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For each table below, select whether the table represents a function that is increasing or decreasing, and whether the function is concave up or concave down. $$ \begin{array}{|l|l|} \hline x & g(x) \\ \hline 1 & 90 \\ \hline 2 & 80 \\ \hline 3 & 75 \\ \hline 4 & 72 \\ \hline 5 & 70 \\ \hline \end{array} $$

Short Answer

Expert verified
The function is decreasing and concave up.

Step by step solution

01

Determine if the Function is Increasing or Decreasing

To determine if the function is increasing or decreasing, observe the values of \( g(x) \) as \( x \) increases. As \( x \) increases from 1 to 5, \( g(x) \) decreases from 90 to 70. Therefore, the function is decreasing.
02

Determine if the Function is Concave Up or Concave Down

To determine concavity, examine the rate of change of \( g(x) \). Calculate the differences between consecutive \( g(x) \) values: \( g(2) - g(1) = 80 - 90 = -10 \), \( g(3) - g(2) = 75 - 80 = -5 \), \( g(4) - g(3) = 72 - 75 = -3 \), \( g(5) - g(4) = 70 - 72 = -2 \). Since the differences (-10, -5, -3, -2) are increasing, the rate of decrease is slowing down, which indicates that the function is concave up.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Increasing and Decreasing Functions
Understanding whether a function is increasing or decreasing is vital in precalculus because it tells us the behavior of the function over a specific range. To determine if a function is increasing or decreasing, observe how the function changes as the input, usually denoted by \( x \), changes.
If the function's output, denoted as \( g(x) \), increases when \( x \) increases, then the function is said to be increasing. On the other hand, if the function's output decreases as \( x \) increases, the function is decreasing. This concept can be visualized on a graph, where an increasing function will rise as you move from left to right, while a decreasing function will fall.
In the given exercise, as \( x \) increases from 1 to 5, \( g(x) \) decreases from 90 to 70; hence the function is decreasing. Observing this pattern can help in predicting the behavior of the function across its domain.
Concave Up and Concave Down
Concavity in functions gives insight into the direction of bending in the function's graph. This is important, as it helps in understanding the nature of turning points and the overall shape of the graph. A function is considered concave up if it bends upwards like a cup, and concave down if it bends downwards like a frown.
To determine concavity from a table of values, we look at how the differences between successive outputs change. If these differences increase, the function is concave up. Conversely, if they decrease, the function is concave down.
For the function in our exercise, the successive differences \( g(2) - g(1) = -10 \), \( g(3) - g(2) = -5 \), \( g(4) - g(3) = -3 \), and \( g(5) - g(4) = -2 \) are increasing. This pattern indicates that although the function is decreasing, the reduction is happening at a slower rate, thus the function is concave up.
Rate of Change in Functions
The rate of change is a crucial concept in understanding how functions behave. It describes how one quantity changes in relation to another. In precalculus, the rate of change often refers to the change in the function's output as the input changes.
To calculate the rate of change, we take the difference in \( g(x) \) values and divide by the difference in \( x \) values for two successive points. For example, the rate of change from \( x = 1 \) to \( x = 2 \) is \( \frac{g(2) - g(1)}{2-1} = -10 \). Such calculations can reveal if the function's slope is steep or shallow, which is indicated by the value of the rate of change.
Important points to note:
  • A constant positive rate signifies a consistently increasing function.
  • A constant negative rate signifies a consistently decreasing function.
  • Varying rates can indicate changing concavity, as seen when rates become less negative or more positive, it points towards a concave up behavior, as is the case in our exercise.
This clear understanding aids in the graphical depiction and the analytic understanding of functions.

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Most popular questions from this chapter

Determine the interval(s) on which the function is concave up and concave down. $$ m(x)=-2(x+3)^{3}+1 $$

Select all of the following tables which represent \(y\) as a function of \(x\). a. $$ \begin{array}{|l|l|} \hline \boldsymbol{x} & \boldsymbol{y} \\ \hline 0 & -2 \\ \hline 3 & 1 \\ \hline 4 & 6 \\ \hline 8 & 9 \\ \hline 3 & 1 \\ \hline \end{array} $$ b. $$ \begin{array}{|l|l|} \hline \boldsymbol{x} & \boldsymbol{y} \\ \hline-1 & -4 \\ \hline 2 & 3 \\ \hline 5 & 4 \\ \hline 8 & 7 \\ \hline 12 & 11 \\ \hline \end{array} $$ c. $$ \begin{array}{|l|l|} \hline \boldsymbol{x} & \boldsymbol{y} \\ \hline 0 & -5 \\ \hline 3 & 1 \\ \hline 3 & 4 \\ \hline 9 & 8 \\ \hline 16 & 13 \\ \hline \end{array} $$ d. $$ \begin{array}{|l|l|} \hline \boldsymbol{x} & \boldsymbol{y} \\ \hline-1 & -4 \\ \hline 1 & 2 \\ \hline 4 & 2 \\ \hline 9 & 7 \\ \hline 12 & 13 \\ \hline \end{array} $$

Describe how each function is a transformation of the original function \(f(x)\) $$ f(x+3) $$

Dave leaves his office in Padelford Hall on his way to teach in Gould Hall. Below are several different scenarios. In each case, sketch a plausible (reasonable) graph of the function \(s=d(t)\) which keeps track of Dave's distance \(s\) from Padelford Hall at time \(t\). Take distance units to be "feet" and time units to be "minutes." Assume Dave's path to Gould Hall is long a straight line which is 2400 feet long. [UW] a. Dave leaves Padelford Hall and walks at a constant spend until he reaches Gould Hall 10 minutes later. b. Dave leaves Padelford Hall and walks at a constant speed. It takes him 6 minutes to reach the half-way point. Then he gets confused and stops for 1 minute. He then continues on to Gould Hall at the same constant speed he had when he originally left Padelford Hall. c. Dave leaves Padelford Hall and walks at a constant speed. It takes him 6 minutes to reach the half-way point. Then he gets confused and stops for 1 minute to figure out where he is. Dave then continues on to Gould Hall at twice the constant speed he had when he originally left Padelford Hall. d. Dave leaves Padelford Hall and walks at a constant speed. It takes him 6 minutes to reach the half-way point. Then he gets confused and stops for 1 minute to figure out where he is. Dave is totally lost, so he simply heads back to his office, walking the same constant speed he had when he originally left Padelford Hall. e. Dave leaves Padelford heading for Gould Hall at the same instant Angela leaves Gould Hall heading for Padelford Hall. Both walk at a constant speed, but Angela walks twice as fast as Dave. Indicate a plot of "distance from Padelford" vs. "time" for the both Angela and Dave. f. Suppose you want to sketch the graph of a new function \(\mathrm{s}=\mathrm{g}(\mathrm{t})\) that keeps track of Dave's distance s from Gould Hall at time t. How would your graphs change in (a)-(e)?

Based on the table below, a. Evaluate \(f(8)\) b. Solve \(f(x)=7\) $$ \begin{array}{|l|l|l|l|l|l|l|l|l|l|l|} \hline \boldsymbol{x} & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 \\ \hline \boldsymbol{f}(\boldsymbol{x}) & 62 & 8 & 7 & 38 & 86 & 73 & 70 & 39 & 75 & 34 \\ \hline \end{array} $$

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