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In Exercises \(7-14,\) use \(\log 2 \approx 0.3010, \log 5 \approx 0.6990,\) and \(\log 7 \approx 0.8451\) to evaluate each logarithm without using a calculator. Then check your answer using a calculator. $$\log \sqrt{5}$$

Short Answer

Expert verified
The value of \(\log \sqrt{5}\) is approximately 0.3495

Step by step solution

01

Apply Logarithm Properties

First, rewrite the logarithm \(\log \sqrt{5}\) into a simpler form using the properties of logarithms. Since the square root of a number is just the number to the power of 1/2, \(\log \sqrt{5}\) can be written as \(1/2 \times \log 5\). Simplifying the expression gives us \(0.5 \times \log 5\).
02

Evaluate the Simplified Logarithm

From the given \(\log 5 \approx 0.6990\), multiply this value with 0.5, which results in approximately 0.3495.
03

Check Answer Using a Calculator

To confirm the correctness of the answer, one can check it by using a calculator to compute the logarithm of the square root of 5, which should give a result very close to 0.3495.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithm Properties
Understanding the properties of logarithms is crucial in simplifying complex logarithmic expressions. A logarithm, at its core, tells us which power we need to raise a base to get a certain number. A key property is the product rule, which states that \(\log_b(x \times y) = \log_b(x) + \log_b(y)\) for a base \(b\). Additionally, the quotient rule indicates that \(\log_b\left(\frac{x}{y}\right) = \log_b(x) - \log_b(y)\).

Another important property is the power rule, which is particularly useful in the exercise provided. It allows us to take an exponent inside a logarithm and move it to the front as a multiplier: \(\log_b(x^p) = p \times \log_b(x)\). This rule is used to transform \(\log \sqrt{5}\) into a more manageable form, \(\log 5^{1/2}\), and then further into \(\frac{1}{2} \log 5\), which can be easily evaluated using the given logarithmic values.

Mastering these properties enables us to evaluate logarithms that would otherwise require extensive calculation or a calculator, making it easier to solve problems in various mathematical fields and applications.
Evaluating Logarithms Without a Calculator
When faced with the challenge of evaluating logarithms without the help of a calculator, we rely on our understanding of logarithm properties and known values. As seen in the provided exercise, the known logarithmic values such as \(\log 2\), \(\log 5\), and \(\log 7\) are pivotal. These constants can be combined with properties of logarithms to find the values of more complex expressions.

For instance, to evaluate \(\log \sqrt{5}\), you first express the square root as a power of 1/2, then use the power rule to bring the exponent out in front. By knowing the value of \(\log 5\), you can then perform simple multiplication to get your result. In a scenario where you do not have the exact logarithm values, you can estimate logarithms using nearby values you know and logarithm properties to interpolate or by transforming the argument into a product of known factors. Developing these critical thinking and problem-solving skills empowers students to handle logarithmic calculations even when electronic aids are not available.
Square Root as Exponent
The square root of a number can be represented as an exponent, which is a fundamental concept in algebra and higher-level math. Namely, the square root of any number \(x\) is the same as raising that number to the power of 1/2, written as \(x^{1/2}\). This notation is rooted in the definition of rational exponents, where the denominator of the fraction exponent indicates the root and the numerator indicates the power.

In the context of the exercise, \(\sqrt{5}\) is equivalent to \(5^{1/2}\). When inserted into a logarithmic function, this exponent becomes highly significant, as we can apply the power rule of logarithms to simplify the expression. Not only does this representation make it easier to manipulate algebraic expressions, but it also connects to the geometric concept of a square root, which deepens a student's overall understanding of how various mathematical concepts are interrelated.

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Most popular questions from this chapter

The spread of a disease can be modcled by a logistic function. For example, in carly 2003 there was an outbreak of an illness called SARS (Severe Acute Respiratory Syndrome) in many parts of the world. The following table gives the total momber of cases in Canada for the wecks following March 20,2003 (Source: World Health Organization) (Note: The total number of cases dropped from 149 to 140 between weeks 3 and 4 because some of the cases thought to be SARS were reclassified as other discases.) $$\begin{array}{|c|c|}\hline\text { Weeks since } & \\\\\text { March } 20,2003 & \text { Total Cases } \\\0 & 9 \\\1 & 62 \\\2 & 132 \\\3 & 149 \\\4 & 140 \\\5 & 216 \\\6 & 245 \\\7 & 252 \\\8 & 250 \\\\\hline\end{array}$$ (a) Explain why a logistic function would suit this data well. (b) Make a scatter plot of the data and find the logistic function of the form \(f(x)=\frac{\epsilon}{1+a \varepsilon^{-1}}\) that best fits the data. (c) What docs \(c\) signify in your model? (d) The World Health Organization declared in July 2003 that SARS no longer posed a threat in Canada. By analyring this data, explain why that would be so.

The following table gives the temperature, in degrees Celsius, of a cup of hot water sitting in a room with constant temperature. The data was collected over a period of 30 minutes. (Source: www.phys. unt.edu, Dr. James A. Roberts)$$\begin{array}{|c|c|} \hline\text { Time } & \text { Temperature } \\\\(\mathrm{min}) & (\text { degrees Celsius }) \\ \hline0 & 95 \\\1 & 90.4 \\\5 & 84.6 \\\10 & 73 \\\15 & 64.7 \\\20 & 59 \\\25 & 54.5 \\\29 & 51.4\\\\\hline\end{array}$$ (a) Make a scatter plot of the data and find the exponential function of the form \(f(t)=C a^{2}\) that best fits the data. Let \(t\) be the number of minutes the water has been cooling. (b) Using your modicl, what is the projected temperature of the water after 1 hour?

Find the interest rate \(r\) if the interest on the initial deposit is compounded continuously and no withdrawals or further deposits are made. Initial amount: \(\$ 3000 ;\) Amount in 3 years: \(\$ 3600\)

Find the inverse of the given function. Then graph the given function and its inverse on the same set of axes. $$g(x)=(x+2)^{2}, x \geq-2$$

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