/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Write an equation for a line per... [FREE SOLUTION] | 91Ó°ÊÓ

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Write an equation for a line perpendicular to \(h(t)=-2 t+4\) and passing through the point (-4,-1)

Short Answer

Expert verified
The equation is \(y = \frac{1}{2}x + 1\).

Step by step solution

01

Identify the Slope of the Given Line

The equation of the given line is in the slope-intercept form: \(h(t) = -2t + 4\). This gives it a slope of \(-2\).
02

Calculate the Perpendicular Slope

To find the slope of a line that is perpendicular to another, take the negative reciprocal of the original slope. The negative reciprocal of \(-2\) is \(\frac{1}{2}\). So, the perpendicular slope will be \(\frac{1}{2}\).
03

Use the Point-Slope Form

With the perpendicular slope \(\frac{1}{2}\) and the point \((-4, -1)\), use the point-slope form of a line \(y - y_1 = m(x - x_1)\). Here, \(m\) is \(\frac{1}{2}\), \(x_1\) is \(-4\), and \(y_1\) is \(-1\).
04

Substitute Values into the Point-Slope Form

Substitute \(m = \frac{1}{2}\), \(x_1 = -4\), and \(y_1 = -1\) into the equation \(y - y_1 = m(x - x_1)\):\[y + 1 = \frac{1}{2}(x + 4)\]
05

Simplify the Equation

Distribute \(\frac{1}{2}\):\[y + 1 = \frac{1}{2}x + 2\]Subtract 1 from both sides to solve for \(y\):\[y = \frac{1}{2}x + 1\]
06

Present the Final Equation

The equation of the line perpendicular to \(h(t) = -2t + 4\) and passing through \((-4, -1)\) is:\[y = \frac{1}{2}x + 1\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Point-Slope Form
The point-slope form is a really handy tool in geometry for finding the equation of a line. This form is especially useful when you know a specific point on the line and its slope. The general equation for point-slope form is:
  • \(y - y_1 = m(x - x_1)\)
Here, \(m\) represents the slope of the line. \((x_1, y_1)\) is the point the line passes through.
To use this form:
  • Identify the slope \(m\) of the line
  • Use the given coordinates of the point \((x_1, y_1)\)
Once these values are plugged into the equation, you're left with a simple linear equation representing the line. This makes it a straightforward process to write equations for lines, especially in algebra problems.
Slope-Intercept Form
The slope-intercept form is another common way to express linear equations. It's called the slope-intercept form because it makes the slope and the y-intercept clear and easy to see. The form looks like this:
  • \(y = mx + c\)
In this equation, \(m\) is the slope, just like in point-slope form, and \(c\) is the y-intercept (the point where the line crosses the y-axis).
This form is convenient because it allows you to quickly graph a linear equation by identifying the slope and where the line will intersect the y-axis. To convert from point-slope form to slope-intercept form, you rearrange the equation to solve for \(y\).

In the problem given, once we identified the perpendicular slope and point, we initially used the point-slope form and then converted it to the slope-intercept form for final presentation.
Negative Reciprocal
A negative reciprocal is used when we're dealing with perpendicular lines. It means flipping the fraction of a number and changing the sign. For example, the negative reciprocal of \(-2\) is calculated as follows:
  • First, take the reciprocal of \(-2\) which is \(-\frac{1}{2}\)
  • Change the sign to make it positive \(\frac{1}{2}\)
The negative reciprocal helps us determine the slope of a line that is perpendicular to another.
This property is crucial since perpendicular lines intersect at a right angle. In the exercise, the original line had a slope of \(-2\), so the perpendicular slope we used was \(\frac{1}{2}\). Knowing how to find a negative reciprocal ensures you can find these perpendicular relationships between lines effortlessly.
Linear Equations
Linear equations form the basis of algebra and coordinate geometry, representing straight lines on a graph. They are equations involving one or two variables with no exponents greater than one. Here's the general concept:
  • In the equation, variables are usually \(x\) and \(y\)
  • It forms a straight line when graphed
Linear equations come in standard forms, such as point-slope and slope-intercept forms, to express their relationships between variables.
The characteristic feature of a linear equation is its constant slope, which represents the rate of change between the variables. The example provided in the original exercise, \(y = \frac{1}{2}x + 1\), represents a linear equation derived from applying perpendicular line properties.
Understanding linear equations is critical to analyzing how different lines can be related through their slopes and points, enabling easy problem-solving in algebra and beyond.

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