Chapter 1: Problem 17
Find the average rate of change of each function on the interval specified. Your answers will be expressions involving a parameter \((b\) or \(h)\). \(j(x)=3 x^{3}\) on \([1,1+h]\)
Short Answer
Expert verified
The average rate of change is \(9 + 9h + 3h^2\).
Step by step solution
01
Understand the formula for average rate of change
The average rate of change of a function \(f(x)\) on the interval \([a, b]\) is given by the expression \(\frac{f(b) - f(a)}{b - a}\). This formula calculates how much the function changes, on average, between two points on the graph of the function.
02
Identify function values
We need to find \(j(1)\) and \(j(1+h)\) for the function \(j(x) = 3x^3\). - Calculate \(j(1) = 3(1)^3 = 3\).- Express \(j(1+h)\) as \(3(1+h)^3\).
03
Expand expression for \(j(1+h)\)
Expand \(j(1+h) = 3(1+h)^3\) using the binomial theorem:\((1+h)^3 = 1 + 3h + 3h^2 + h^3\) So, \(j(1+h) = 3(1 + 3h + 3h^2 + h^3) = 3 + 9h + 9h^2 + 3h^3\).
04
Compute the change in the function values
Subtract \(j(1)\) from \(j(1+h)\):\[j(1+h) - j(1) = (3 + 9h + 9h^2 + 3h^3) - 3 = 9h + 9h^2 + 3h^3\]
05
Apply the average rate of change formula
Plug the expression from Step 4 into the average rate of change formula:\[\frac{j(1+h) - j(1)}{h} = \frac{9h + 9h^2 + 3h^3}{h}\]Simplify the expression by dividing each term by \(h\):\[= 9 + 9h + 3h^2\]
06
Write the final expression
The average rate of change of the function \(j(x) = 3x^3\) on the interval \([1, 1+h]\) is given by: \(9 + 9h + 3h^2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Theorem
The Binomial Theorem is a powerful tool in algebra used to expand expressions that are raised to a power. It takes an expression in the form of \((a + b)^n\) and provides a way to expand it using combinations. This expansion adds ease to the calculation of polynomial expressions, especially when dealing with specific powers. When applying the Binomial Theorem, the expression \((a + b)^n\) can be expanded as:
- \((1 + h)^3 = 1 + 3h + 3h^2 + h^3\)
Function Evaluation
Function evaluation is the process of determining the value of a function for specific inputs. It is core to calculus and algebra, allowing us to understand how a function behaves. In our exercise, the function given is \(j(x) = 3x^3\). To evaluate this function at specific points, we simply substitute the values into the function. For example:
- To find \(j(1)\), substitute 1 into \(j(x)\):
\(j(1) = 3(1)^3 = 3\). - For \(j(1+h)\), replace \(x\) with \((1+h)\):
\(j(1+h) = 3(1+h)^3\).
Interval Notation
Interval notation is a mathematical notation used to represent a set of numbers between two endpoints. It’s a concise way to define intervals on the real number line, indicating all numbers in between the endpoints. Intervals can be:
- Closed, denoted by brackets \([ ]\), meaning endpoints are included.
- Open, denoted by parentheses \(( )\), meaning endpoints are excluded.