Chapter 6: Problem 72
Use a scientific calculator to find the solutions of the given equations, in radians, that lie in the interval \([0,2 \pi)\). $$4 \sin ^{2} x-7 \sin x+3=0$$
Short Answer
Expert verified
The solutions to the equation in the interval [0, \(2 \pi\)] are \(x = \frac{\pi}{2}\), \(x = 0.848\) and \(x = 2.293\).
Step by step solution
01
Identify the coefficients and Apply the quadratic formula
The coefficients are \(a = 4\), \(b = -7\), and \(c = 3\). Plug these into the quadratic formula to give: \(\sin x = \frac{-(-7) \pm \sqrt{(-7)^2 - 4*4*3}}{2*4}\) . This simplifies to \(\sin x = \frac{7 \pm \sqrt{49 - 48}}{8}\) which further simplifies to \(\sin x = \frac{7 \pm \sqrt{1}}{8}\). So \(\sin x = 1\) or \(\sin x = \frac{3}{4}\)
02
Find the corresponding angles for the solutions from Step 1
For \(\sin x = 1\), the solution in the interval [0, \(2 \pi\)] is \(x = \frac{\pi}{2}\). For \(\sin x = \frac{3}{4}\), we must use the inverse sine or arcsin function in the calculator. This gives us \(x = \text{arcsin}(\frac{3}{4})\). However, sine is also positive in the second quadrant, so we also have the solution \(x = \pi - \text{arcsin}(\frac{3}{4})\) in the interval [0, \(2 \pi\)]
03
Calculate the exact values of the solutions
Now we simply need to calculate exact values for the solutions. We already know \(x = \frac{\pi}{2}\). Using a scientific calculator, we can find that \(\text{arcsin}(\frac{3}{4})\) is approximately \(0.848\). So, the solutions to the equation are \(x = \frac{\pi}{2}\), \(x = 0.848\) and \(x = \pi - 0.848 = 2.293\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool for solving equations of the form \( ax^2 + bx + c = 0 \). This kind of equation is known as a quadratic equation. By using the quadratic formula, you can find the values of \( x \) that satisfy the equation by following a consistent process. Here's a rundown of what it involves and how it's used in trigonometric equations.
This formula is critical for finding solutions such as \( \sin x \) when faced with quadratic trigonometric problems. It's also important to simplify throughout the process to make calculations easier. Remember, any number that can result from this process is potentially a solution, but it should be evaluated in the context of a trigonometric problem, as seen with \( \sin x = 1 \) and \( \sin x = \frac{3}{4} \) in the original problem.
- Identify the coefficients \( a \), \( b \), and \( c \) from your quadratic equation.
- Substitute these values into the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
- Carefully solve for \( x \) by calculating the square root and division.
This formula is critical for finding solutions such as \( \sin x \) when faced with quadratic trigonometric problems. It's also important to simplify throughout the process to make calculations easier. Remember, any number that can result from this process is potentially a solution, but it should be evaluated in the context of a trigonometric problem, as seen with \( \sin x = 1 \) and \( \sin x = \frac{3}{4} \) in the original problem.
Sine Function
The sine function is one of the fundamental trigonometric functions often used to describe the relationships in triangles, especially right-angled ones. For angles, it is defined as the ratio of the opposite side to the hypotenuse in a right triangle. However, in the context of equations, it helps in understanding periodic behaviors and oscillations.
In the exercise, the sine function is central to moving from \( \sin x = \{1, \frac{3}{4}\} \) to finding the angles that produce these values. Especially note \( \sin x = \frac{3}{4}\), where specific quadrant knowledge helps determine other angles in the given interval.
- The function is an input-output mechanism where an angle (in radians or degrees) is given as input and the ratio is the output.
- Sine values range between -1 and 1, which is why solutions to trigonometric equations are expected within this range.
- Sine has its maximum value at \( x = \frac{\pi}{2} \) where \( \sin x = 1 \).
- It is symmetric and can provide positive values in both the first and second quadrants.
In the exercise, the sine function is central to moving from \( \sin x = \{1, \frac{3}{4}\} \) to finding the angles that produce these values. Especially note \( \sin x = \frac{3}{4}\), where specific quadrant knowledge helps determine other angles in the given interval.
Inverse Trigonometric Functions
Inverse trigonometric functions are essential for finding angles when given a sine value, as seen with \( \sin x = \frac{3}{4} \). When you have the result of a sine function and need to determine the angle, you use the inverse sine function, denoted as \( \text{arcsin} \) or \( \sin^{-1} \). This concept allows us to reverse-engineer from the trigonometric values back to the angle.
In our example, calculating \( \text{arcsin} \left( \frac{3}{4} \right) \) gives an initial angle of approximately 0.848. Recognizing that sine is positive in the second quadrant as well, we add \( \pi - \text{arcsin} \left( \frac{3}{4} \right) \) to find another valid solution within our specified range. This demonstrates the usefulness of inverse trigonometric functions in solving complex equations efficiently.
- An inverse trigonometric function receives a value between -1 and 1 and produces an angle whose sine, cosine, or tangent is that value.
- \( \text{arcsin} \left(x\right) \) produces an angle in radians.
- The inverse function is useful for finding primary solutions; however, it can also be used to find secondary angles by considering the symmetry of the sine function.
In our example, calculating \( \text{arcsin} \left( \frac{3}{4} \right) \) gives an initial angle of approximately 0.848. Recognizing that sine is positive in the second quadrant as well, we add \( \pi - \text{arcsin} \left( \frac{3}{4} \right) \) to find another valid solution within our specified range. This demonstrates the usefulness of inverse trigonometric functions in solving complex equations efficiently.