Chapter 8: Problem 14
Find the magnitude and direction of the vector. $$ \langle 3,7\rangle $$
Short Answer
Expert verified
Magnitude: \( \sqrt{58} \), Direction: \( 66.80^\circ \).
Step by step solution
01
Identify the Components of the Vector
The vector given is \( \langle 3, 7 \rangle \). This means the x-component (horizontal component) is 3 and the y-component (vertical component) is 7. These components will be used to find the magnitude and direction of the vector.
02
Calculate the Magnitude of the Vector
The magnitude of a vector \( \langle x, y \rangle \) can be found using the formula \( \| \mathbf{v} \| = \sqrt{x^2 + y^2} \). For the vector \( \langle 3, 7 \rangle \), this becomes \( \| \mathbf{v} \| = \sqrt{3^2 + 7^2} = \sqrt{9 + 49} = \sqrt{58} \). Therefore, the magnitude is \( \sqrt{58} \).
03
Determine the Direction (Angle) of the Vector
The direction or angle \( \theta \) of the vector relative to the positive x-axis is found using the arctangent function: \( \theta = \tan^{-1} \left( \frac{y}{x} \right) \). For the vector \( \langle 3, 7 \rangle \), \( \theta = \tan^{-1} \left( \frac{7}{3} \right) \). Compute this value using a calculator to find \( \theta \).
04
Finalize the Direction in Degrees
Use a calculator to compute the direction: \( \theta = \tan^{-1} \left( \frac{7}{3} \right) \approx 66.80^\circ \). The vector's direction is approximately 66.80 degrees from the positive x-axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Components
A vector can be thought of as an arrow pointing from one place to another in space. Each arrow has certain characteristics, one of which is its components. The components of a vector are essentially its description in terms of horizontal and vertical distances. In the vector \( \langle 3, 7 \rangle \), the number 3 is the x-component, which tells us how far to move along the x-axis. The number 7 is the y-component, indicating how far to move along the y-axis. When dealing with components, it is helpful to remember:
- The x-component is always horizontal.
- The y-component is always vertical.
- Both components are necessary to precisely describe the vector's direction and magnitude.
Magnitude Calculation
Magnitude is a scalar quantity and signifies how long the vector is. It acts like a yardstick for the vector, telling you the "size" of it without any indication of its direction. Calculating the magnitude involves a straightforward application of the Pythagorean theorem.To find the magnitude of vector \( \langle 3, 7 \rangle \), you use the formula:\[ \| \mathbf{v} \| = \sqrt{x^2 + y^2} \]For the vector in question, this becomes:\[ \| \mathbf{v} \| = \sqrt{3^2 + 7^2} = \sqrt{9 + 49} = \sqrt{58} \]Thus, the magnitude is \( \sqrt{58} \), or roughly 7.62 when approximated to two decimal places.Always remember:
- The magnitude is always a positive value.
- It gives the total distance from the origin to the point represented by the vector.
Angle Determination
The angle or direction of a vector expresses where the vector is pointing relative to the positive x-axis. It's like a compass telling you which way the vector "leans" in the coordinate plane. To determine this direction, we use the arctangent function, which calculates the angle based on the y-component and x-component ratio. Specifically, it's given by:\[ \theta = \tan^{-1} \left( \frac{y}{x} \right) \]For the vector \( \langle 3, 7 \rangle \), this ratio is \( \frac{7}{3} \), so:\[ \theta = \tan^{-1} \left( \frac{7}{3} \right) \]Using a calculator provides the angle \( \theta \), approximately 66.80 degrees.Key points to note:
- The angle is measured from the positive x-axis.
- It is usually expressed in degrees.
- This angle helps in visualizing the vector's direction accurately.