/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Find \(\mathbf{u}-\mathbf{v}, \m... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find \(\mathbf{u}-\mathbf{v}, \mathbf{u}+2 \mathbf{v},\) and \(-3 \mathbf{u}+\mathbf{v}\). $$\mathbf{u}=-1.1 \mathbf{i}+4 \mathbf{j}, \mathbf{v}=4 \mathbf{i}+2.4 \mathbf{j}$$

Short Answer

Expert verified
The solution to the vector operations are: \(\mathbf{u}-\mathbf{v} = -5.1 \mathbf{i} + 1.6 \mathbf{j}\), \(\mathbf{u}+2\mathbf{v} = 6.9 \mathbf{i} + 8.8 \mathbf{j}\), \(-3\mathbf{u}+\mathbf{v} = 7.3 \mathbf{i}-9.6 \mathbf{j}\)

Step by step solution

01

Operation 1: Subtraction (\(\mathbf{u}-\mathbf{v}\))

To subtract one vector from another, subtract the corresponding components from each other. So, \(\mathbf{u}-\mathbf{v} = (-1.1-4) \mathbf{i} + (4-2.4) \mathbf{j} = -5.1 \mathbf{i} + 1.6 \mathbf{j}\)
02

Operation 2: Addition and Scalar Multiplication (\(\mathbf{u}+2\mathbf{v}\))

First, scale vector \(\mathbf{v}\) by a factor of 2, then add this result to vector \(\mathbf{u}\). So, \(\mathbf{u}+2\mathbf{v} = (-1.1+2*4) \mathbf{i} + (4 + 2*2.4) \mathbf{j} = 6.9 \mathbf{i} + 8.8 \mathbf{j}\)
03

Operation 3: Scaling and Addition \(-3\mathbf{u}+\mathbf{v}\)

First, scale vector \(\mathbf{u}\) by a factor of -3, then add vector \(\mathbf{v}\) to the result. So, \(-3\mathbf{u}+ \mathbf{v} = (-3*-1.1+4) \mathbf{i}+(-3*4+2.4) \mathbf{j} = 7.3 \mathbf{i} - 9.6 \mathbf{j}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Addition
Vector addition is like combining two arrows' effects. If you have vectors \( \mathbf{u} \) and \( \mathbf{v} \), adding them means simply putting one after the other in a head-to-tail method. This way, it's similar to walking in one direction for \( \mathbf{u} \) units and then continuing for \( \mathbf{v} \) units.

Mathematically, you add their corresponding components. If \( \mathbf{u} = a\mathbf{i} + b\mathbf{j} \) and \( \mathbf{v} = c\mathbf{i} + d\mathbf{j} \), then:
  • \( \mathbf{u} + \mathbf{v} = (a+c)\mathbf{i} + (b+d)\mathbf{j} \)
This combines the horizontal (\( \mathbf{i} \)) and vertical (\( \mathbf{j} \)) parts. For example, if \( \mathbf{u} = -1.1\mathbf{i} + 4\mathbf{j} \) and \( \mathbf{v} = 4\mathbf{i} + 2.4\mathbf{j} \), to find \( \mathbf{u} + \mathbf{v} \), we do:
  • Add \(-1.1 + 4 = 2.9\) for the \( \mathbf{i} \) component.
  • Add \(4 + 2.4 = 6.4\) for the \( \mathbf{j} \) component.
So, \( \mathbf{u} + \mathbf{v} = 2.9\mathbf{i} + 6.4\mathbf{j} \).
Vector Subtraction
In vector subtraction, you're finding the difference or the gap between two vectors. Consider it like reversing the direction of one vector before adding. When you subtract vector \( \mathbf{v} \) from \( \mathbf{u} \), it calculates \( \mathbf{u} - \mathbf{v} \), which effectively involves flipping all components of \( \mathbf{v} \) and then adding.

