Chapter 2: Problem 43
Write an equation for a line perpendicular to \(h(t)=-2 t+4\) and passing through the point (-4,-1)
Short Answer
Expert verified
The equation is \(y = \frac{1}{2}x + 1\).
Step by step solution
01
Identify the Slope of the Given Line
The equation of the given line is in the slope-intercept form: \(h(t) = -2t + 4\). This gives it a slope of \(-2\).
02
Calculate the Perpendicular Slope
To find the slope of a line that is perpendicular to another, take the negative reciprocal of the original slope. The negative reciprocal of \(-2\) is \(\frac{1}{2}\). So, the perpendicular slope will be \(\frac{1}{2}\).
03
Use the Point-Slope Form
With the perpendicular slope \(\frac{1}{2}\) and the point \((-4, -1)\), use the point-slope form of a line \(y - y_1 = m(x - x_1)\). Here, \(m\) is \(\frac{1}{2}\), \(x_1\) is \(-4\), and \(y_1\) is \(-1\).
04
Substitute Values into the Point-Slope Form
Substitute \(m = \frac{1}{2}\), \(x_1 = -4\), and \(y_1 = -1\) into the equation \(y - y_1 = m(x - x_1)\):\[y + 1 = \frac{1}{2}(x + 4)\]
05
Simplify the Equation
Distribute \(\frac{1}{2}\):\[y + 1 = \frac{1}{2}x + 2\]Subtract 1 from both sides to solve for \(y\):\[y = \frac{1}{2}x + 1\]
06
Present the Final Equation
The equation of the line perpendicular to \(h(t) = -2t + 4\) and passing through \((-4, -1)\) is:\[y = \frac{1}{2}x + 1\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Point-Slope Form
The point-slope form is a really handy tool in geometry for finding the equation of a line. This form is especially useful when you know a specific point on the line and its slope. The general equation for point-slope form is:
To use this form:
- \(y - y_1 = m(x - x_1)\)
To use this form:
- Identify the slope \(m\) of the line
- Use the given coordinates of the point \((x_1, y_1)\)
Slope-Intercept Form
The slope-intercept form is another common way to express linear equations. It's called the slope-intercept form because it makes the slope and the y-intercept clear and easy to see. The form looks like this:
This form is convenient because it allows you to quickly graph a linear equation by identifying the slope and where the line will intersect the y-axis. To convert from point-slope form to slope-intercept form, you rearrange the equation to solve for \(y\).
In the problem given, once we identified the perpendicular slope and point, we initially used the point-slope form and then converted it to the slope-intercept form for final presentation.
- \(y = mx + c\)
This form is convenient because it allows you to quickly graph a linear equation by identifying the slope and where the line will intersect the y-axis. To convert from point-slope form to slope-intercept form, you rearrange the equation to solve for \(y\).
In the problem given, once we identified the perpendicular slope and point, we initially used the point-slope form and then converted it to the slope-intercept form for final presentation.
Negative Reciprocal
A negative reciprocal is used when we're dealing with perpendicular lines. It means flipping the fraction of a number and changing the sign. For example, the negative reciprocal of \(-2\) is calculated as follows:
This property is crucial since perpendicular lines intersect at a right angle. In the exercise, the original line had a slope of \(-2\), so the perpendicular slope we used was \(\frac{1}{2}\). Knowing how to find a negative reciprocal ensures you can find these perpendicular relationships between lines effortlessly.
- First, take the reciprocal of \(-2\) which is \(-\frac{1}{2}\)
- Change the sign to make it positive \(\frac{1}{2}\)
This property is crucial since perpendicular lines intersect at a right angle. In the exercise, the original line had a slope of \(-2\), so the perpendicular slope we used was \(\frac{1}{2}\). Knowing how to find a negative reciprocal ensures you can find these perpendicular relationships between lines effortlessly.
Linear Equations
Linear equations form the basis of algebra and coordinate geometry, representing straight lines on a graph. They are equations involving one or two variables with no exponents greater than one. Here's the general concept:
The characteristic feature of a linear equation is its constant slope, which represents the rate of change between the variables. The example provided in the original exercise, \(y = \frac{1}{2}x + 1\), represents a linear equation derived from applying perpendicular line properties.
Understanding linear equations is critical to analyzing how different lines can be related through their slopes and points, enabling easy problem-solving in algebra and beyond.
- In the equation, variables are usually \(x\) and \(y\)
- It forms a straight line when graphed
The characteristic feature of a linear equation is its constant slope, which represents the rate of change between the variables. The example provided in the original exercise, \(y = \frac{1}{2}x + 1\), represents a linear equation derived from applying perpendicular line properties.
Understanding linear equations is critical to analyzing how different lines can be related through their slopes and points, enabling easy problem-solving in algebra and beyond.