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In Exercises \(53-64,\) simplify each expression. Assume that each variable expression is defined for appropriate values of \(x .\) Do not use a calculator. $$e^{\ln \left(5 x^{2}-1\right)}$$

Short Answer

Expert verified
The simplification of the expression \(e^{\ln \left(5 x^{2}-1\right)}\) is \(5x^{2} - 1\).

Step by step solution

01

Recall the properties of logarithm and exponential

The properties we will use here are the inverse properties of the natural logarithm, \(ln\), and the natural exponential, \(e\). Specifically, \(e^{ln(a)} = a\) and \(ln(e^a) = a\). These two functions are inverse of each other and cancel each other out.
02

Apply the Property

Applying this property to our given expression \(e^{\ln \left(5 x^{2}-1\right)}\), we can see that the \(e\) and \(ln\) are set up in a way where they'll cancel each other out, leading to the expression within the \(ln\), which is \(5 x^{2}-1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Properties of Logarithms
Properties of logarithms are mathematical rules that allow us to manipulate logarithmic expressions in various ways. Understanding these properties is key to simplifying logarithmic expressions and solving logarithmic equations. Central to these properties is the rule that the logarithm of a product is the sum of the logarithms of the factors (\[ \log(a \cdot b) = \log(a) + \log(b) \]). Similarly, the logarithm of a quotient is the difference of the logarithms (\[ \log\left(\frac{a}{b}\right) = \log(a) - \log(b) \]), and the logarithm of a power is the exponent times the logarithm of the base (\[ \log(a^b) = b \cdot \log(a) \]). More advanced properties involve changing the base of a logarithm and using logarithms to solve exponential equations. By mastering these properties, students can significantly simplify and solve problems that would otherwise be intractable.

In the exercise \(e^{\ln \left(5 x^{2}-1\right)}\), the property that is particularly useful is the inverse relationship between exponents and logarithms, which is explained further in the 'Inverse Functions' section.
Inverse Functions
Inverse functions are pairs of functions that 'undo' each other. When one function is applied and then its inverse is applied, the original value is retrieved. This concept is foundational when dealing with exponential and logarithmic forms, as they are inverse operations. For the natural base \(e\) and its corresponding natural logarithm \(\ln\), their inverseness is expressed by two critical identities: \(e^{\ln(a)} = a\) and \(\ln(e^a) = a\).

When dealing with the exercise \(e^{\ln \left(5 x^{2}-1\right)}\), recognizing that \(e\) and \(\ln\) are inverse functions simplifies the expression immediately to \(5x^2 - 1\), because the exponential function \(e^x\) and the natural logarithm \(\ln(x)\) effectively cancel each other out.
Exponential and Logarithmic Properties
Exponential and logarithmic properties are essential tools for working with expressions that include powers and logarithms. Exponential properties are based on the laws of exponents, which include rules for multiplying powers with the same base, dividing powers with the same base, and raising a power to a power. Logarithmic properties are closely related, given that logarithms are the inverse of exponentiation. These properties allow us to simplify complex expressions and solve equations involving exponents and logarithms.

When facing a composite expression like \(e^{\ln \left(5 x^{2}-1\right)}\), understanding the properties of both exponential and logarithmic functions is crucial. The solution utilizes the fact that logarithmic and exponential functions can reverse each other's effects, leading to a simpler expression. This simplification is one application of these powerful properties.
Natural Logarithm Simplification
Natural logarithm simplification involves applying the rules and properties of logarithms to the natural logarithm, \(\ln\), which has the mathematical constant \(e\) as its base. The simplification often revolves around recognizing patterns that align with logarithmic identities, such as \(\ln(e^x) = x\) and \(e^{\ln(x)} = x\), which indicate the natural logarithm and the base \(e\) exponential function as inverses.

In our textbook exercise \(e^{\ln \left(5 x^{2}-1\right)}\), we simplify the expression by invoking the inverse relationship between the exponential and logarithmic function. Since the output of the logarithm function is the exponent needed to get its input from the base \(e\), when we raise \(e\) to that power (\(\ln\) of something), we're simply going back to the original expression inside the \(\ln\), thus simplifying \(e^{\ln \left(5 x^{2}-1\right)}\) to \(5x^2 - 1\).

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Most popular questions from this chapter

The 1960 earthquake in Chile registered 9.5 on the Richter scale. Find the energy \(E\) (in Ergs) released by using the following model, which relates the energy in Ergs to the magnitude \(R\) of an earthquake. (Source: National Earthquake Information Center, U.S. Geological Survey) $$\log E=11.4+(1.5) R$$

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