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Write down the variable parts of the terms in the expansion of the binomial. $$(a+b)^{6}$$

Short Answer

Expert verified
The variable parts of the terms in the expansion are \( a^6, a^5b, a^4b^2, a^3b^3, a^2b^4, ab^5, b^6 \)

Step by step solution

01

Identify the binomial theorem

One must first know the binomial theorem which is \( (a+b)^n = \sum_{r=0}^{n} \, ^nC_r a^{n-r}b^r \) where \( n \) can be any whole number, \( ^nC_r \) are the binominial coefficients that can be found using the formula \( ^nC_r = \frac{n!}{r!(n-r)!} \), \( ! \) denotes factorial operation.
02

Apply the binomial theorem for \( (a+b)^6 \)

Next, apply the binomial theorem to our problem, which is \( (a+b)^{6} \). The expansion of this will form 7 terms because there is an increment of 1 in the total number of terms.
03

Write down the expanded form of \( (a+b)^6 \)

The expanded form of \( (a+b)^6 \) will hence be \( ^6C_0 a^6b^0 + ^6C_1 a^5b^1 + ^6C_2 a^4b^2 + ^6C_3 a^3b^3 + ^6C_4 a^2b^4 + ^6C_5 a^1b^5 + ^6C_6 a^0b^6 \)
04

Identify the variable parts of the terms

The variable parts of the terms in the expansion are the ones associated with the variables a and b in each term.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficients
The binomial coefficients are integral parts of binomial theorem expansion and can seem daunting at first glance but are quite simple once you understand them. They represent the number of ways to choose 'r' elements out of a set of 'n', irrespective of their order and are denoted by the symbol \(^nC_r\) or sometimes \(C(n, r)\).

Imagine you have a fruit basket with 'n' kinds of fruits and you want to see how many ways you can select 'r' types out of them. This selection of 'r' fruits from 'n' similar to how binomial coefficients work. They essentially tell you how many different terms there will be when you multiply out a binomial raised to a power 'n', like in the question, \((a+b)^6\).

Each coefficient corresponds to a specific term in the binomial expansion and pairs up with the variable parts to complete the term. As seen in the exercise, the binomial coefficients for each term of \((a+b)^6\) can be calculated using the formula \(^nC_r = \frac{n!}{r!(n-r)!}\). For instance, the first term's coefficient is \(^6C_0\), the second \(^6C_1\), and so on until \(^6C_6\).

By understanding how to calculate and interpret binomial coefficients, you've mastered an essential part of expanding binomials and are on your way to confidently tackling any problems involving them.
Factorial Operation
The factorial operation is a mathematical process that involves multiplying a series of descending natural numbers. It is symbolized with an exclamation mark \( ! \), for example, \(5!\) is read as '5 factorial'. It represents the product of all positive integers from 1 to 5, which is \(5 \times 4 \times 3 \times 2 \times 1 = 120\).

This operation is not just a mathematician's fancy - it’s a tool deployed in various calculations, such as combinatorics, algebra, and our current focus, the binomial theorem. Factorials help find the binomial coefficients that are central to binomial expansions because they allow us to calculate the number of combinations in a given situation.

When looking at the binomial theorem expansion, you need to perform factorial operations as part of finding the binomial coefficients. The formula \(^nC_r = \frac{n!}{r!(n-r)!}\) clearly shows factorials in action. Understanding how the factorial operation works is like finding the keys to a treasure trove of mathematical concepts, allowing for accurate and efficient calculations in the realm of binomial expansions and beyond.
Binomial Expansion Terms
Each term in the binomial expansion is a result of the combination of binomial coefficients with the powers of the binomial terms. These terms follow a specific pattern dictated by the binomial theorem. When you expand a binomial like \((a+b)^6\), each term is an intimate dance between the number of choices (the binomial coefficients) and the variables raised to specific powers.

In the sequence of expansion terms for \((a+b)^6\), as shown in the textbook solution, you'll notice that with every step from the first term to the last, the power of 'a' decreases while the power of 'b' increases. They begin as \(a^6b^0\) and transition to \(a^0b^6\). This meticulous change in the power of variables is not random; it is a subset of the internextricable pattern brought forth by the binomial theorem.

Recognizing the orderly progression of the binomial expansion terms can simplify complex algebraic problems and bring clarity to what might initially appear as a tangle of numbers and letters. By breaking down the expansion into its individual terms, and understanding the role of coefficients and variable parts, students can solve binomial expansion problems with greater ease and confidence.

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Most popular questions from this chapter

In this set of exercises, you will use sequences to study real-world problems. Investment An income-producing investment valued at \(\$ 2000\) pays interest at an annual rate of \(6 \% .\) Assume that the interest is taken out as income and therefore is not compounded. (a) Make a table in which you list the initial investment along with the total value of the investment-related assets (initial investment plus total interest earned) at the end of each of the first 4 years. (b) What is the total value of the investment-related assets after \(n\) years?

Each card in a standard deck of 52 cards belongs to one of four different suits: hearts, diamonds, spades, or clubs. There are 13 cards in each suit. Consider a scenario in which you draw five cards from the deck, one at a time, and record only the suit to which each card drawn belongs. (a) Describe the sample space. (b) What is the probability that the set of five cards you draw consists of two spades, one heart, one diamond, and one club (drawn in any order)? (c) What is the probability that exactly two of the five cards you draw are from the same suit?

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In Exercises \(5-25,\) prove the statement by induction. \(3^{n}-1\) is divisible by 2

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