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Use a graphing utility to find all real solutions. You may need to adjust the window size manually or use the ZOOMFIT feature to get a clear graph. $$\text { Solve } \sqrt{0.3 x+0.95}-\sqrt{0.75 x-0.5}=-0.3$$

Short Answer

Expert verified
The real solutions to the equation are the x-values of the intersection points of the two plotted functions. For an exact numerical value, check the coordinates of the intersection points.

Step by step solution

01

Define the functions

Define two functions, \(f(x) = \sqrt{0.3 x+0.95}\) and \(g(x) = \sqrt{0.75 x-0.5}+0.3\), using your graphing utility.
02

Graph the functions

Plot both functions on the same graph. Select a window size that is appropriate for the functions, and adjust if necessary using the ZOOM or ZOOMFIT feature until you can see both curves clearly.
03

Find the intersections

Identify the points at which the two functions intersect. These represent the x-values where \(f(x) = g(x)\), and thus, solutions to the original equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Calculator Techniques
Graphing calculators are powerful tools that can help students visualize complex functions and their solutions. To effectively use a graphing calculator, it is crucial to become familiar with its functions and settings. When solving square root equations, a graphical approach involves plotting the equation on the calculator.

Start by entering two separate functions that represent each side of the equation. In this example, we have defined the functions \(f(x) = \sqrt{0.3 x+0.95}\) and \(g(x) = \sqrt{0.75 x-0.5}+0.3\). After inputting the functions, select an appropriate window size to ensure all relevant parts of the graph can be seen. If the graph isn't clear or seems off, use the 'Zoom' features — particularly ZOOMFIT — which scales the graph to fit important points like intercepts and peaks within the display view.

Adjusting View for Clarity

Ensure that your graphing window includes both positive and negative values if needed, and be sure to look out for any asymptotes or discontinuities. By using TRACE or a similar feature, you can scroll along the graph to see coordinates for specific points.

Remember, practising with these features and experimenting with window sizes will enhance your ability to quickly and accurately depict functions on a graphing calculator, thus facilitating easier identification of intersections and solutions.
Solving Square Root Equations
Square root equations involve variables under square root signs, presenting a unique challenge in finding their solutions. To solve these equations on a graphing utility, rewrite each side of the equation as a separate function. For instance, our exercise transforms into a function for \(f(x)\) and a function for \(g(x)\) as mentioned before.

To find the real solutions by graphing, you search for the values of \(x\) where the two functions intersect, indicating that \(f(x) = g(x)\). However, when dealing with square roots, ensure that the radicand (the number under the square root) is non-negative, as square roots of negative numbers are not real.

Checking Solutions

After graphing, you must also validate the solutions. Square root functions can sometimes result in extraneous solutions when squared to eliminate the roots. Always plug the solutions back into the original equation to confirm they work. By doing this, you ensure accuracy and deepen your understanding of how square root functions behave algebraically and graphically.
Function Intersection Points
Intersection points on a graph represent the solutions to an equation where two functions meet. These solutions can either be \(x\)-values, \(y\)-values, or coordinates of points depending on the context. When equating two functions \(f(x)\) and \(g(x)\), the intersection points' \(x\)-coordinates are your solutions.

Using a graphing calculator, you can find these intersection points through a 'Calculate' menu or a similar function, often labeled as 'intersect.' This tool requires you to select both functions and then guess the point of intersection by moving the cursor close to where the graphs intersect.

Interpreting the Intersections

It is essential to carefully analyze the graph and consider each intersection point — if there are multiple solutions, each one must be evaluated. Especially when studying square root equations, some visible intersections might not be valid solutions because they might not satisfy the original equation when substituting back. Be sure to validate each potential solution by checking it against the original equation to avoid including extraneous solutions. Understanding this concept will significantly boost your problem-solving skills in algebra and calculus.

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Most popular questions from this chapter

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This set of exercises will draw on the ideas presented in this section and your general math background. Why must we have \(a \neq 0\) in the definition of a quadratic function?

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A rectangular garden plot is to be enclosed with a fence on three of its sides and an existing wall on the fourth side. There is 45 feet of fencing material available. (a) Write an equation relating the amount of available fencing material to the lengths of the three sides that are to be fenced. (b) Use the equation in part (a) to write an expression for the width of the enclosed region in terms of its length. (c) For each value of the length given in the following table of possible dimensions for the garden plot, fill in the value of the corresponding width. Use your expression from part (b) and compute the resulting area. What do you observe about the area of the enclosed region as the dimensions of the garden plot are varied? $$\begin{array}{ccc}\hline \begin{array}{c}\text { Length } \\\\\text { (feet) }\end{array} & \begin{array}{c}\text { Width } \\\\\text { (feet) }\end{array} & \begin{array}{c}\text { Total Amount of } \\\\\text { Fencing Material (feet) }\end{array} & \begin{array}{c}\text { Area } \\\\\text { (square feet) }\end{array} \\\\\hline 5 & & 45 \\\10 & & 45 \\\15 & & 45 \\\20 & & 45 \\\30 & & 45 \\\k & & 45 \\\& &\end{array}$$ (d) Write an expression for the area of the garden plot in terms of its length. (e) Find the dimensions that will yield a garden plot with an area of 145 square feet.

The perimeter of a square is \(P(s)=4 s\) where \(s\) is the length of a side in inches. The function \(C(x)=2.54 x\) takes \(x\) inches as input and outputs the equivalent result in centimeters. Find \((C \circ P)(s)\) and explain what it represents.

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