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In Exercises \(7-16,\) for the given functions \(f\) and \(g,\) find each composite function and identify its domain. (a) \((f+g)(x)\) (b) \((f-g)(x)\) (c) \((f g)(x)\) (d) \(\left(\frac{f}{g}\right)(x)\) $$f(x)=\frac{1}{x} ; g(x)=\frac{1}{2 x-1}$$

Short Answer

Expert verified
The functions are as follows: a) \((f+g)(x) = \frac{3x-1}{2x^2-x}\) with \(x \neq 0\) and \(x \neq 0.5\), b) \((f-g)(x) = \frac{x-1}{2x^2-x}\) with \(x \neq 0\) and \(x \neq 0.5\), c) \((fg)(x) = \frac{1}{2x^2 - x}\) with \(x \neq 0\) and \(x \neq 0.5\), d) \(\left(\frac{f}{g}\right)(x) = \frac{2x-1}{x}\) with \(x \neq 0\).

Step by step solution

01

Find the function \((f+g)(x)\)

For \(f(x)+g(x)\), simply add the two functions together: \[f(x) + g(x) = \frac{1}{x} + \frac{1}{2x-1}\]. To combine these into a single fraction, find a common denominator: \[\frac{1}{x} + \frac{1}{2x-1} = \frac{1(2x-1)+x(1)}{x(2x-1)} = \frac{2x-1+x}{2x^2-x}\] which simplifies to \[\frac{3x-1}{2x^2-x}\]. The domain is all \(x\) such that the denominator does not equal zero. In other words, \(x \neq 0\) and \(x \neq 0.5\).
02

Find the function \((f-g)(x)\)

For \(f(x)-g(x)\), subtract the second function from the first: \[f(x) - g(x) = \frac{1}{x} - \frac{1}{2x-1} = \frac{2x-1-x}{x(2x-1)} = \frac{x-1}{2x^2-x}\]. The domain is all \(x\) such that the denominator does not equal zero. In other words, \(x \neq 0\) and \(x \neq 0.5\).
03

Find the function \((fg)(x)\)

For \((fg)(x)\), multiply the two functions: \[f(x) \cdot g(x) = \left(\frac{1}{x}\right) \cdot \left(\frac{1}{2x-1}\right) = \frac{1}{2x^2 - x}\]. The domain is the set of \(x\) such that the denominator does not equal zero, \(x \neq 0\) and \(x \neq 0.5\).
04

Find the function \(\left(\frac{f}{g}\right)(x)\)

For \(\frac{f}{g}(x)\), divide the first function by the second: \[\frac{f(x)}{g(x)} = \frac{1/x}{1/(2x-1)} = \frac{2x-1}{x}\]. The domain is the set of \(x\) such that \(x \neq 0\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Operations
When we talk about function operations, we refer to the processes of adding, subtracting, multiplying, or dividing two functions. These operations produce a new function, known as the result function.
To perform these operations, you often begin with two distinct functions, say \(f(x)\) and \(g(x)\). Here are the basic procedures for each operation:
  • Addition \((f+g)(x)\): Simply add the function values: \(f(x) + g(x)\).
  • Subtraction \((f-g)(x)\): Subtract the second function values from the first: \(f(x) - g(x)\).
  • Multiplication \((fg)(x)\): Multiply the functions: \(f(x) \cdot g(x)\).
  • Division \(\left(\frac{f}{g}\right)(x)\): Divide the first function by the second: \(\frac{f(x)}{g(x)}\). Note that \(g(x)\) must not be zero for this operation to be valid.
It is essential to work step by step through these operations, simplifying the resulting expressions whenever possible. This often involves finding a common denominator when dealing with rational functions.
Domain of a Function
The domain of a function refers to all the possible input values \(x\) for which the function is defined. It is important to determine this set of values, especially when dealing with composite functions.
Finding the domain requires you to consider the following:
  • If the function is given as a fraction, ensure the denominator is not zero.
  • Consider any square roots in the expression, as they imply non-negative values under the root for real numbers.
  • Check if a logarithm is involved, as it requires positive arguments.
In the context of adding, subtracting, multiplying, or dividing functions like in our example, you determine the domain by combining the domain restrictions of both functions involved.
The resulting domain is the intersection of the domains of \(f\) and \(g\). Sometimes, additional restrictions arise from operations themselves, like division, where the divisor cannot be zero.
Rational Functions
Rational functions are specific types of functions where the function is expressed as the ratio of two polynomials, \(\frac{P(x)}{Q(x)}\). Understanding rational functions involves both recognizing their form and handling their unique characteristics.
Some key features of rational functions include:
  • Poles: These are points where the function becomes undefined due to a zero in the denominator. They are significant when determining the domain.
  • Asymptotes: These lines a function approaches but never actually reaches. They often occur near the poles, showcasing the function's behavior at extreme values.
  • Intercepts: The points where the function crosses the axes, crucial for graphing these functions.
In our exercise, the functions \(f(x) = \frac{1}{x}\) and \(g(x) = \frac{1}{2x-1}\) are both rational. When performing operations like addition or subtraction, it’s common to encounter complex fractions.
Simplifying these involves finding a common denominator, allowing you to combine them effectively into one comprehensive expression. Always be mindful of the domain restrictions that emerge from these simplifications.

