/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Find the inverse of each matrix.... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the inverse of each matrix. $$\left[\begin{array}{ll}3 & 4 \\\1 & 2\end{array}\right]$$

Short Answer

Expert verified
The inverse of the matrix \(\left[\begin{array}{ll}3 & 4 \\ 1 & 2\end{array}\right]\) is \(\left[\begin{array}{ll}1 & -2 \\ -0.5 & 1.5\end{array}\right]\)

Step by step solution

01

Calculate the Determinant

The determinant of a 2x2 matrix \(\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]\) is given by \(ad - bc\). Substituting a=3, b=4, c=1, d=2 into this formula gives a determinant of \(3 * 2 - 4 * 1 = 2\).
02

Swap a and d and Change Sign of b and c

To find the adjugate matrix, swap elements a and d. Change the signs of elements b and c. This gives \(\left[\begin{array}{ll}2 & -4 \\ -1 & 3\end{array}\right]\).
03

Divide each entry by the determinant

Finally divide each matrix element in the matrix obtained in step 2 by the determinant (2) and the result will be the required inverse of the initial matrix: \( \left[\begin{array}{ll}2/2 & -4/2 \\ -1/2 & 3/2\end{array}\right] = \left[\begin{array}{ll}1 & -2 \\ -0.5 & 1.5\end{array}\right]\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Determinant of a Matrix
The determinant of a matrix is a unique number associated with square matrices. It is a scalar value that provides crucial information about a matrix, such as whether it has an inverse or what its volume scaling factor is in linear transformations. For a 2x2 matrix, the determinant is calculated using the formula: \( ad - bc \).In simpler terms, if we take a matrix \( \left[\begin{array}{ll}a & b\ \c & d\end{array}\right] \), the determinant would be the product of the elements on the main diagonal (a and d), minus the product of the off-diagonal elements (b and c). To illustrate, consider the matrix from the exercise:\[ \left[\begin{array}{ll}3 & 4\ \1 & 2\end{array}\right] \]Following the determinant formula, the solution becomes \( 3 \times 2 - 4 \times 1 = 6 - 4 = 2 \). The determinant is not just a step towards finding the matrix inverse; it's essential for understanding many other matrix-related concepts.
Adjugate Matrix
The adjugate of a matrix, also known as the adjoint, is the transpose of the cofactor matrix. It plays a key role in calculating the inverse of a square matrix. The process involves swapping, sign-changing, and transposing operations that may seem convoluted at first, but it follows a precise pattern for 2x2 matrices.For a 2x2 matrix \( \left[\begin{array}{ll}a & b\ \c & d\end{array}\right] \), the adjugate is obtained by swapping elements a and d, then changing the signs of b and c: \( \left[\begin{array}{ll}d & -b\ \-c & a\end{array}\right] \). This operation is critical as it prepares the matrix for the final step of division by the determinant when finding its inverse.
Matrix Operations
Matrix operations include several key computations such as addition, multiplication, and inversion, which can be applied to matrices. These are analogous to arithmetic operations but are performed according to specific rules that take into account the sizes and shapes of the matrices involved. For example, matrix addition requires both matrices to be of the same dimension, while matrix multiplication requires the number of columns in the first matrix to be equal to the number of rows in the second matrix.When we discuss the inversion of matrices, we utilize operations like finding the determinant, obtaining the adjugate, and scalar multiplication, which involves dividing by the determinant. Each of these steps uses fundamental matrix operations to arrive at the final result — the inverse matrix.
2x2 Matrix Inverse
The inverse of a 2x2 matrix is particularly easy to calculate compared to larger matrices. Assuming the determinant is not zero (which means the matrix is invertible), the steps follow a concise pattern. After calculating the determinant and the adjugate, the following operation is straightforward: divide each element of the adjugate by the determinant to get the inverse.Let's apply this to the given exercise matrix \( \left[\begin{array}{ll}3 & 4\ \1 & 2\end{array}\right] \). The determinant is 2, and after following the adjugate process, we obtain \( \left[\begin{array}{ll}2 & -4\ \-1 & 3\end{array}\right] \). Dividing each term by the determinant results in \( \left[\begin{array}{ll}1 & -2\ \-0.5 & 1.5\end{array}\right] \), which is the inverse matrix. This matrix, when multiplied by the original, would result in the identity matrix, confirming its inverseness.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In this set of exercises, you will use the method of solving linear systems using matrices to study real-world problems. Privately owned, single-family homes in a small town were heated with gas, electricity, or oil. The percentage of homes heated with electricity was 9 times the percentage heated with oil. The percentage of homes heated with gas was 40 percentage points higher than the percentage heated with oil and the percentage heated with electricity combined. Find the percentage of homes heated with each type of fuel.

Let \(A=\left[\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right]\) and \(B=\left[\begin{array}{ll}0 & 1 \\ 1 & 1\end{array}\right] .\) What are the product \(A B\) and \(B A ?\) Is it true that if \(A\) and \(B\) are \(2 \times 2\) matrices, then \(A B=B A ?\) Explain.

Consider the following augmented matrix. For what value(s) of \(a\) does the corresponding system of linear equations have infinitely many solutions? One solution? Explain your answers.$$\left[\begin{array}{lll|r}1 & 0 & 0 & -2 \\\0 & 1 & 0 & 5 \\\0 & 0 & a & 0\end{array}\right]$$.

Tara is planning a party for at least 100 people. She is going to serve two types of appetizers: mini pizzas and mini quiche. Each mini pizza costs \(\$ .50\) and each mini quiche costs \(\$ .60 .\) Tara thinks that each person will eat only one item, either a mini pizza or a mini quiche. She also estimates that she will need at least 60 mini pizzas and at least 20 mini quiche. How many mini pizzas and how many mini quiche should Tara order to minimize her cost?

$$\begin{aligned}&\text { If } A=\left[\begin{array}{ll}0 & 1 \\\a & 0\end{array}\right] \text { and } B=\left[\begin{array}{ll}0 & a \\\1 & 0\end{array}\right], \text { for what value(s) of }\\\&a \operatorname{does} A B=\left[\begin{array}{ll}1 & 0 \\\0 & 1\end{array}\right] ?\end{aligned}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.