If \( \mathbf{u} = a\mathbf{i} + b\mathbf{j} \) and \( \mathbf{v} = c\mathbf{i} + d\mathbf{j} \), then:
  • \( \mathbf{u} - \mathbf{v} = (a-c)\mathbf{i} + (b-d)\mathbf{j} \)
This process ensures each respective component is solely influenced by the other vector's component. Using \( \mathbf{u} = -1.1\mathbf{i} + 4\mathbf{j} \) and \( \mathbf{v} = 4\mathbf{i} + 2.4\mathbf{j} \), we compute \( \mathbf{u} - \mathbf{v} \) by subtracting:
  • Subtract \(-1.1 - 4 = -5.1\) from the \( \mathbf{i} \) component.
  • Subtract \(4 - 2.4 = 1.6\) from the \( \mathbf{j} \) component.
Thus, \( \mathbf{u} - \mathbf{v} = -5.1\mathbf{i} + 1.6\mathbf{j} \).
Scalar Multiplication
Scalar multiplication involves stretching or shrinking a vector by a number, known as a scalar. This operation changes the magnitude (or length) of the vector, but not its direction, unless the scalar is negative, which also reverses the direction.

Let's take a vector \( \mathbf{u} = a\mathbf{i} + b\mathbf{j} \). If you multiply it by a scalar \( k \), then:
  • \( k\mathbf{u} = (ka)\mathbf{i} + (kb)\mathbf{j} \)
This operation scales both components by \( k \). Considering \( \mathbf{u} = -1.1\mathbf{i} + 4\mathbf{j} \) and scaling by \( -3 \), we perform:
  • -1.1 becomes \(-3 \times -1.1 = 3.3\).
  • 4 becomes \(-3 \times 4 = -12\).
So, the resulting vector is \( -3\mathbf{u} = 3.3\mathbf{i} - 12\mathbf{j} \). This vector points in the opposite direction and is stretched by 3 times the magnitude of \( \mathbf{u} \). In operations like \(-3\mathbf{u} + \mathbf{v} \), you would then add \( \mathbf{v} = 4\mathbf{i} + 2.4\mathbf{j} \) to this scaled vector.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Let \(z=r(\cos \theta+i \sin \theta)\) be a nonzero complex number, and let \(n\) be a positive integer greater than 1. Verify that each of the following \(n\) numbers is a solution of the equation \(u^{n}=z:\) $$\begin{aligned} &\sqrt[n]{r}\left[\cos \left(\frac{\theta+2 \pi k}{n}\right)+i \sin \left(\frac{\theta+2 \pi k}{n}\right)\right]\\\ &k=0,1,2, \ldots, n-1 \end{aligned}$$ where \(\sqrt[n]{r}\) denotes the positive real number that, when raised to the \(n\) th power, gives \(r .\) (Hint: Use De Moivre's Theorem.)

Show that if \(\|\mathbf{v}\|=0,\) then \(\mathbf{v}=\langle 0,0\rangle\)

Sweepstakes Patrons of a nationwide fast-food chain are given a ticket that gives them a chance of winning a million dollars. The ticket shows a triangle \(A B C\) with the lengths of two sides marked as \(a=6.1 \mathrm{cm}\) and \(b=5.4 \mathrm{cm},\) and the measure of angle \(A\) marked as \(72.5^{\circ} .\) The winning ticket will be chosen from all the entries that correctly state the value of \(c\) rounded to the nearest tenth of a centimeter and the measures of angles \(B\) and \(C\) rounded to the nearest tenth of a degree. To be eligible for the prize, what should you submit as the values of \(c, B,\) and \(C ?\)

This set of exercises will draw on the ideas presented in this section and your general math background. Explain why you cannot use the Law of Sines to solve an oblique triangle if you are given only the three sides of the triangle (SSS) and no two of them are of equal length.

Use De Moivre's Theorem to find each expression. $$(2-2 i)^{4}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.