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Solve the inequality algebraically or graphically. $$x^{2}+1<0$$

Short Answer

Expert verified
The inequality \(x^{2}+1<0\) has no solution.

Step by step solution

01

Factoring the Inequality

This inequality is already in its simplest form and cannot be factored. Nonetheless, we can observe that for all \(x\), \(x^{2}+1\geq 1\), with equality when \(x=0\). This is a parabola that opens upwards with vertex at (0, 1).
02

Finding the Roots

Now, find the roots of \(x^{2}+1=0\). However, this results in \(x^{2}=-1\), which has no real solutions because a square of a real number is always non-negative. The roots of this inequality are imaginary.
03

Determining the Sign of the Expression

Since there are no real roots, it is not necessary to check the signs of the intervals.
04

Confirming the Solution

As we have never found any real numbers \(x\) that fulfill the inequality, we can conclude that this inequality has no solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Algebraic Methods
When solving inequalities using algebraic methods, the process often involves isolating the variable on one side of the inequality sign. This can include operations like adding or subtracting terms on both sides, multiplying or dividing by positive or negative numbers (remembering that multiplying or dividing by a negative number reverses the inequality sign), and factoring.
In the given exercise, the inequality \(x^2+1 < 0\) is peculiar because it immediately presents a challenge: the square of any real number is non-negative, thus making \(x^2\) alone always greater than or zero. After adding 1 to both sides, it becomes evident that the left side of the inequality is always greater than 1. Therefore, no real number for \(x\) can satisfy this inequality, leading to the solution that there are no real solutions.
This simple example demonstrates that algebraic methods are not only about manipulating equations but also about understanding the inherent properties of the numbers involved, such as the fact that the square of a real number cannot be negative.
Graphical Methods
Graphical methods for solving inequalities involve sketching the functions or expressions on a coordinate system to visually understand the region where the inequality holds true. For example, plotting \(y = x^2 + 1\) on a graph yields a parabola that opens upwards and has its vertex at (0,1).

Analyzing the Parabola

When dealing with inequalities, the areas above or below the curve represent the range of values where the inequality is satisfied. In this case, since we're looking for where the parabola is less than zero, we would be interested in the region below the x-axis. However, the parabola never dips below the x-axis, which corresponds to the fact that \(x^2 + 1\) is always positive for real numbers.

Conclusion from Graph

The graphical representation clearly shows that there is no intersection with the x-axis (where the expression would equal zero), confirming that the inequality has no solution in the real number system. This visual approach is often invaluable in understanding the implications of the algebraic methods used to solve an inequality.
Complex Numbers
Complex numbers extend the idea of the traditional number line to a two-dimensional complex plane, using the imaginary unit \(i\), where \(i^2 = -1\). This is especially useful in situations where algebraic manipulations result in the square root of negative numbers, which do not have solutions in the set of real numbers.

Real vs. Complex Solutions

In our problem, looking for the roots of \(x^2+1=0\), we find that \(x^2=-1\), which has no solution within the real numbers. However, if we extend our search to the complex numbers, we find that \(x = \pm i\) are the roots, where \(i\) is the imaginary unit.
This is an important concept to understand: while inequalities involving real numbers may have no solution, the same inequalities can have solutions in the complex plane. However, when solving inequalities, we typically seek real number solutions, as the concept of being 'greater than' or 'less than' is not as intuitively defined in the realm of complex numbers as it is in the real numbers.

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Most popular questions from this chapter

When using transformations with both vertical scaling and vertical shifts, the order in which you perform the transformations matters. Let \(f(x)=|x|\). (a) Find the function \(g(x)\) whose graph is obtained by first vertically stretching \(f(x)\) by a factor of 2 and then shifting the result upward by 3 units. A table of values and/or a sketch of the graph will be helpful. (b) Find the function \(g(x)\) whose graph is obtained by first shifting \(f(x)\) upward by 3 units and then multiplying the result by a factor of 2 A table of values and/or a sketch of the graph will be helpful. (c) Compare your answers to parts (a) and (b). Explain why they are different.

Suppose the vertex of the parabola associated with a certain quadratic function is \((2,1),\) and another point on this parabola is (3,-1) (a) Find the equation of the axis of symmetry of the parabola. (b) Use symmetry to find a third point on the parabola. (c) Sketch the parabola.

A rectangular sandbox is to be enclosed with a fence on three of its sides and a brick wall on the fourth side. If 24 feet of fencing material is available, what dimensions will yield an enclosed region with an area of 70 square feet?

A chartered bus company has the following price structure. A single bus ticket costs \(\$ 30 .\) For each additional ticket sold to a group of travelers, the price per ticket is reduced by \(\$ 0.50 .\) The reduced price applies to all the tickets sold to the group. (a) Calculate the total cost for one, two, and five tickets. (b) Using your calculations in part (a) as a guide, find a quadratic function that gives the total cost of the tickets. (c) How many tickets must be sold to maximize the revenue for the bus company?

When designing buildings, engineers must pay careful attention to how different factors affect the load a structure can bear. The following table gives the load in terms of the weight of concrete that can be borne when threaded rod anchors of various diameters are used to form joints. $$\begin{array}{cc} \text { Diameter (in.) } & \text { Load (1b) } \\ \hline 0.3750 & 2105 \\ 0.5000 & 3750 \\ 0.6250 & 5875 \\ 0.7500 & 8460 \\ 0.8750 & 11,500 \end{array}$$ (a) Examine the table and explain why the relationship between the diameter and the load is not linear. (b) The function $$f(x)=14,926 x^{2}+148 x-51$$ gives the load (in pounds of concrete) that can be borne when rod anchors of diameter \(x\) (in inches) are employed. Use this function to determine the load for an anchor with a diameter of 0.8 inch. (c) since the rods are drilled into the concrete, the manufacturer's specifications sheet gives the load in terms of the diameter of the drill bit. This diameter is always 0.125 inch larger than the diameter of the anchor. Write the function in part (b) in terms of the diameter of the drill bit. The loads for the drill bits will be the same as the loads for the corresponding anchors. (Hint: Examine the table of values and see if you can present the table in terms of the diameter of the drill bit.)

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