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In Exercises \(15-20,\) write each expression in terms of \(\sin x\) and/or \(\cos x\) only. $$1-\tan x$$

Short Answer

Expert verified
The expression \(1-\tan x\) in terms of \(\sin x\) and/or \(\cos x\) only is \(\frac{\cos x - \sin x}{\cos x}\).

Step by step solution

01

Identify the given expression

The given expression is \(1- \tan x\). The task is to express this in terms of \(\sin x\) and/or \(\cos x\) only.
02

Apply the Trigonometric Identity

We apply the trigonometric identity \(\tan x = \frac{\sin x}{\cos x}\). Hence, the \(\tan x\) in the expression becomes \(\frac{\sin x}{\cos x}\). Thus, the original expression when substituted becomes \(1 - \frac{\sin x}{\cos x}\).
03

Simplify the Expression

To express the expression in \(\sin x\) and/or \(\cos x\) only, simplify it to \(\frac{\cos x - \sin x}{\cos x}\). Do this by combining the terms under one denominator, which is possible because both terms are fractions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simplifying Trigonometric Expressions
The art of simplifying trigonometric expressions is a fundamental skill in precalculus and beyond. It's similar to tidying up a room by clearing clutter and organizing items so that you can navigate the space efficiently.

Trigonometry, the mathematical study of triangles and the relationships between their sides and angles, often involves expressions that seem complex at first glance. Simplifying these expressions not only makes them easier to understand but also prepares them for further manipulation and integration into more complex equations.

To simplify, we often combine like terms, factor, or use common denominators. A crucial part of this process is applying trigonometric identities, such as \( \sin^2 x + \cos^2 x = 1 \) and \( 1 + \tan^2 x = \sec^2 x \), which serve as the 'tools of the trade’ to transform the expressions into a more manageable form. By mastering these identities and techniques, students can confidently tackle a wide range of problems.
Tan in Terms of Sin and Cos
Understanding the relationship between the basic trigonometric functions is often the key to unlocking the solution to many trigonometric problems. For instance, the tangent function, denoted as \( \tan x \), is one of the six fundamental trigonometric functions and it can be defined in terms of sine and cosine functions.

The identity \( \tan x = \frac{\sin x}{\cos x} \) explains that the tangent of an angle in a right-angled triangle is the ratio of the opposite side to the adjacent side, or in trigonometric jargon, the ratio of sine to cosine.

Applying the Identity

When given an expression involving \( \tan x \), such as \( 1 - \tan x \), substituting \( \tan x \) with \( \frac{\sin x}{\cos x} \) paves the way for simplification. Once substituted, simplification might require bringing terms over a common denominator or factoring. Grasping this concept can immensely simplify complex trigonometric expressions and facilitates solving a wide array of trigonometric problems.
Precalculus Trigonometry
Precalculus trigonometry lays the groundwork for calculus, extending beyond basic geometric relationships to include a variety of functions and identities that describe the properties of angles and their applications. In this stage of mathematical learning, the focus shifts from merely understanding how angles work to manipulating trigonometric functions to solve equations.

In precalculus, we explore more than just the primary trigonometric functions (sine, cosine, and tangent). We delve into the properties of their inverses, study trigonometric identities extensively and learn about the graphs of these functions. This rich area of mathematics is critical for anyone venturing into fields such as physics, engineering, and any discipline involving waves or oscillatory motion.

Being familiar with how to express one trigonometric function in terms of the others, as with expressing \( \tan x \) in terms of \( \sin x \) and \( \cos x \), and simplifying complex expressions are essential skills that are honed during this stage. This knowledge then becomes a stepping stone to the application of these functions in calculus, such as in the differentiation and integration of trigonometric functions.

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