/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Utilities A telephone pole is po... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Utilities A telephone pole is positioned beside a road that has a slope of \(10^{\circ}\) from the horizontal. When the angle of elevation of the sun is \(65^{\circ},\) the telephone pole casts a shadow that is 20.6 feet long. How tall is the telephone pole?

Short Answer

Expert verified
The height of the telephone pole is approximately 14.6 feet.

Step by step solution

01

Identify relevant angles

The slope of the road is given as 10 degrees, so the angle of elevation is the angle up from the incline. Thus, the relative angle of the sun to the horizontal is \(65^{\circ} - 10^{\circ} = 55^{\circ}\). Next, the angle of depression of the sun to the ground is \(90^{\circ} - 55^{\circ} = 35^{\circ}\). This is the angle formed by the sun's rays with the ground.
02

Use the right triangle

Now, you have all the necessary information to use the tangent of the 35-degree angle to find the height of the pole. The tangent of an angle in a right triangle is the length of the side opposite the angle (the height of the pole) over the length of the side adjacent to the angle (the length of the shadow). Therefore you have the equation \(\tan(35^{\circ}) = \frac{{\text{{height of pole}}}}{20.6}\).
03

Solve the right triangle

Solve for the height of the pole: \(\text{{height of pole}} = \tan(35^{\circ}) \times 20.6 \approx 14.6 \, \text{{feet}}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angle of Elevation
The angle of elevation refers to the angle that is formed between the horizontal line and the line of sight directed upwards. Imagine you are looking up at the top of a telephone pole or a tall building from a point on the ground. The line from your eyes to the top of the structure forms an angle with the ground you are standing on. That angle is what we call the angle of elevation.

Understanding this concept is crucial when dealing with problems involving height and distances. For example, when the sunlight hits a telephone pole, we can assume a straight line (representative of sun rays) from the top of the pole to the end of its shadow on the ground. Here, the telephone pole and the shadow form a right triangle with the ground, and the angle of elevation is the angle inside that triangle, above the horizontal.
Tangent of an Angle
The tangent of an angle is a concept from trigonometry that describes the ratio of the length of the opposite side to the length of the adjacent side in a right-angled triangle. For any given angle in such a triangle, this ratio is constant and is represented as tan(angle). This is particularly handy when you have to solve for an unknown side of a right triangle and you only have one side and an acute angle for reference.

To write it mathematically, if you have a right triangle and are focusing on one of its acute angles, then \( \tan(\text{{angle}}) = \frac{{\text{{opposite}}}}{{\text{{adjacent}}}} \). In the context of our telephone pole problem, if the shadow is the adjacent side and the height of the pole is the opposite side, then knowing the angle of elevation (after adjusting for any incline, as in the slopes of the road) will allow you to determine the height using this tangent function.
Right Triangle
A right triangle is a type of triangle that has one angle exactly equal to \(90^\circ\) (a right angle). The sides forming the right angle are referred to as the 'legs', and the side opposite the right angle is known as the 'hypotenuse', which is also the longest side of the triangle.

Right triangles are fundamental in trigonometry. The reason they are so important is that they allow us to use trigonometric ratios—sine, cosine, and tangent—to find unknown side lengths and angles. Since the angles in a triangle add up to \(180^\circ\), knowing that one angle is a right one simplifies our calculations because we only need to find the measurements for the other two angles, both of which must together add up to \(90^\circ\).

In practical scenarios like our telephone pole problem, identifying a right triangle allows us to use these trigonometric ratios to solve for unknown quantities efficiently.
Trigonometric Functions
Finally, let's talk about trigonometric functions. These functions—sine (sin), cosine (cos), and tangent (tan)—are used to relate the angles of a triangle to the lengths of its sides. They are essential for solving problems in trigonometry.

The sine function represents the ratio of the length of the opposite side to the length of the hypotenuse in a right-angled triangle. The cosine function represents the ratio of the length of the adjacent side to the hypotenuse. And as we've discussed, the tangent function represents the ratio of the length of the opposite side to the length of the adjacent side.

Using these functions, one can solve for missing sides and angles in right triangles, which is exactly what we did in our telephone pole example. By using the adjusted angle of elevation and the tangent function, we determined the height of the pole. Trigonometric functions are key tools in the fields of engineering, physics, and various other sciences where measurement and angles come into play.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Multiply or divide as indicated, and leave the answer in trigonometric form. $$\frac{6\left(\cos \frac{\pi}{12}+i \sin \frac{\pi}{12}\right)}{3\left(\cos \frac{\pi}{4}+i \sin \frac{\pi}{4}\right)}$$

Games A billiard ball traverses a distance of 26 inches on a straight-line path, and then it collides with another ball, changes direction, and traverses a distance of 18 inches on a different straight-line path before coming to a stop. If an angle of \(37^{\circ}\) is formed from the lines that connect the initial location of the ball to the final location of the ball and to the point of the collision, what are the two possible values of the distance \(d\) between the initial and final locations of the ball? Sketch a figure first.

Find a unit vector in the same direction as the given vector. $$\mathbf{u}=\langle 3,4\rangle$$

Round your answers to two decimal places. Lucas pulls a 40 -pound box along a level surface from left to right by attaching a piece of rope to the box and pulling on it with a force \(\mathbf{F}_{1}\) of 20 pounds in the direction \(25^{\circ}\) above the horizontal. A friction force \(\mathbf{F}_{2}\) of 5 pounds is acting on the box as it is being pulled. (A friction force acts in the direction opposite to the direction of motion.) (a) Find the \(x\) and \(y\) components of \(\mathbf{F}_{1}\) (b) Find the \(x\) and \(y\) components of \(\mathbf{F}_{2}\) (c) Use your answers to parts (a) and (b) to express the vector sum \(\mathbf{F}_{1}+\mathbf{F}_{2}\) in terms of its \(x\) and \(y\) components. (d) Give the magnitude and direction of each of the other forces acting on the box. (e) Find the magnitude and direction of the net force acting on the box.

In this set of exercises, you will use vectors and dot products to study real- world problems. In a new video game, Mario and Luigi are at positions defined by the vectors \langle 10,3\rangle and \(\langle x, 15\rangle .\) What must be the value of \(x\) so that their position vectors are orthogonal?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.