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Most popular questions from this chapter

The area of a square is given by \(A(s)=s^{2}\) where \(s\) is the length of a side in inches. Compute the expression for \(A(2 s)\) and explain what it represents.

A rectangular garden plot is to be enclosed with a fence on three of its sides and an existing wall on the fourth side. There is 45 feet of fencing material available. (a) Write an equation relating the amount of available fencing material to the lengths of the three sides that are to be fenced. (b) Use the equation in part (a) to write an expression for the width of the enclosed region in terms of its length. (c) For each value of the length given in the following table of possible dimensions for the garden plot, fill in the value of the corresponding width. Use your expression from part (b) and compute the resulting area. What do you observe about the area of the enclosed region as the dimensions of the garden plot are varied? $$\begin{array}{ccc}\hline \begin{array}{c}\text { Length } \\\\\text { (feet) }\end{array} & \begin{array}{c}\text { Width } \\\\\text { (feet) }\end{array} & \begin{array}{c}\text { Total Amount of } \\\\\text { Fencing Material (feet) }\end{array} & \begin{array}{c}\text { Area } \\\\\text { (square feet) }\end{array} \\\\\hline 5 & & 45 \\\10 & & 45 \\\15 & & 45 \\\20 & & 45 \\\30 & & 45 \\\k & & 45 \\\& &\end{array}$$ (d) Write an expression for the area of the garden plot in terms of its length. (e) Find the dimensions that will yield a garden plot with an area of 145 square feet.

A carpenter wishes to make a rain gutter with a rectangular cross-section by bending up a flat piece of metal that is 18 feet long and 20 inches wide. The top of the gutter is open. $$2$$ (a) Write an expression for the cross-sectional area in terms of \(x,\) the length of metal that is bent upward. (b) How much metal has to be bent upward to maximize the cross-sectional area? What is the maximum cross-sectional area?

This set of exercises will draw on the ideas presented in this section and your general math background. Without doing any calculations, explain why $$\sqrt{x+1}=-2$$ does not have a solution.

A parabola associated with a certain quadratic function \(f\) has the point (2,8) as its vertex and passes through the point \((4,0) .\) Find an expression for \(f(x)\) in the form \(f(x)=a(x-h)^{2}+k\) (a) From the given information, find the values of \(h\) and \(k\) (b) Substitute the values you found for \(h\) and \(k\) into the expression \(f(x)=a(x-h)^{2}+k\) (c) Now find \(a\). To do this, use the fact that the parabola passes through the point \((4,0) .\) That is, \(f(4)=0\) You should get an equation having just \(a\) as a variable. Solve for \(a\) (d) Substitute the value you found for \(a\) into the expression you found in part (b). (e) Graph the function using a graphing utility and check your answer. Is (2,8) the vertex of the parabola? Does the parabola pass through (4,0)\(?\)

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