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In Exercises \(105-110\), find the difference quotient \(\frac{f(x+h)-f(x)}{h}\) \(h \neq 0,\) for the given function \(f\). $$f(x)=3 x^{2}+2 x$$

Short Answer

Expert verified
The difference quotient of the function \(f(x)=3x^{2}+2x\) is \(6x+3h+2\).

Step by step solution

01

Insert the function into the difference quotient

First, substitute the function \(f(x) = 3x^{2}+2x\) into the expression of the difference quotient. This results in: \(\frac{f(x+h)-f(x)}{h}= \frac{(3(x+h)^{2}+2(x+h))-(3x^{2}+2x)}{h}\)
02

Simplify the numerator

The next step is to simplify the numerator. Expand and simplify the terms to get: \(\frac{3x^{2}+6xh+3h^{2}+2x+2h-3x^{2}-2x}{h}= \frac{6xh+3h^{2}+2h}{h}\)
03

Divide Each Term by \(h\)

To further simplify the expression, divide each term in the numerator by \(h\). Therefore, the difference quotient becomes: \(6x+3h+2\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Precalculus
Precalculus is a foundational area of mathematics that prepares students for calculus. It combines the skills and concepts from algebra and trigonometry to tackle more advanced mathematical problems.
A crucial topic covered in precalculus is the difference quotient, which provides a way to approximate the slope of the tangent line to a curve at a point. This concept becomes essential in understanding derivatives, a core component of calculus.
The difference quotient formula, \(\frac{f(x+h)-f(x)}{h}\), is used as an introduction to the idea of a derivative. By working with this formula, students start to see how small changes in \(x\) affect the function \(f(x)\), leading to a deeper understanding of instantaneous rates of change.
Precalculus lays the groundwork by building on existing algebraic reasoning skills, introducing new types of functions, and encouraging problem-solving strategies that are vital for tackling calculus.
Algebraic Functions
Algebraic functions are expressions that involve constants and variables, using operations like addition, subtraction, multiplication, division, and exponentiation involving whole numbers.
In the given exercise, we deal with the algebraic function \(f(x) = 3x^2 + 2x\). This quadratic function consists of terms raised to the power of 2 and 1, making it a polynomial.
In the context of the difference quotient, students learn how to manipulate these expressions by expanding polynomials and simplifying terms.
  • Substitution: Inserting \(x + h\) into the function, as shown in \((3(x+h)^2 + 2(x+h))\).
  • Expansion: Expanding the squared term \((x+h)^2\) and distributing the coefficients.
  • Simplification: Collecting like terms and reducing the expression.
These steps help students practice their algebraic skills and build confidence in handling more complex functions in calculus.
Derivatives
Derivatives are one of the most significant concepts in calculus, describing how a function changes as its input changes.
The difference quotient \(\frac{f(x+h)-f(x)}{h}\), is a fundamental building block for understanding derivatives. It approximates the rate of change of a function over a small interval \(h\).
When \(h\) approaches zero, the difference quotient becomes the derivative of \(f(x)\). In our example, simplifying the expression yields \(6x + 3h + 2\). As \(h\) goes to zero, the derivative is \(6x + 2\).
This result indicates how steeply \(f(x) = 3x^2 + 2x\) increases at any point \(x\). The derivative function helps identify critical points, such as maxima, minima, and points of inflection. Understanding derivatives allows students to not just analyze change, but also predict behavior, and optimize various problems in calculus.

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Most popular questions from this chapter

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