/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 If \(\sin (\theta)=\frac{3}{8}\)... [FREE SOLUTION] | 91Ó°ÊÓ

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If \(\sin (\theta)=\frac{3}{8}\) and \(\theta\) is in the \(2^{\text {nd }}\) quadrant, find \(\cos (\theta)\)

Short Answer

Expert verified
\( \cos(\theta) = -\frac{\sqrt{55}}{8} \)

Step by step solution

01

Understand the Problem

We are given that \( \sin(\theta) = \frac{3}{8} \) and \( \theta \) is in the 2nd quadrant. We need to find \( \cos(\theta) \). In the 2nd quadrant, \( \sin(\theta) \) is positive and \( \cos(\theta) \) is negative.
02

Use the Pythagorean Identity

The Pythagorean identity states that \( \sin^2(\theta) + \cos^2(\theta) = 1 \). We will use this identity to find \( \cos^2(\theta) \). Substitute \( \sin(\theta) = \frac{3}{8} \) into the identity:\[ \left(\frac{3}{8}\right)^2 + \cos^2(\theta) = 1 \]
03

Calculate \( \sin^2(\theta) \)

Calculate \( \sin^2(\theta) \) by squaring \( \frac{3}{8} \):\[ \sin^2(\theta) = \left(\frac{3}{8}\right)^2 = \frac{9}{64} \]
04

Solve for \( \cos^2(\theta) \)

Substitute \( \sin^2(\theta) = \frac{9}{64} \) into the Pythagorean identity:\[ \frac{9}{64} + \cos^2(\theta) = 1 \]Solving for \( \cos^2(\theta) \):\[ \cos^2(\theta) = 1 - \frac{9}{64} = \frac{64}{64} - \frac{9}{64} = \frac{55}{64} \]
05

Find \( \cos(\theta) \)

Now solve for \( \cos(\theta) \) by taking the square root of \( \cos^2(\theta) = \frac{55}{64} \):\[ \cos(\theta) = \pm \sqrt{\frac{55}{64}} \]Since \( \theta \) is in the 2nd quadrant where cosine is negative, we choose the negative root:\[ \cos(\theta) = -\sqrt{\frac{55}{64}} = -\frac{\sqrt{55}}{8} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Second Quadrant
In the world of trigonometry, the circle is divided into four quadrants. The angle \( \theta \) lies in one of these four sections based on its measure. The second quadrant is particularly interesting because it covers angles between 90° and 180° or \( \frac{\pi}{2} \) to \( \pi \) radians.

In the second quadrant, the Sine function, noted as \( \sin(\theta) \), is positive. This means any angle here will have a positive sine value. On the other hand, the Cosine function, \( \cos(\theta) \), will always be negative in this quadrant. This is a key feature to remember when solving trigonometric problems.

Identifying the quadrant is vital as it helps determine the sign of the trigonometric functions, which is crucial for accurate calculations.
Pythagorean Identity
One of the fundamental identities in trigonometry is the Pythagorean Identity. This identity is rooted deeply in the properties of right triangles and the Pythagorean theorem. It states that for any angle \( \theta \), the following is always true:
  • \( \sin^2(\theta) + \cos^2(\theta) = 1 \)
This identity allows us to express one trigonometric function in terms of the other, which can be extremely useful.

In practical terms, if you know the value of \( \sin(\theta) \), you can find \( \cos(\theta) \) by rearranging the identity to \( \cos^2(\theta) = 1 - \sin^2(\theta) \). This rearrangement is especially helpful when one function's value is given, and you need to find the other.

Understanding how to apply this identity is key in solving many trigonometric exercises.
Cosine Function
The Cosine function, \( \cos(\theta) \), is one of the principal trigonometric functions. It describes the x-coordinate of the point on the unit circle corresponding to an angle \( \theta \). This function starts at 1 when \( \theta = 0 \) and varies between -1 and 1 as the angle changes.

In the second quadrant, the cosine values are negative. This means that if you find \( \cos(\theta) \) via the Pythagorean Identity or another method, and \( \theta \) is in this quadrant, your answer should be negative. For example, if you compute \( \cos(\theta) = \pm \sqrt{\frac{55}{64}} \), the correct choice in the second quadrant would be the negative value: \(-\frac{\sqrt{55}}{8}\).

This negative aspect often catches students off guard, making it crucial to note the quadrant when determining the sign for cosine.
Sine Function
The Sine function, denoted as \( \sin(\theta) \), represents the y-coordinate on the unit circle of a corresponding angle \( \theta \). It also modulates between -1 and 1 and is one of the core trigonometric functions used in many applications.

For angles in the second quadrant, the sine function remains positive. So, when given \( \sin(\theta) = \frac{3}{8} \), you can confidently use this value in calculations because it aligns with the expected positive range for sine in that quadrant.

Grasping the behavior of the sine function and how it changes based on the quadrant is vital for correctly solving problems. This understanding dictates how you apply trigonometric identities and solve for unknowns, such as when using the Pythagorean Identity to find \( \cos(\theta) \). Recognizing the signs of these functions in different quadrants can make trigonometry problems much easier to tackle.

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Most popular questions from this chapter

Simplify each of the following to an expression involving a single trig function with no fractions. $$ \frac{\sec (t)-\cos (t)}{\sin (t)} $$

Simplify each of the following to an expression involving a single trig function with no fractions. $$ \frac{\sin ^{2}(t)+\cos ^{2}(t)}{\cos ^{2}(t)} $$

A wheel of radius 14 in. is rotating \(0.5 \mathrm{rad} / \mathrm{sec}\). What is the linear speed \(v\), the angular speed in RPM, and the angular speed in deg/sec?

Erik's disabled sailboat is floating stationary 3 miles East and 2 miles North of Kingston. A ferry leaves Kingston heading toward Edmonds at \(12 \mathrm{mph} .\) Edmonds is 6 miles due east of Kingston. After 20 minutes the ferry turns heading due South. Ballard is 8 miles South and 1 mile West of Edmonds. Impose coordinates with Ballard as the origin. [UW] a) Find the equations for the lines along which the ferry is moving and draw in th lines. b) The sailboat has a radar scope that will detect any object within 3 miles of the sailboat. Looking down from above, as in the picture, the radar region looks lik circular disk. The boundary is the "edge" pr circle around this disc, the interio the inside of the disk, and the exterior is everything outside of the disk (i.e. outside of the circle). Give the mathematical (equation) description of the boundary, interior and exterior of the radar zone. Sketch an accurate picture of radar zone. Sketch an accurate picture of the radar zone by determining where line connecting Kingston and Edmonds would cross the radar zone. c) When does the ferry exit the radar zone? d) Where and when does the ferry exit the radar zone? e) How long does the ferry spend inside the radar zone?

The angle of elevation to the top of a building in New York is found to be 9 degrees from the ground at a distance of 1 mile from the base of the building. Using this information, find the height of the building.

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