Chapter 8: Problem 66
Sketch a graph of the polar equation. \(r=2 \sqrt{1-\sin ^{2}(\theta)},\) a hippopede
Short Answer
Expert verified
The graph is a circle, centered at (1,0) with a radius of 1.
Step by step solution
01
Simplify the Polar Equation
The given polar equation is \(r = 2 \sqrt{1-\sin^2(\theta)}\). Use the trigonometric identity \(\sin^2(\theta) + \cos^2(\theta) = 1\), which simplifies the expression \(1-\sin^2(\theta)\) to \(\cos^2(\theta)\). So the equation becomes \(r = 2 \cos(\theta)\).
02
Identify Properties of the Graph
The equation \(r = 2 \cos(\theta)\) corresponds to a circle with a diameter of 2 units. The center of this circle is at \(r = 1\) along the positive x-axis (polar axis), not the origin. This indicates symmetry about the polar axis, which suggests a circular path.
03
Convert Polar Equation to Cartesian Coordinates for Graphing
To sketch this circle, express the polar equation in Cartesian coordinates. Using \(x = r \cos(\theta)\) and \(y = r \sin(\theta)\), substitute \(r\) from the equation to get: \(x = 2 \cos^2(\theta)\) and \(y = 2 \cos(\theta)\sin(\theta)\). Also use the identity \(\cos(2\theta) = \cos^2(\theta) - \sin^2(\theta)\) and simplify to get \((x-1)^2 + y^2 = 1\), which confirms a circle centered at (1,0) with radius 1.
04
Sketch the Graph
Using the information that we have a circle centered at (1,0) with a radius of 1, sketch the graph by drawing a circle with these properties. The circle is tangent to the origin and extends from (0,0) to (2,0) on the x-axis.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
Polar coordinates offer a unique way to represent points on a plane. In this system, each point is defined by a distance from a reference point (the origin) and an angle from a reference direction (the positive x-axis). This is different from the Cartesian system, which uses x and y coordinates.
- The distance is denoted by \(r\). It is a non-negative value representing how far the point is from the origin.
- The angle is denoted by \(\theta\). It is usually measured in radians, with the direction typically counter-clockwise from the positive x-axis.
- \(x = r \cdot \cos(\theta)\)
- \(y = r \cdot \sin(\theta)\)
Trigonometric Identities
Understanding trigonometric identities is crucial for simplifying complex mathematical expressions. One of the most commonly used identities is the Pythagorean identity: \[ \sin^2(\theta) + \cos^2(\theta) = 1 \]This identity helps simplify expressions involving trigonometric functions. For instance, given an equation with \(1 - \sin^2(\theta)\), you can use this identity to rewrite it as \(\cos^2(\theta)\).Other important identities include the double angle formulas, such as:
- \(\cos(2\theta) = \cos^2(\theta) - \sin^2(\theta)\)
- \(\cos(2\theta) = 2\cos^2(\theta) - 1\)
- \(\cos(2\theta) = 1 - 2\sin^2(\theta)\)
Cartesian Conversion
Converting from polar to Cartesian coordinates can help in graphing by translating trigonometric expressions into straight-line formats more familiar in algebra. The formulas integral to this process are:
- \(x = r \cos(\theta)\) which expresses the x-coordinate based on the radial distance and angle.
- \(y = r \sin(\theta)\) which does the same for the y-coordinate.
Graphing Circles
Graphing circles in either polar or Cartesian coordinates involves understanding their geometric properties. In polar coordinates, circles can often be represented with equations like \(r = a \cos(\theta)\) or \(r = a \sin(\theta)\). These describe the path traced out by the set of all the points that satisfy the equation.In Cartesian coordinates, the equation of a circle looks like \((x-h)^2 + (y-k)^2 = r^2\), where \((h,k)\) is the center and \(r\) is the radius of the circle.In our step-by-step solution, the polar equation \(r = 2 \cos(\theta)\) is shown to form such a circle. Through Cartesian conversion, it simplifies to \((x-1)^2 + y^2 = 1\). This shows a clear, visual representation of the circle's location and size:
- The circle is centered at (1,0).
- It has a radius of 1 unit.
- The circle touches the origin at one point, emphasizing its symmetrical nature around the x-axis.