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Applications In this set of exercises, you will use properties of functions to study real-world problems. Demand Function The demand for a product, in thousands of units, is given by \(d(x)=\frac{100}{x},\) where \(x\) is the price of the product, \((x>0) .\) Is this an increasing or a decreasing function? Explain.

Short Answer

Expert verified
The function \(d(x)=\frac{100}{x}\) is a decreasing function as its derivative is negative (\(d'(x) = -\frac{100}{x^2}\)) for any \(x > 0\).

Step by step solution

01

Understanding the Function

The function given is \(d(x)=\frac{100}{x}\), representing demand as a function of price. Furthermore, it is given that the price, \(x\), is always positive (\(x > 0\)). The task is to determine whether the function increases or decreases as \(x\) increases.
02

Deriving the Function

The derivative of the function needs to be calculated to determine if it's increasing or decreasing. The derivative of the function \(d(x)=\frac{100}{x}\) can be computed as \(d'(x) = -\frac{100}{x^2}\)
03

Analyze the Derivative

As given, the value of \(x\) is always positive. So the denominator \(x^2\) of the derivative is always positive. The term -100 makes the entire derivative negative for any value of \(x > 0\). A negative derivative indicates that a function is decreasing.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative Analysis
When we talk about derivative analysis, we are referring to the process of studying how a function behaves, especially in terms of whether it increases or decreases. Derivatives are a fundamental tool in calculus, and they allow us to understand the rate at which a function changes. In the case of the demand function given by \(d(x)=\frac{100}{x}\), finding the derivative helps us identify the nature of the demand as price changes. The derivative of this function, \(d'(x) = -\frac{100}{x^2}\), is crucial here. Calculating the derivative involves applying differentiation techniques to understand how \(d(x)\) responds to small changes in \(x\). The derivative informs us about the slope of the tangent to the graph of \(d(x)\). When \(d'(x)\) is negative, it suggests that the slope is downward, indicating that \(d(x)\) decreases as \(x\) increases.
Decreasing Functions
A function is said to be decreasing on an interval if, as the input (x) increases, the output (the value of the function) decreases. In simpler terms, think of walking down a hill—the further you go, the lower you get. Mathematically, a function \(f(x)\) is decreasing if its derivative \(f'(x)\) is negative over the interval under consideration. For the demand function \(d(x) = \frac{100}{x}\), as the price \(x\) rises, the demand decreases. This relationship can be affirmed by the negative derivative \(d'(x) = -\frac{100}{x^2}\). This shows that with every increase in \(x\), the value of \(d(x)\) gets smaller, pointing towards a decreasing function. Understanding decreasing functions is helpful in many economic contexts, such as predicting what happens to sales when prices go up.
Real-World Applications
The concept of a demand function isn't just theoretical—it has real-world implications, especially in economics and business. Demand functions like \(d(x) = \frac{100}{x}\) are employed by companies to ascertain how consumer purchasing behavior changes with pricing.For instance, businesses use these functions to set pricing strategies that maximize revenue or profit. If a firm's goal is revenue maximization, understanding whether the demand is increasing or decreasing with pricing adjustments helps in determining the optimal price point. Additionally, these functions can guide marketing decisions by revealing potential changes in demand due to external factors, such as economic shifts or competitor actions.By utilizing concepts from derivative analysis and characteristics of decreasing functions, companies can make informed decisions to better align with consumer expectations and market conditions.

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Most popular questions from this chapter

Is it true that \((f g)(x)\) is the same as \((f \circ g)(x)\) for any functions \(f\) and \(g ?\) Explain.

A rectangular garden plot is to be enclosed with a fence on three of its sides and an existing wall on the fourth side. There is 45 feet of fencing material available. (a) Write an equation relating the amount of available fencing material to the lengths of the three sides that are to be fenced. (b) Use the equation in part (a) to write an expression for the width of the enclosed region in terms of its length. (c) For each value of the length given in the following table of possible dimensions for the garden plot, fill in the value of the corresponding width. Use your expression from part (b) and compute the resulting area. What do you observe about the area of the enclosed region as the dimensions of the garden plot are varied? $$\begin{array}{ccc}\hline \begin{array}{c}\text { Length } \\\\\text { (feet) }\end{array} & \begin{array}{c}\text { Width } \\\\\text { (feet) }\end{array} & \begin{array}{c}\text { Total Amount of } \\\\\text { Fencing Material (feet) }\end{array} & \begin{array}{c}\text { Area } \\\\\text { (square feet) }\end{array} \\\\\hline 5 & & 45 \\\10 & & 45 \\\15 & & 45 \\\20 & & 45 \\\30 & & 45 \\\k & & 45 \\\& &\end{array}$$ (d) Write an expression for the area of the garden plot in terms of its length. (e) Find the dimensions that will yield a garden plot with an area of 145 square feet.

For function of the form \(f(x)=\) \(a x^{2}+b x+c,\) find the discriminant, \(b^{2}-4 a c,\) and use it to determine the number of \(x\)-intercepts of the graph of \(f .\) Also determine the number of real solutions of the equation \(f(x)=0.\) $$f(x)=-x^{2}+4 x-4$$

When designing buildings, engineers must pay careful attention to how different factors affect the load a structure can bear. The following table gives the load in terms of the weight of concrete that can be borne when threaded rod anchors of various diameters are used to form joints. $$\begin{array}{cc} \text { Diameter (in.) } & \text { Load (1b) } \\ \hline 0.3750 & 2105 \\ 0.5000 & 3750 \\ 0.6250 & 5875 \\ 0.7500 & 8460 \\ 0.8750 & 11,500 \end{array}$$ (a) Examine the table and explain why the relationship between the diameter and the load is not linear. (b) The function $$f(x)=14,926 x^{2}+148 x-51$$ gives the load (in pounds of concrete) that can be borne when rod anchors of diameter \(x\) (in inches) are employed. Use this function to determine the load for an anchor with a diameter of 0.8 inch. (c) since the rods are drilled into the concrete, the manufacturer's specifications sheet gives the load in terms of the diameter of the drill bit. This diameter is always 0.125 inch larger than the diameter of the anchor. Write the function in part (b) in terms of the diameter of the drill bit. The loads for the drill bits will be the same as the loads for the corresponding anchors. (Hint: Examine the table of values and see if you can present the table in terms of the diameter of the drill bit.)

In Exercises \(105-110\), find the difference quotient \(\frac{f(x+h)-f(x)}{h}\) \(h \neq 0,\) for the given function \(f\). $$f(x)=3 x-1$$

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