^2\).
02

Write out the form of the Partial Fraction Decomposition

The form of the Partial Fraction Decomposition depends on the denominator after factorization. The denominator \(2x^2(x + 1)^2\) has 2 distinct factors which are \(x\) and \(x + 1\). Each will correspond to a term in the decomposition. Also, the repeated factor \(x + 1\) makes this irreducible quadratic factor, so it requires 2 terms, one for each power up to the highest power in the original fraction. So, the form of the partial fraction decomposition is: \(\frac{A}{x} + \frac{B}{x^2} + \frac{C}{x+1} + \frac{D}{(x+1)^2}\). The decomposition was written without calculating the coefficients A, B, C, D, as instructed in the exercise. It is important to note that each term in the decomposition corresponds to its independent factor in the fully factored denominator.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorization
Factorization is the process of breaking down an expression into a product of simpler expressions, called factors. It is crucial in many areas of algebra as it simplifies expressions and solves equations. In the context of Partial Fraction Decomposition, factorization of the denominator is the first necessary step.

For the given rational expression, the denominator is a polynomial: \(2x^{4} + 4x^{3} + 2x^{2}\). To factor this polynomial, we look for common factors across all terms. Here, each term shares a factor of \(2x^2\), which allows us to factor it out. This gives us: \(2x^2(x^2 + 2x + 1)\).

Further, we identify \(x^2 + 2x + 1\) as a perfect square, namely \((x + 1)^2\). Thus, the fully factored form of the denominator is \(2x^2(x + 1)^2\). This form reveals the structure needed for setting up the partial fraction decomposition.
Rational Expressions
Rational expressions are fractions where both the numerator and the denominator are polynomials. Simplifying these expressions involves a series of steps like factorization, cancellation, and sometimes performing long division.

Understanding rational expressions is important for performing operations such as addition, subtraction, multiplication, and division with algebraic fractions. Each of these steps requires the notions of simplification and manipulation based on algebraic rules.

In the realm of partial fraction decomposition, simplifying the expression begins with factorizing the denominator. As demonstrated in this exercise, recognizing the structure of the denominator \(2x^2(x + 1)^2\) guides us in breaking down the expression into simpler, understandable components.
Algebraic Fractions
Algebraic fractions are fractions that contain variables in the numerator, the denominator, or both. They are similar to numerical fractions but require extra care due to the presence of variables.

In algebraic fractions, the process of partial fraction decomposition is employed to express a complex fraction into simpler components. This approach is particularly useful in calculus for integrating rational functions or solving differential equations.

The decomposition set up \(\frac{A}{x} + \frac{B}{x^2} + \frac{C}{x+1} + \frac{D}{(x+1)^2}\) shows how the original complex algebraic fraction can be expressed as a sum of simpler fractions whose denominators are the factors of the original denominator. This method allows easier management and manipulation of complex algebraic fractions.

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Most popular questions from this chapter

The following table lists the caloric content of a typical fast-food meal. Food (single serving) Calories Cheeseburger Medium order of fries Medium cola (21 oz) \(\begin{array}{lc}\text { Food (single serving) } & \text { Calories } \\\ \text { Cheeseburger } & 330 \\ \text { Medium order of fries } & 450 \\\ \text { Medium cola }(210 z) & 220\end{array}\) (a) After a lunch that consists of a cheeseburger, a medium order of fries, and a medium cola, you decide to burn off a quarter of the total calories in the meal by some combination of running and walking. You know that running burns 8 calories per minute and walking burns 3 calories per minute. If you exercise for a total of 40 minutes, how many minutes should you spend on each activity? (b) Rework part (a) for the case in which you exercise for a total of only 20 minutes. Do you get a realistic solution? Explain your answer.

Tara is planning a party for at least 100 people. She is going to serve two types of appetizers: mini pizzas and mini quiche. Each mini pizza costs \(\$ .50\) and each mini quiche costs \(\$ .60 .\) Tara thinks that each person will eat only one item, either a mini pizza or a mini quiche. She also estimates that she will need at least 60 mini pizzas and at least 20 mini quiche. How many mini pizzas and how many mini quiche should Tara order to minimize her cost?

A family owns and operates three businesses. On their income-tax return, they have to report the depreciation deductions for the three businesses separately. In \(2004,\) their depreciation deductions consisted of use of a car, plus depreciation on 5 -year equipment (on which onc-fifth of the original value is deductible per year) and 10-year equipment (on which one- tenth of the original valuc is deductible per year). The car use (in miles) for cach business in 2004 is given in the following table, along with the original value of the depreciable 5 - and 10 year equipment used in each business that year. $$\begin{array}{|c|c|c|c|}\hline & \begin{array}{c}\text { Car } \\\\\text { Use }\end{array} & \begin{array}{c}\text { Original } \\\\\text { Value, 5-Year }\end{array} & \begin{array}{c}\text { Original } \\\\\text { Value, 10-Year }\end{array} \\\\\text { Business } & \text { (miles) } & \text { Equipment (S) } & \text { Equipment (S) } \\\\\hline 1 & 3200 & 9850 & 435 \\\2 & 8800 & 12,730 & 980 \\\3 & 6880 & 2240 & 615\\\\\hline\end{array}$$ The depreciation deduction for car use in 2004 was 37.5 cents per mile. Use matrix multiplication to determine the total depreciation deduction for each business in 2004.

Let \(I=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]\) and \(A=\left[\begin{array}{rr}2 & -1 \\ 1 & 0\end{array}\right] .\) Calculate \(A I\) and IA. What do you observe?

Answer the question pertaining to the matrices. $$A=\left[\begin{array}{ll}a & b \\\c & d \\\e & f\end{array}\right] \text { and } B=\left[\begin{array}{lll}g & h & i \\\j & k & l\end{array}\right]$$ Let \(Q=B A,\) and find \(q_{11}\) and \(q_{22}\) without performing the entire multiplication of matrix \(B\) by matrix \(A\).

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