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Simplify each expression to a single complex number. $$ i^{6} $$

Short Answer

Expert verified
The simplified expression is -1.

Step by step solution

01

Understand the Powers of i

To solve this problem, it's important to remember that the imaginary unit \( i \) is defined such that \( i^2 = -1 \). This definition forms the basis for simplifying higher powers of \( i \). We can note a pattern: \( i^1 = i \), \( i^2 = -1 \), \( i^3 = -i \), and \( i^4 = 1 \). After \( i^4 \), the powers repeat this cycle: \( i^5 = i \), \( i^6 = -1 \), and so on.
02

Simplify i^6 Using the Pattern

Having identified the repeating powers, calculate \( i^6 \). Notice that \( i^6 = (i^4) imes (i^2) \). From the pattern: \( i^4 = 1 \) and \( i^2 = -1 \). Therefore, \( i^6 = 1 imes -1 = -1 \).
03

Write the Final Complex Number

The simplified expression of \( i^6 \) is thus \( -1 \). In terms of its complex number form, this is equivalent to \( -1 + 0i \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Powers of i
When dealing with powers of the imaginary unit \( i \), recognizing the cyclic nature of its powers is key. The imaginary unit \( i \) is defined mathematically such that \( i^2 = -1 \). This definition influences the powers that follow:
  • \( i^1 = i \)
  • \( i^2 = -1 \)
  • \( i^3 = -i \)
  • \( i^4 = 1 \)
After \( i^4 \), these results repeat cyclically in groups of four. This repetitive pattern is crucial for simplifying expressions with higher powers. For instance, instead of computing \( i^6 \) by multiplying six times, we recognize \( i^6 \) falls in the same cycle as \( i^2 \), hence \( i^6 = -1 \). By noticing this sequence, calculations become more straightforward and efficient. Understanding this pattern helps in simplifying any power of \( i \).
Imaginary Unit
The imaginary unit, denoted as \( i \), is a fundamental mathematical concept that extends the real number system to the complex number system. By definition, \( i \) is the square root of \(-1\), giving it unique properties different from regular real numbers. Furthermore:
  • When squared, \( i \) yields \(-1\) (\( i^2 = -1 \)), an essential fact that underpins many of its applications.
  • Since \( i \) leads to negative results, it opens doors to handling square roots of negative numbers, enabling solutions in equations previously unsolvable in real numbers.
The introduction of \( i \) lets mathematicians work within a larger set of numbers where they can find roots, solutions, and properties not evident in real numbers alone. This was crucial for developing complex analysis and helps solve real-world problems across different fields, including engineering and physics.
Simplifying Complex Expressions
Simplifying complex expressions involving imaginary numbers can seem daunting, but with an understanding of powers of \( i \) and basic algebraic maneuvers, it becomes a manageable task. To simplify a complex expression:
  • Identify powers of \( i \) present in the expression. Use the known cycle \( i^1 \), \( i^2 \), \( i^3 \), and \( i^4 \) to simplify powers of \( i \) to basic forms like \( 1 \), \( -1 \), \( i \), or \( -i \).
  • Combine like terms, simplifying both the real and imaginary parts. This means collating and operating on real numbers separately from imaginary ones (multiples of \( i \)).
  • Express the result in standard form, \( a + bi \), where \( a \) is the real part, and \( b \) is the imaginary part.
Take \( i^6 \) as an example: simplify by restructuring using the cyclic nature of powers, resulting in \(-1\), which can be written as \(-1 + 0i\). This systematic method can resolve even more complex expressions, ensuring clarity and simplicity.

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