Chapter 6: Problem 54
Find the exact solutions of the given equations, in radians, that lie in the interval \([0,2 \pi)\). $$\sec ^{2} x-\tan x=1$$
Short Answer
Expert verified
The solutions in the interval [0,2Ï€) for the equation are \(x = 0, \pi, \frac{\pi}{2}, \frac{3\pi}{2}\)
Step by step solution
01
Express the equation in terms of sine and cosine
Given \(\sec ^{2} x-\tan x=1\), express \(sec^2x\) and \(\tan x\) in terms of cosine and sine respectively, to get \(\frac{1}{cos^2x} - \frac{sinx}{cosx} = 1\).
02
Multiply out the denominators
To solve the equation, get rid of the fractions by multiplying every term by \(cos^2x\) which gives \(cos^2x(1 - sinx) = cos^2x\).
03
Expanding and rearranging
Rearrange the equation as \(cos^2x - sinx*cos^2x = cos^2x\). Then, bring all terms to one side to set the equation to zero. The result is \(cos^2x - sinx*cos^2x - cos^2x = 0\). This simplifies to \(-sinx*cos^2x = 0\).
04
Solve the equation
From \(-sinx*cos^2x = 0\), get the solutions, \(sinx = 0\) or \(cos^2x = 0\) which implies that \(cosx = 0\). Define each case separately. Solving for \(sinx = 0\), we get \(x = 0, \pi\); while solving for \(cosx = 0\), we get \(x = \frac{\pi}{2}, \frac{3\pi}{2}\).
05
Verify solutions
Verify all the solutions \(x = 0, \pi, \frac{\pi}{2}, \frac{3\pi}{2}\) in the original equation \(\sec ^{2} x-\tan x=1\) to confirm they are valid. Always verify solutions in the original equation especially when squaring was involved in the process.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Secant Function
The secant function, often denoted as \( \sec(x) \), is a trigonometric function that is defined as the reciprocal of the cosine function. Simply put, it can be described as:
- \( \sec(x) = \frac{1}{\cos(x)} \)
- The secant function has vertical asymptotes at every \( x \) where \( \cos(x) = 0 \), such as at \( \frac{\pi}{2} \), \( \frac{3\pi}{2} \), etc.
- \( \sec^2(x) = 1 + \tan^2(x) \)
Tangent Function
The tangent function, denoted \( \tan(x) \), represents the ratio of the sine to the cosine of an angle. In terms of the unit circle,
- \( \tan(x) = \frac{\sin(x)}{\cos(x)} \)
- Using the identity \( \sec^2(x) = 1 + \tan^2(x) \).
Unit Circle
The unit circle is a crucial concept in trigonometry designed to make understanding trigonometric functions simpler. It is a circle centered at the origin (0,0) with a radius of 1. On this circle:
- The x-coordinate of any point on the circle is \( \cos(\theta) \).
- The y-coordinate is \( \sin(\theta) \).
- \( \sin(\theta) \) is symmetric about the y-axis.
- \( \cos(\theta) \) is symmetric about the x-axis.
Solving Equations
Solving trigonometric equations involves finding all angle measures that satisfy given equations in defined intervals. The process generally encompasses:
- Utilizing trigonometric identities to simplify equations.
- Re-expressing functions like \( \sec(x) \) or \( \tan(x) \) in terms of \( \sin(x) \) and \( \cos(x) \).
- Exploring possible solutions by analyzing static and periodic behaviors of trigonometric functions.