/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Evaluate \(f(a), f(a+1),\) and \... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate \(f(a), f(a+1),\) and \(f\left(\frac{1}{2}\right)\). $$f(x)=4 x+3$$

Short Answer

Expert verified
The results of the exercise are: \(f(a)=4a+3\), \(f(a+1)=4a+7\), and \(f\left(\frac{1}{2}\right)=5\).

Step by step solution

01

Substituting a

First, substitute \(a\) into \(f(x)=4x+3\). This leads to \(f(a) = 4a + 3\)
02

Substituting a+1

In the second instance, substitute \(a+1\) into \(f(x)=4x+3\). This gives us \(f(a+1) = 4(a+1) + 3 = 4a + 4 + 3 = 4a + 7\)
03

Substituting 1/2

Lastly, substitute \(\frac{1}{2}\) into \(f(x)=4x+3\). This will result in \(f\left(\frac{1}{2}\right) = 4 \cdot \left(\frac{1}{2}\right) + 3 = 2 + 3 = 5\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Substituting Values into Functions
Substituting values into functions is a fundamental skill in algebra that involves replacing the variable in a function with a specific value to calculate the output. This process turns abstract expressions into tangible numbers that you can work with. Let's take a closer look at our example function, f(x)=4x+3. When we're asked to find f(a), we replace every instance of x with a and perform the calculations. It's just like plugging in numbers into your calculator, but instead of numbers, you're plugging in whatever the problem specifies, like a, a+1, or even fractions like 1/2.

For f(a), you'll get 4a + 3. For f(a+1), replace x with a+1 to get 4(a+1) + 3. Simplify this to 4a + 4 + 3, which is 4a + 7. Finally, substituting 1/2 for x gives you 4(1/2) + 3, which simplifies to 5. By doing so, you can evaluate the function for any input within its domain.
Linear Functions
Linear functions are the simplest form of functions that produce a straight line when graphed on a coordinate plane. They follow the format f(x) = mx + b, where m is the slope, and b is the y-intercept—this is the point where the line crosses the y-axis. In the equation f(x)=4x+3, the slope is 4, and the y-intercept is 3. So, for every unit increase in x, f(x) increases by 4 units. This linear relationship makes these functions very predictable and easy to work with.

When you're dealing with a linear function, you're looking at a straightforward, proportional change. This property is what allows us to easily substitute values and immediately see the impact on the function's output, as each input has one and only one output. That's why evaluating f(a+1) simply involves adding 1 to a and determining the corresponding increase in f(x) based on the slope.
Algebraic Expressions
Algebraic expressions are mathematical phrases that can contain numbers, variables, and operational symbols. For example, in the expression 4x+3, 4x represents the variable part, and 3 is the constant term. You'll encounter algebraic expressions in functions, equations, and inequalities.

The beauty of algebraic expressions lies in their ability to generalize mathematical ideas. Instead of working with specific numbers, expressions allow you to work with symbols that represent any number. Algebra allows us to manipulate these symbols using the same rules you'd use for tangible numbers. As you substitute values into these expressions, you convert the abstract into the concrete and solve real-world problems. Understanding how to work with these expressions is crucial, and as you practice, you'll become more adept at 'translating' them into meaningful numerical answers.

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Most popular questions from this chapter

Solve the inequality. Express your answer in interval notation. $$-2 x-1 \geq \frac{x+5}{2}$$

A long-distance telephone company advertises that it charges 1.00 dollars for the first 20 minutes of phone use and 7 cents a minute for every minute beyond the first 20 minutes. Let \(C(t)\) denote the total cost of a telephone call lasting \(t\) minutes. Assume that the minutes are nonnegative integers. (a) Many people will assume that it will cost only 0.50 dollars to talk for 10 minutes. Why is this incorrect? (b) Write an expression for the function \(C(t).\) (c) How much will it cost to talk for 5 minutes? 20 minutes? 30 minutes?

Solve the inequality. Express your answer in interval notation. $$3 x+1 \leq 7$$

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A telephone company offers two different long-distance calling plans. Plan A charges a fee of S4. 95 per month plus \(\$ 0.07\) for each minute used. Plan B costs \(\$ 0.10\) per minute of use, but has no monthly fee. (IMAGE CANNOT COPY) (a) Find the total monthly cost of using Plan \(A\) as a linear function of the number of minutes used. (b) Find the total monthly cost of using Plan \(B\) as a linear function of the number of minutes used. (c) Interpret the \(y\) -intercept of the graph of each cost function. (d) Calculate algebraically the number of minutes of long-distance calling for which the two plans will cost the same. What will be the monthly charge at that level of usage? 4 (e) \(\quad\) Graph the functions from parts (a) and (b) on the same set of axes and find the number of minutes of long-distance calling for which the two plans will cost the same. You will have to adjust the window size and scales appropriately. What is the monthly cost at that level of usage? Compare your result with the result you found algebraically.

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