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In Exercises \(21-30,\) write each logarithm as a sum and\or difference of logarithmic expressions. Eliminate exponents and radicals and evaluate logarithms wherever possible. Assume that \(a, x, y\) \(z>0\) and \(a \neq 1\). $$\log \sqrt[3]{\frac{x^{3} z^{5}}{10 y^{2}}}$$

Short Answer

Expert verified
The logarithmic expression \(\log \sqrt[3]{\frac{x^{3} z^{5}}{10 y^{2}}}\) simplifies to \(1\log(x) + 5/3\log(z) - 1/3\log(10) - 2/3\log(y)\).

Step by step solution

01

Change Logarithm of Radical into Exponent

Firstly, recognize the cube root in the expression as an exponent. The cube root of an expression is the same as that expression to the power of \(1/3\). Therefore, the given expression can be rewritten as: \(\log \left(\frac{x^{3} z^{5}}{10 y^{2}}\right)^{1/3}\)
02

Apply Logarithm Power Rule

Next, apply the power rule of logarithms. The power rule says that \(\log(b^{p}) = p\cdot\log(b)\). So, it allows to take the exponent and bring it out in front as a multiplier. Rewrite the expression as: \(1/3 \cdot \log \left(\frac{x^{3} z^{5}}{10 y^{2}}\right)\)
03

Apply Logarithm Quotient Rule

After that, apply the quotient rule of logarithms, which states that the logarithm of a quotient is equal to the difference of the logarithms. So, the logarithm of the quotient that is inside the log function right now can be split up into a difference of two logarithms. Rewrite the expression as: \(1/3 \cdot (\log(x^{3} z^{5}) - \log(10 y^{2}))\)
04

Apply Logarithm Product Rule

Then, apply the product rule of logarithms. This rule states that the logarithm of a product is equal to the sum of the logarithms. The logarithm of the product that is inside the first log function right now can be split up into a sum of two logarithms. Rewrite the expression as: \(1/3 \cdot (\log(x^{3}) + \log(z^{5}) - \log(10 y^{2}))\)
05

Apply Logarithm Power Rule Again

Now again, apply the power rule of logarithms to take the exponents out and move them in front as multipliers. Rewrite the expression as: \(1/3 \cdot ([3\log(x) + 5\log(z)] - [1\log(10) + 2\log(y)])\)
06

Simplify Logarithmic Expression

Finally, simplify the expression by multiplying through by \(1/3\), and apply the knowledge that \(\log{10} = 1\). The final expression becomes: \(1\log(x) + 5/3\log(z) - 1/3\log(10) - 2/3\log(y)\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithm Power Rule
The logarithm power rule is a fundamental concept in understanding how to simplify logarithmic expressions. Simply put, this rule allows us to move an exponent in a logarithmic argument to the front, making it a coefficient. If we have an expression \(\log(b^p)\), the logarithm power rule lets us rewrite it as \(p \cdot \log(b)\).

This rule comes in very handy when dealing with complex expressions that involve powers. It turns multiplicative processes inside a log into additive ones outside, which are often simpler to work with. As seen in our exercise, the cube root, which is the same as raising to the power of \(1/3\), got pulled out in front of the log, simplifying the expression immensely. Applying this rule the second time further simplified the expression by moving the exponents of \(x^3\) and \(z^5\) outside the log, resulting in \(3\log(x)\) and \(5\log(z)\), respectively.
Logarithm Quotient Rule
The logarithm quotient rule is invaluable when we encounter a quotient within a logarithmic function. According to this rule, \(\log(\frac{a}{b})\) is equal to \(\log(a) - \log(b)\). Thus, a division inside the log becomes a subtraction outside of it, breaking down a possibly convoluted expression into simpler, separate logarithmic terms.

In the solution to our exercise, this rule enabled us to separate the log of a fraction \(\frac{x^{3} z^{5}}{10 y^{2}}\) into a difference of logs. The subtraction makes it easier to handle each logarithmic term individually. The expression transformed into \(1/3 \cdot (\log(x^{3} z^{5}) - \log(10 y^{2}))\), streamlining the process of simplification.
Logarithm Product Rule
Much like the quotient rule, the logarithm product rule simplifies expressions involving the log of a product. It states that the log of a product, \(\log(ab)\), is equal to the sum of the logs: \(\log(a) + \log(b)\). This transformation is incredibly useful as it allows us to break down complex logs into more manageable parts.

When we applied this rule to our exercise, it helped us convert the log of the product \(x^3 z^5\) into the sum \(\log(x^3) + \log(z^5)\). This step is crucial in turning multiplicative relationships within the logarithm into additive ones outside, making the subsequent steps, which involve applying other logarithmic properties, far more straightforward.

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Most popular questions from this chapter

Pesticides decay at different rates depending on the pH level of the water contained in the pesticide solution. The pH scale measures the acidity of a solution. The lower the pH value, the more acidic the solution. When produced with water that has a pH of 6.0, the pesticide chemical known as malathion has a half-life of 8 days; that is, half the initial amount of malathion will remain after 8 days. However, if it is produced with water that has a pH of \(7.0,\) the half-life of malathion decreases to 3 days. (Source: Cooperative Extension Program, University of Missouri) (a) Assume the initial amount of malathion is 5 milligrams. Find an exponential function of the form \(A(t)=A_{0} e^{k t}\) that gives the amount of malathion that remains after \(t\) days if it is produced with water that has a pH of 6.0 (b) Assume the initial amount of malathion is 5 milligrams. Find an exponential function of the form \(B(t)=B_{0} e^{t t}\) that gives the amount of malathion that remains after \(t\) days if it is produced with water that has a pH of 7.0 (c) How long will it take for the amount of malathion in each of the solutions in parts (a) and (b) to decay to 3 milligrams? (d) If the malathion is to be stored for a few days before use, which of the two solutions would be more effective, and why? 4 (e) Graph the two exponential functions in the same viewing window and describe how the graphs illustrate the differing decay rates.

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The spread of a disease can be modcled by a logistic function. For example, in carly 2003 there was an outbreak of an illness called SARS (Severe Acute Respiratory Syndrome) in many parts of the world. The following table gives the total momber of cases in Canada for the wecks following March 20,2003 (Source: World Health Organization) (Note: The total number of cases dropped from 149 to 140 between weeks 3 and 4 because some of the cases thought to be SARS were reclassified as other discases.) $$\begin{array}{|c|c|}\hline\text { Weeks since } & \\\\\text { March } 20,2003 & \text { Total Cases } \\\0 & 9 \\\1 & 62 \\\2 & 132 \\\3 & 149 \\\4 & 140 \\\5 & 216 \\\6 & 245 \\\7 & 252 \\\8 & 250 \\\\\hline\end{array}$$ (a) Explain why a logistic function would suit this data well. (b) Make a scatter plot of the data and find the logistic function of the form \(f(x)=\frac{\epsilon}{1+a \varepsilon^{-1}}\) that best fits the data. (c) What docs \(c\) signify in your model? (d) The World Health Organization declared in July 2003 that SARS no longer posed a threat in Canada. By analyring this data, explain why that would be so.

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