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In Exercises \(21-30,\) write each logarithm as a sum and\or difference of logarithmic expressions. Eliminate exponents and radicals and evaluate logarithms wherever possible. Assume that \(a, x, y\) \(z>0\) and \(a \neq 1\). $$\log _{a} \sqrt{\frac{z^{5}}{x y^{4}}}$$

Short Answer

Expert verified
So the logarithmic expression simplifies to: \(\frac{5}{2}\log_{a}(z) - \frac{1}{2}\log_{a}(x) - 2\log_{a}(y)\)

Step by step solution

01

Apply the logarithm property of power

The property of power states that when a logarithm has a square root, it can be represented as a fraction of 1/2. So, apply this to the given logarithm and write it as \(\log_{a}(z^{5}/xy^{4})^{1/2}\)
02

Apply the logarithm rule of quotient

The rule of quotient states that when a logarithm has a fraction, it can be represented as the difference of the logarithms. Hence, this transforms to: \(\log_{a}(z^{5}/xy^{4})^{1/2} = \frac{1}{2}[\log_{a}(z^{5}) - \log_{a}(xy^{4})]\).
03

Apply the logarithm property of product

Apply the rule of product, which states that when a logarithm has a product, it can be represented as a sum of the logarithms. Hence, it changes to: \frac{1}{2}[\log_{a}(z^{5}) - (\log_{a}(x) + \log_{a}(y^{4}))].
04

Simplify the logarithm expression

Directly apply the rule of powers where the power comes out as a coefficient. Hence, we get: \frac{1}{2}[5*\log_{a}(z) - (\log_{a}(x) + 4*\log_{a}(y))].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Expressions
Logarithmic expressions are mathematical notations used to describe the power to which a base must be raised to get a certain value. A logarithm tells us what exponent we need to give a base number to obtain another number. For example, the logarithm of 1000 to the base 10 is 3, written as \( \text{log}_{10}(1000) = 3 \), because \( 10^3 = 1000 \).

When dealing with complex logarithmic expressions, particularly those involving quotients and radicals as in our original exercise, we can simplify the expression using various logarithmic properties. In our exercise, we had the expression \( \text{log}_{a} \sqrt{\frac{z^{5}}{x y^{4}}} \). This can initially seem daunting but breaking it into smaller parts makes it manageable. First, the square root can be handled by using the exponent \( \frac{1}{2} \), and then the properties of logarithms are applied to handle the quotient and product within the radicand.

By methodically applying these properties, step by step, we transition the complex expression into one that is much simpler and consists of a difference and a sum of individual logarithms. This step-by-step simplification aligns with a key educational goal: to help students easily understand and handle logarithmic expressions.
Exponentiation and Logarithms
Exponentiation and logarithms are two sides of the same coin in mathematics. They are inverse operations; while exponentiation involves raising a number by a certain power, logarithms deal with finding what that power is, given the base and the number itself. This is a crucial concept to understand as it provides a bridge between multiplication/division operations and their exponential/logarithmic counterparts.

To illuminate this connection, let's observe the general form: if \( b^x = y \), then \( \text{log}_{b}(y) = x \). Exponentiation can be seen as 'building up', and logarithms as 'breaking down' numbers. Our original exercise is a perfect demonstration of how exponents hidden within radicals (like the square root) can be unpacked using logarithms. The starting expression under the radical had an exponent, which we could expose through logarithms.

Understanding this relationship enhances problem-solving skills, as it opens up new ways to approach and simplify complex expressions involving powers, which is often the case in algebra and calculus.
Logarithm Rules
There are several key rules for logarithms that can simplify complex expressions into more digestible pieces — these are the product, quotient, and power rules. The product rule states that the logarithm of a product can be rewritten as the sum of the logarithms of the individual factors: \( \text{log}_b(mn) = \text{log}_b(m) + \text{log}_b(n) \).

On the other hand, the quotient rule tells us that the logarithm of a quotient can be expressed as the difference of the logarithms: \( \text{log}_b(\frac{m}{n}) = \text{log}_b(m) - \text{log}_b(n) \). Lastly, the power rule simplifies the logarithm of a power as the exponent times the logarithm of the base: \( \text{log}_b(m^p) = p \times \text{log}_b(m) \).

These rules were sequentially applied in the given exercise to streamline the original logarithmic expression. Simplification using these rules can often be the first step in solving calculus problems involving logarithms or even in finding derivatives and integrals of logarithmic functions. By mastering these logarithm rules, students can more easily dissect and tackle logarithmic equations.

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Most popular questions from this chapter

The following data gives the percentage of women who smoked during pregnancy for selected years from 1994 to \(2002 .\) (Sournce: National Center for Health Statistics) $$\begin{array}{|c|c|} \hline\text { Year } & \text { Percent Smoking } \\\\\text { Yuring Pregnancy } \\ \hline1994 & 14.6 \\\1996 & 13.6 \\\1998 & 12.9 \\\2000 & 12.2 \\\2001 & 12.0 \\\2002 & 11.4\\\\\hline\end{array}$$ (a) From examining the table, what is the general relationship between the year and the percentage of women smoking during pregnancy? (b) Let \(t\) be the number of years after \(1993 .\) Here, \(t\) starts at 1 because in 0 is undefined. Make a scatter plot of the data and find the natural logarithmic function of the form \(p(t)=a \ln t+b\) that best fits the data. Why must a be negative? (c) Project the percentage of women who will smoke during pregnancy in the year 2007.

If a function \(f\) has an inverse and the graph of \(f\) lies in Quadrant IV, in which quadrant does the graph of \(f^{-1}\) lie?

The decibel (dB) is a unit that is used to express the relative loudness of two sounds. One application of decibels is the relative value of the output power of an amplifier with respect to the input power. since power levels can vary greatly in magnitude, the relative value \(D\) of power level \(P_{1}\) with respect to power level \(P_{2}\) is given (in units of \(\mathrm{dB}\) ) in terms of the logarithm of their ratio as follows: $$D=10 \log \frac{P_{1}}{P_{2}}$$ where the values of \(P_{1}\) and \(P_{2}\) are expressed in the same units, such as watts \((\mathrm{W}) .\) If \(P_{2}=75 \mathrm{W},\) find the value of \(P_{1}\) at which \(D=0.7\)

The value of a 2006 S-type Jaguar is given by the function $$v(t)=43,173(0.8)^{t}$$ where \(t\) is the number of years since its purchase and \(v(t)\) is its value in dollars. (Source: Kelley Blue Book) (a) What was the Jaguar's initial purchase price? (b) What percentage of its value does the Jaguar S-type lose each year? (c) How many years will it take for the Jaguar S-type to reach a value of \(\$ 22,227 ?\)

Applications In this set of exercises, you will use inverse functions to study real-world problems. In economics, the demand function gives the price \(p\) as a function of the quantity \(q .\) One example of a demand function is \(p=100-0.1 q .\) However, mathematicians tend to think of the price as the input variable and the quantity as the output variable. How can you take this example of a demand function and express \(q\) as a function of p?

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