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Find the rule for the geometric sequence having the given terms. $$\begin{array}{ccc} n & 3 & 6 \\ \hline h_{n} & \frac{2}{27} & \frac{2}{729} \end{array}$$

Short Answer

Expert verified
The rule for the geometric sequence is \(h_n = \frac{2}{3} * (\frac{1}{3})^n\). The first term \(h_0\) is \(\frac{2}{3}\) and the common ratio \(r\) is \(\frac{1}{3}\).

Step by step solution

01

Identify Given Values

In the problem, it is given that the third term \(h_3 = \frac{2}{27}\) and the sixth term \(h_6 = \frac{2}{729}\). A general formula for the geometric sequence is \(h_n = h_0 * r^n\), where \(h_n\) is the nth term, \(h_0\) is the first term, and \(r\) is the common ratio.
02

Setup the Equations

We can set up two equations from the general formula of the geometric sequence using the given terms. The equations will be:1. \(h_3 = h_0 * r^3 = \frac{2}{27}\)2. \(h_6 = h_0 * r^6 = \frac{2}{729}\)
03

Solve for the Ratio

Divide the second equation by the first equation in order to obtain the ratio \(r\). The calculation would be as follows: \(\frac{h_6}{h_3} = \frac{h_0 * r^6}{h_0 * r^3}\) ​which simplifies to \(r^3 = \frac{2}{729} / \frac{2}{27} = \frac{1}{27}\). Then, we take the cube root of both sides to find \(r = \sqrt[3]{\frac{1}{27}} = \frac{1}{3}\).
04

Solve for the First term

Substitute the value of \(r\) into the first equation in order to find \(h_0\). The equation is \(h_3 = h_0 * r^3 = \frac{2}{27}\). Substitute \(r = \frac{1}{3}\) to find \(h_0 = \frac{h_3}{(\frac{1}{3})^3} = \frac{\frac{2}{27}}{(\frac{1}{3})^3} = \frac{2}{3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Common Ratio
In a geometric sequence, each term is derived from the previous term by multiplying it with a fixed number known as the common ratio. This ratio is pivotal because it defines the pattern of the sequence.
When dealing with a sequence, once you know any term and the common ratio, you can determine any other term in the sequence. To find the common ratio in the problem, we had two terms: the third term, \(h_3 = \frac{2}{27}\), and the sixth term, \(h_6 = \frac{2}{729}\). By setting up the equations based on these terms and then dividing them, we arrived at \(r^3 = \frac{1}{27}\). This equation tells us how the sequence has grown over three steps. By calculating the cube root of both sides, the common ratio \(r\) is found to be \(\frac{1}{3}\).
  • Key idea: The common ratio is constant and allows the sequence to progress in a predictable manner.
  • Finding the common ratio helps in finding any term in the sequence.
  • In this exercise, identifying \(r\) involved dividing the sixth term by the third term and calculating the cube root of the result.
General Formula
The general formula for a geometric sequence provides a universal way to calculate any term of that sequence. It is expressed as \(h_n = h_0 \cdot r^n\), where \(h_n\) is the term you want to find, \(h_0\) is the first term, and \(r\) is the common ratio.
This formula is powerful because it connects every term to the very first term, scaling it by multiplying with \(r^n\). In our problem, even though the value of \(h_0\) wasn't given directly, the use of the given terms and the common ratio allowed us to calculate it.
  • Importance: This formula is essential for finding any term within the sequence as long as the first term and the common ratio are known.
  • Flexibility: Even if you don't know \(h_0\), calculating it using other known terms and the ratio is straightforward, as seen when finding it to be \(\frac{2}{3}\) in this exercise.
Cube Root
The cube root is a specific type of root that undoes cubing a number. For any number \(x\), the cube root is a number \(y\) such that \(y^3 = x\). Understanding cube roots is crucial when the relationship between elements involves cubes.In our exercise, we found ourselves needing to determine the cube root when solving for the common ratio of the sequence. After simplifying the division of given terms, \(r^3\) equates to \(\frac{1}{27}\). To find \(r\), we needed the cube root of \(\frac{1}{27}\), which is \(\frac{1}{3}\).
  • Definition: The cube root reverses the cube operation and is represented in mathematics as \(\sqrt[3]{x}\).
  • Application: Essential when resolving equations involving terms raised to the third power.
  • In geometry and algebra, roots are fundamental for dealing with polynomial equations and sequences.

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Most popular questions from this chapter

State whether the sequence is arithmetic or geometric. $$4,10,16,22, \dots$$

This set of exercises will draw on the ideas presented in this section and your general math background. Find the next two terms in the geometric sequence whose first three terms are \((1+x),(1+x)^{2},\) and \((1+x)^{3} .\) What is the common ratio \(r\) in this case?

In this set of exercises, you will use sequences to study real-world problems. Knitting Knitting, whether by hand or by machine, uses a sequence of stitches and proceeds row by row. Suppose you knit 100 stitches for the bottommost row and increase the number of stitches in each row thereafter by 4 This is a standard way to make the sleeve portion of a sweater. (a) What type of sequence does the number of stitches in each row produce: arithmetic, geometric, or neither? (b) Find a rule that gives the number of stitches in the nth row. (c) How many rows must be knitted to end with a row of 168 stitches?

In a telephone survey, people are asked whether they have seen each of four different films. Their answers for each film (yes or no) are recorded. (a) What is the sample space? (b) What is the probability that a respondent has seen exactly two of the four films? (c) Assuming that all outcomes are equally likely, what is the probability that a respondent has seen all four films?

Concepts This set of exercises will draw on the ideas presented in this section and your general math background. \- A sequence \(b_{0}, b_{1}, b_{2}, \ldots\) has the property that \(b_{n}=\) \(\left(\frac{n+3}{n+2}\right) b_{n-1}\) for \(n=1,2,3, \ldots,\) where \(c\) is a positive constant to be determined. Find \(c\) if \(b_{2}=25\) and \(b_{4}=315\)

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