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Find the domain of each function $$ f(x)=3-\sqrt{6-2 x} $$

Short Answer

Expert verified
The domain is \( (-\infty, 3] \).

Step by step solution

01

Understand the Function

The function given is \( f(x) = 3 - \sqrt{6 - 2x} \). It contains a square root, which imposes restrictions on the domain, because the expression inside the square root must be non-negative.
02

Set the Expression Inside the Square Root to be Non-negative

For the square root function \( \sqrt{6 - 2x} \), the expression inside the square root, \( 6 - 2x \), must be greater than or equal to zero. This is written as: \( 6 - 2x \geq 0 \).
03

Solve the Inequality

Solving the inequality for \( x \):\[6 - 2x \geq 0 \ -2x \geq -6 \ 2x \leq 6 \ x \leq 3.\]Thus, the inequality provides the range for \( x \) where the function is defined.
04

State the Domain

The domain of the function is the set of all possible values of \( x \) for which the function is defined. From the inequality solution, the domain is all real numbers \( x \) such that \( x \leq 3 \). In interval notation, the domain is \( (-\infty, 3] \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Square Root Function
In mathematics, a square root function includes the square root of a variable or an expression. Its general form is \( f(x) = \sqrt{x} \). This function is special because the square root of any number needs to result in a non-negative value. This means that the expression under the square root, called the radicand, must be zero or a positive number. For example, in the function \( f(x) = 3 - \sqrt{6 - 2x} \), the radicand is \( 6 - 2x \). Because you cannot take the square root of a negative value and get a real number, the radicand must be \( 6 - 2x \geq 0 \) for the function to be well-defined. The characteristics of square root functions are relevant when determining domains, as this function imposes natural restrictions on the values that \( x \) can take. This leads us to solving inequalities to find out which values make the radicand non-negative.
Solving Inequalities Involving Square Roots
When you solve inequalities for a function like \( f(x) = 3 - \sqrt{6 - 2x} \), your primary goal is to identify values of \( x \) that satisfy the expression under the square root being greater than or equal to zero. The inequality for this function is \( 6 - 2x \geq 0 \). The process involves simple algebraic manipulations:
  • First, maintain the inequality structure: \( 6 - 2x \geq 0 \).
  • To isolate \( x \), subtract \( 6 \) from both sides: \( -2x \geq -6 \).
  • Finally, divide each side by \(-2\). Remember that dividing by a negative flips the inequality sign: \( x \leq 3 \).
This gives a clear range of values for \( x \) wherein the original expression \( 6 - 2x \) remains non-negative. Prudent algebraic steps ensure you correctly find the range of valid \( x \) values.
Expressing Domain Using Interval Notation
Once you have determined the values for \( x \) that keep the function valid, you express these values using a concise mathematical language known as interval notation. Interval notation is a method of writing subsets of the real number line. In our inequality \( x \leq 3 \), all numbers less than or equal to 3 are part of the domain. Therefore, in interval notation, this domain is expressed as \((-\infty, 3]\).
  • The \((-\infty\) symbol means that there is no lower limit to the smallest value \( x \) can be. It stretches to negative infinity.
  • The \([3]\) includes the number 3 itself as part of the possible values of \( x \), illustrating that the boundary is closed at 3.
Interval notation presents the function's domain succinctly, providing a clear picture of which real numbers are allowable inputs for the function.

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