/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 Find the smallest nomnegation an... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the smallest nomnegation angle betwoen the vectors \(\mathbf{v}\) and \(\mathbf{w} .\) Round your anstoer to the nearest tenth of a degree. $$\mathbf{v}=(-2,0), \mathbf{w}=\langle 0,3\rangle$$

Short Answer

Expert verified
The smallest nonnegation angle between the vectors is \(90^\circ\).

Step by step solution

01

Find the Dot Product

The dot product of vectors \(\mathbf{v} = (-2,0)\) and \(\mathbf{w} = (0,3)\) can be calculated as: \(\mathbf{v} \cdot \mathbf{w} = (-2*0 + 0*3) = 0\)
02

Find the Magnitudes

The magnitude of vector \( \mathbf{v} \) is \( ||\mathbf{v}|| = \sqrt{-2^2 + 0^2} = 2 \) and the magnitude of vector \( \mathbf{w} \) is \( ||\mathbf{w}|| = \sqrt{0^2 + 3^2} = 3 \)
03

Calculate the Angle

Using the formula for the angle between two vectors, cos(\( \theta \)) = \( \frac{\mathbf{v} \cdot \mathbf{w}}{||\mathbf{v}|| ||\mathbf{w}||} \), we get cos(\( \theta \)) = \( \frac{0}{2*3} = 0 \). So, \( \theta = cos^{-1}(0) = 90^\circ \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dot Product
The dot product, also known as the scalar product, plays a pivotal role in finding the angle between two vectors. It is a way of multiplying two vectors to get a single scalar or real number. The dot product of two vectors \( \mathbf{u} \text{ and } \mathbf{v} \) with components \( \mathbf{u} = (u_1, u_2) \text{ and } \mathbf{v} = (v_1, v_2) \) is calculated as \( \mathbf{u} \cdot \mathbf{v} = u_1v_1 + u_2v_2 \).

The result of the dot product tells us about the relationship between the two vectors. For instance, if the dot product is zero, as in the exercise with vectors \( \mathbf{v} \) and \( \mathbf{w} \), this indicates that the vectors are orthogonal, meaning they are at a right angle to each other. If the dot product is positive, the vectors make an acute angle; if it's negative, they form an obtuse angle.

This concept is very useful as it provides a means to calculate the angle between vectors using the cosine of the angle, which leads us to another important concept: cosine similarity.
Magnitude of a Vector
Understanding the magnitude of a vector is crucial when working with vectors and geometry. The magnitude refers to the length or size of the vector and is often denoted as \( ||\mathbf{v}|| \). For a 2D vector \( \mathbf{v} = (v_1, v_2) \), the magnitude is given by the square root of the sum of the squares of its components: \( ||\mathbf{v}|| = \sqrt{v_1^2 + v_2^2} \).

The concept of magnitude is comparable to measuring the straight-line distance from the origin to the point denoted by the vector in a coordinate system. For our exercise, the magnitudes of vectors \( \mathbf{v} \) and \( \mathbf{w} \) are the distances from the origin to the points (-2,0) and (0,3), respectively. Knowing the magnitudes is necessary to apply the formula for finding the angle between vectors using the dot product and cosine similarity.
Cosine Similarity
Cosine similarity is a measure that calculates the cosine of the angle between two non-zero vectors in a multi-dimensional space. It provides an indication of how similar the directional movements of the vectors are. The cosine similarity is obtained using the dot product and the magnitudes of the vectors and is defined by the formula \( \frac{\mathbf{u} \cdot \mathbf{v}}{||\mathbf{u}|| ||\mathbf{v}||} \), where \( \mathbf{u} \) and \( \mathbf{v} \) are the vectors in question.

In the context of our exercise, we used cosine similarity to find the angle between vectors \( \mathbf{v} \) and \( \mathbf{w} \). Since the dot product was zero, the cosine similarity also equaled zero, leading us to conclude that the angle between them is \( 90^\circ \), as the cosine of \( 90^\circ \) is zero. This measure is highly valuable in many fields, including machine learning, where it's used to assess the similarity between documents or vectors of features.

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Most popular questions from this chapter

Find the components of the vector in standard position that satisfy the given conditions. Length \(7 ;\) direction \(276^{\circ}\)

In this set of exercises, you will use vectors and dot products to study real- world problems. \- Work A parent pulling a wagon in which her child is riding along level ground exerts a force of 20 pounds on the handle. The handle makes an angle of \(45^{\circ}\) with the horizontal. How much work is done in pulling the wagon 100 feet, to the nearest foot-pound?

Write each of the given vectors in terms of the unit vectors \(\mathbf{i}\) and \(\mathbf{j}\). $$\mathbf{v}=\langle 5,-3\rangle$$

Round your answers to two decimal places. The world's largest weathervane is located in Montague, Michigan. On a July day in 2007 , it showed that the wind had a speed of 15 miles per hour in the direction \(S 30^{\circ} \mathrm{E}\). Express the wind velocity in component form. (Source: www. wunderground.com)

Round your answers to two decimal places. Lucas pulls a 40 -pound box along a level surface from left to right by attaching a piece of rope to the box and pulling on it with a force \(\mathbf{F}_{1}\) of 20 pounds in the direction \(25^{\circ}\) above the horizontal. A friction force \(\mathbf{F}_{2}\) of 5 pounds is acting on the box as it is being pulled. (A friction force acts in the direction opposite to the direction of motion.) (a) Find the \(x\) and \(y\) components of \(\mathbf{F}_{1}\) (b) Find the \(x\) and \(y\) components of \(\mathbf{F}_{2}\) (c) Use your answers to parts (a) and (b) to express the vector sum \(\mathbf{F}_{1}+\mathbf{F}_{2}\) in terms of its \(x\) and \(y\) components. (d) Give the magnitude and direction of each of the other forces acting on the box. (e) Find the magnitude and direction of the net force acting on the box.

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