Chapter 6: Problem 42
In Exercises \(39-42,\) verify the given cofunction identities. $$\csc \left(\frac{\pi}{2}-a\right)=\sec a$$
Short Answer
Expert verified
The given cofunction identity \(\csc \left(\frac{\pi}{2}-a\right)=\sec a\) is valid for all values of \(a\) due to the trigonometric identity \(\sin (\frac{\pi}{2}-a)=\cos a\).
Step by step solution
01
Understanding Cofunction Identity
A cofunction identity in trigonometry is an identity that expresses a trigonometric function of an angle in terms of a trigonometric function of its cofunction. In this identity, \(\csc \left(\frac{\pi}{2}-a\right)=\sec a\), it states the cosecant of the difference between \(\pi/2\) and \(a\) is equal to the secant of \(a\), where \(a\) is an angle in radians.
02
Expanding the Trigonometric Functions
\(\csc \left(\frac{\pi}{2}-a\right)\) and \(\sec a\) are not-basic trigonometric functions, rather they are reciprocal trigonometric functions defined as the reciprocals of the sine and cosine functions, respectively. Thus, the given identity can be rewritten as \(\frac{1}{\sin \left(\frac{\pi}{2}-a\right)}= \frac{1}{\cos a}\).
03
Simplify Using Fundamental Trigonometric Identity
Use the fundamental trigonometric identity \(\sin (\frac{\pi}{2}-a)=\cos a\). This identity states that the sine of the difference between \(\pi/2\) and \(a\) is equal to the cosine function of \(a\). Therefore, the given identity becomes: \(\frac{1}{\cos a}= \frac{1}{\cos a}\).
04
Confirming the Identity
The last transformation shows that the left-hand side is indeed equal to the right-hand side, thus confirming the validity of the initial cofunction identity \(\csc \left(\frac{\pi}{2}-a\right)=\sec a\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cofunction Identities
Cofunction identities in trigonometry are an intriguing set of identities that express a trigonometric function in terms of its complementary angle's cofunction. This is based on the complementary angle theorem, where the angles add up to 90 degrees, or \( \frac{\pi}{2} \) radians. A good way to remember this is: when one angle in a right triangle increases, its complementary angle decreases accordingly. It’s like having a see-saw balance between the angles.
- For example, if you have the angle \( a \), its complement is \( \frac{\pi}{2} - a \).
- Cofunction pairs include sine and cosine, tangent and cotangent, secant and cosecant.
Trigonometric Functions
Trigonometric functions are the building blocks of trigonometry. They relate the angles of a triangle to the lengths of its sides. Let's break down the ones most relevant to this exercise:
- Sine (\( \sin \)): Opposite over hypotenuse in a right triangle. Think of it as measuring the height at any angle.
- Cosine (\( \cos \)): Adjacent over hypotenuse in a right triangle. It measures the base length parallel to the angle of interest.
- Cosecant (\( \csc \)): This is the reciprocal of sine, so \( \csc a = \frac{1}{\sin a} \).
- Secant (\( \sec \)): The reciprocal of cosine, hence \( \sec a = \frac{1}{\cos a} \).
- Tangent (\( \tan \)): Opposite over adjacent, giving the slope of the angle.
- Cotangent (\( \cot \)): The reciprocal of tangent.
Trigonometric Identity Verification
Trigonometric identity verification is like proving a well-known truth in math, ensuring both sides of an equation depict the same truth. It’s all about transforming one side to look identical to the other. Here's a simple walkthrough for the given \( \csc \left(\frac{\pi}{2}-a\right)=\sec a \) identity verification:
1. **Understand the problem.** Recognize that \( \csc \) and \( \sec \) are not basic but reciprocal trigonometric functions of \( \sin \) and \( \cos \).2. **Use known identities.** Utilize the fundamental identity \( \sin (\frac{\pi}{2}-a)=\cos a \) which transforms the equation into a known form.3. **Simplify and Substitute.** Write \( \csc \left(\frac{\pi}{2}-a\right) \) as \( \frac{1}{\sin (\frac{\pi}{2}-a) \).\( \sec a \) becomes \( \frac{1}{\cos a} \).4. **Confirm it's true.** Both sides simplify to \( \frac{1}{\cos a} \), confirming the identity.
Verification not only builds trust in these identities but also sharpens problem-solving skills in the realm of mathematics, showing that the left and right sides reveal the same inherent truth.
1. **Understand the problem.** Recognize that \( \csc \) and \( \sec \) are not basic but reciprocal trigonometric functions of \( \sin \) and \( \cos \).2. **Use known identities.** Utilize the fundamental identity \( \sin (\frac{\pi}{2}-a)=\cos a \) which transforms the equation into a known form.3. **Simplify and Substitute.** Write \( \csc \left(\frac{\pi}{2}-a\right) \) as \( \frac{1}{\sin (\frac{\pi}{2}-a) \).\( \sec a \) becomes \( \frac{1}{\cos a} \).4. **Confirm it's true.** Both sides simplify to \( \frac{1}{\cos a} \), confirming the identity.
Verification not only builds trust in these identities but also sharpens problem-solving skills in the realm of mathematics, showing that the left and right sides reveal the same inherent truth.