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Fill in the missing terms of each geometric sequence. $$\begin{array}{ccccc} n & 0 & 1 & 2 & 3 \\ \hline a_{n} & & \frac{1}{9} & \frac{1}{27} & \end{array}$$

Short Answer

Expert verified
The complete geometric sequence is: \(a_0 = \frac{1}{3}\), \(a_1 = \frac{1}{9}\), \(a_2 = \frac{1}{27}\) and \(a_3 = \frac{1}{81}\).

Step by step solution

01

Identify the Common Ratio

In a geometric sequence, the common ratio is obtained by dividing each term by its preceding term. For given sequence, we can get the ratio by dividing \(a_2\) by \(a_1\), which is \(\frac{1}{27} \div \frac{1}{9} = \frac{1}{3}\).
02

Find the First Term

Now we know the common ratio, it's time to find the first term of the sequence, \(a_0\). We know that \(a_1 = a_0 \times r\). So, to find \(a_0\), we can rearrange the formula as \(a_0 = \frac{a_1}{r} = \frac{1}{9} \div \frac{1}{3} = \frac{1}{3}\). So, the first term of the sequence is \(\frac{1}{3}\).
03

Find the Fourth Term

Knowing \(a_0\) and the common ratio, \(r\), we can find the fourth term of the sequence, \(a_3\), by using the formula \(a_n = a_0 \times r^n\). Thus, \(a_3 = a_0 \times r^3 = \frac{1}{3} \times \(\frac{1}{3}\)^3 = \frac{1}{81}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Common Ratio
In any geometric sequence, the common ratio is a crucial component. It determines how each subsequent term is derived from the previous one. To find this ratio, you simply divide the term by the one that precedes it. For instance, in our given sequence, we took the term at position 2, which is \(\frac{1}{27}\), and divided it by the term at position 1, \(\frac{1}{9}\). This calculation gives us the common ratio of \(\frac{1}{3}\).

The common ratio is the same throughout the sequence, which means each term is consistently obtained by multiplying the previous term by this fixed number. If the ratio remains constant, you can confidently use it to find any term within the sequence. Remember, a consistent ratio is what makes the sequence geometric.
First Term of a Sequence
Identifying the first term in a geometric sequence is key to determining the entire sequence. The first term is commonly represented by \(a_0\) and serves as the starting point of the whole sequence. Once we have the common ratio, finding the first term becomes straightforward.

In the example sequence, given \(a_1 = \frac{1}{9}\) and the common ratio \(r = \frac{1}{3}\), we can calculate the first term \(a_0\). By rearranging the formula \(a_1 = a_0 \times r\), we solve for \(a_0\) as follows: \(a_0 = \frac{a_1}{r} = \frac{1}{9} \div \frac{1}{3} = \frac{1}{3}\). This starting point, \(\frac{1}{3}\), sets the foundation for the rest of the sequence.
Recursive Formula
The recursive formula in sequences provides a way to express subsequent terms based on previous ones. For geometric sequences, the recursive formula leverages the common ratio and the prior term
  • \(a_{n+1} = a_n \times r\), where \(a_n\) represents the current term.
This formula is particularly powerful because it allows you to construct the entire sequence step by step.

For our sequence, starting with \(a_0 = \frac{1}{3}\) and using the common ratio \(r = \frac{1}{3}\), we apply the recursive formula:
  • \(a_1 = a_0 \times r = \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}\)
  • \(a_2 = a_1 \times r = \frac{1}{9} \times \frac{1}{3} = \frac{1}{27}\)
  • \(a_3 = a_2 \times r = \frac{1}{27} \times \frac{1}{3} = \frac{1}{81}\)
With this formula, determining each next term becomes a simple multiplication task using the common ratio, illustrating the elegance and simplicity of geometric sequences.

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Most popular questions from this chapter

Use counting principles from Section 10.4 to calculate the number of outcomes. A pair of dice, one blue and one green, are rolled and the number showing on the top of each die is recorded. What is the probability that the sum of the numbers on the two dice is \(7 ?\)

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Consider the following experiment: pick one coin out of a bag that contains one quarter, one dime, one nickel, and one penny. What is the probability of picking a nickel?

In this set of exercises, you will use sequences to study real-world problems. Knitting Knitting, whether by hand or by machine, uses a sequence of stitches and proceeds row by row. Suppose you knit 100 stitches for the bottommost row and increase the number of stitches in each row thereafter by 4 This is a standard way to make the sleeve portion of a sweater. (a) What type of sequence does the number of stitches in each row produce: arithmetic, geometric, or neither? (b) Find a rule that gives the number of stitches in the nth row. (c) How many rows must be knitted to end with a row of 168 stitches?

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