/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Convert each of the given rectan... [FREE SOLUTION] | 91Ó°ÊÓ

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Convert each of the given rectangular equations to polar form. $$(x+1)^{2}+y^{2}=1$$

Short Answer

Expert verified
The polar form of the given rectangular equation \((x+1)^{2}+y^{2}=1\) is \(r = \cos(\theta)\).

Step by step solution

01

Identification

Identify the given rectangular equation which is \((x+1)^{2}+y^{2}=1\).
02

Transformation

Transform x and y in terms of r and \(\theta\) using the relations \(x = r \cos(\theta)\) and \(y = r \sin(\theta)\). After substitution, we obtain \((r \cos(\theta)+1)^{2}+(r \sin(\theta))^{2}=1\).
03

Expansion and simplification

Expand the squared terms and simplify. We then obtain \(r^{2} \cos^{2}(\theta) + 2r \cos(\theta) + 1 + r^{2} \sin^{2}(\theta) = 1\).
04

Combine similar terms

Combine terms with \(r^{2}\) and simplify to obtain \(r^{2} = -2r \cos(\theta)\).
05

Final polar equation

Divide both sides by -2 to isolate r on the left side, we get the final polar equation \(r = \cos(\theta)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rectangular to Polar Conversion
Converting equations from rectangular form to polar form involves transforming the coordinate system from
  • Cartesian coordinates (x, y)
  • to polar coordinates (r, \(\theta\)).
The main reason for this type of conversion is that polar coordinates can simplify expressions and make certain problems easier to solve.
To convert rectangular coordinates to polar coordinates, we use the relationships:
  • \(x = r \cos(\theta)\)
  • and \(y = r \sin(\theta)\).
In the exercise,
we started with the rectangular equation \((x+1)^2 + y^2 = 1\).
By substituting the polar coordinate equations,
we transformed it to polar form: \((r \cos(\theta) + 1)^2 + (r \sin(\theta))^2 = 1\).
This conversion sets the stage for further simplification.
It's an essential step in solving problems involving both coordinate systems.
Trigonometric Identities
Trigonometric identities serve as the fundamental building blocks for simplifying equations and expressions.
These identities are particularly useful when working with polar coordinates,
as they allow for the simplification of equations involving trigonometric functions.
  • In the context of the exercise, identities such as \(\cos^2(\theta) + \sin^2(\theta) = 1\) play a critical role.
For our problem, after substituting the polar coordinate relations,
we expanded and simplified \(r^2 \cos^2(\theta) + 2r \cos(\theta) + 1 + r^2 \sin^2(\theta) = 1\).
By recognizing that \(\cos^2(\theta) + \sin^2(\theta) = 1\),
we were able to combine terms to get \(r^2\) on one side more succinctly.
Utilizing these identities not only aids in simplifying expressions
but also in revealing underlying relationships between the variables and the geometric components they represent.
Polar Equations
Polar equations express relationships taking into consideration the polar coordinate system,
where relationships are defined in terms of the radius \(r\) and the angle \(\theta\).
These equations provide a different perspective compared to rectangular equations
and can offer a simpler solution pathway for problems involving circles, spirals, or angles.
By the conclusion of our problem,
we arrived at the polar equation \(r = \cos(\theta)\).
  • This final equation is notably more straightforward than the initial rectangular form.
Here, \(r = \cos(\theta)\) indicates that polar coordinates are compactly summarizing the geometry described.
This highlights one of the advantages of using polar equations:
They can easily represent curves and shapes in a simpler and often more insightful manner.
Recognizing when to convert an equation to polar form helps tackle complex geometric problems efficiently.

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Most popular questions from this chapter

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