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Find \(r\) for the given complex numbers. $$\sqrt{3}+i$$

Short Answer

Expert verified
The magnitude \( r \) of the complex number \( \sqrt{3}+i \) is \( 2 \).

Step by step solution

01

- Identifying the real and imaginary parts of the complex number

For the complex number \( \sqrt{3}+i \), the real part (denoted as \( a \)) is \( \sqrt{3} \) and the imaginary part (denoted as \( b \)) is \( 1 \).
02

- Substituting into formula

By substituting \( a = \sqrt{3} \) and \( b = 1 \) into the formula \( r = \sqrt{a^{2}+b^{2}} \), we get \( r = \sqrt{(\sqrt{3})^{2}+1^{2}} \).
03

- Square and simplify

Next, we square \( \sqrt{3} \) and \( 1 \) to get \( r = \sqrt{3+1} \).
04

- Calculate and obtain the magnitude

Finally, simplify to get the magnitude, \( r = \sqrt{4} \). Simplifying the square root of 4, we get \( r = 2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Real and Imaginary Parts of a Complex Number
Complex numbers are fascinating because they extend the concept of the one-dimensional number line to a plane with two dimensions. To understand them, it's important to dive into the notion of their components known as real and imaginary parts.
For any complex number, it is expressed generally in the form of \( a + bi \). Here, \( a \) represents the real part and \( b \) represents the imaginary part, where \( i \) is the imaginary unit satisfying \( i^2 = -1 \). Simply put, in the complex number \( \sqrt{3} + i \), the real part is \( \sqrt{3} \), and the imaginary part is \( 1 \), as it is equivalent to \( 1 \times i \).
Understanding the separation into real and imaginary parts helps to visualize complex numbers on a plane called the complex plane, where the x-axis represents the real part, and the y-axis represents the imaginary part.
Magnitude of a Complex Number
The magnitude of a complex number, often referred to as its absolute value or modulus, gives us the "length" of the vector it represents on the complex plane. It's like finding the distance of a point from the origin in a two-dimensional space.
To calculate the magnitude \( r \) of a complex number \( a + bi \), the formula is:
  • \( r = \sqrt{a^{2} + b^{2}} \)
For our given complex number \( \sqrt{3} + i \), substitute \( a = \sqrt{3} \) and \( b = 1 \) into the formula. This gives:
  • \( r = \sqrt{(\sqrt{3})^{2} + 1^{2}} \)
Simplifying, we have:
  • \( r = \sqrt{3 + 1} \)
  • \( r = \sqrt{4} \)
  • \( r = 2 \)
The magnitude 2 simply represents how "far" the complex number is from the center of the complex plane.
The Pythagorean Theorem and Complex Numbers
The Pythagorean Theorem plays an integral role in understanding the magnitude of complex numbers. This theorem, traditionally used to determine the length of the hypotenuse of a right triangle, is crucial when dealing with complex numbers.
For a right triangle with sides labeled \( a \) and \( b \), and hypotenuse \( r \), the Pythagorean Theorem states:
  • \( a^2 + b^2 = r^2 \)
In the context of complex numbers, \( a \) and \( b \) are analogous to the real and imaginary parts, and \( r \) is the magnitude or the hypotenuse.
Using the complex number \( \sqrt{3} + i \) as an example, we square the real part \( \sqrt{3} \) and the imaginary part \( 1 \), adding the squares to find the hypotenuse:
  • \( (\sqrt{3})^2 + 1^2 = 4 \)
Then, solve for \( r \):
  • \( r = \sqrt{4} = 2 \)
This allows us to see the geometric significance of complex numbers and their magnitudes.

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