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Find the horizontal and vertical intercepts of each equation. $$ h(x)=3 x-5 $$

Short Answer

Expert verified
Vertical intercept at (0, -5) and horizontal intercept at \(\left(\frac{5}{3}, 0\right)\).

Step by step solution

01

Finding the Vertical Intercept

To find the vertical intercept, we need to find the point where the graph of the equation intersects the y-axis. At this point, the value of \(x\) is zero. Substitute \(x = 0\) into the equation \(h(x) = 3x - 5\) to find the vertical intercept. This gives:\[h(0) = 3(0) - 5 = -5\]So, the vertical intercept is \((0, -5)\).
02

Finding the Horizontal Intercept

To find the horizontal intercept, we need to find the point where the graph of the equation intersects the x-axis. At this point, \(h(x)\) or \(y\) is zero. Set \(h(x) = 0\) and solve for \(x\):\[0 = 3x - 5\]Adding 5 to both sides gives:\[3x = 5\]Dividing both sides by 3 gives:\[x = \frac{5}{3}\]So, the horizontal intercept is \(\left(\frac{5}{3}, 0\right)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertical Intercept
The vertical intercept is where a linear function graph crosses the y-axis. To find this point, consider that the x-coordinate of any point along the y-axis is always zero.
A vertical intercept is, essentially, the value of y when x equals zero.
To calculate the vertical intercept for an equation like \( h(x) = 3x - 5 \), you substitute 0 for x, then solve for y, which is represented by \( h(x) \). Let's look at the process:
  • In \( h(x) = 3x - 5 \), substitute 0 for \( x \): \( h(0) = 3(0) - 5 \).
  • Perform the calculation: \( 3(0) - 5 = -5 \).
The vertical intercept, here, is \( (0, -5) \). This means the point \( (0, -5) \) is where the line crosses the y-axis.
Horizontal Intercept
The horizontal intercept is found where a linear graph crosses the x-axis.
This is the point where the value of y is zero. In terms of function notation, this means when \( h(x) = 0 \).
To find this intercept, set the function equal to zero and solve for x.For the linear equation \( h(x) = 3x - 5 \):
  • Start by setting \( h(x) = 0 \), leading to the equation \( 0 = 3x - 5 \).
  • Add 5 to both sides to get \( 3x = 5 \).
  • Finally, divide each side by 3 to isolate x, resulting in \( x = \frac{5}{3} \).
The horizontal intercept is \( \left( \frac{5}{3}, 0 \right) \). This tells you that the line crosses the x-axis at \( x = \frac{5}{3} \).
Solving Linear Equations
Solving linear equations is a fundamental skill in algebra.
Linear equations are typically represented in the form \( ax + b = c \). These equations graph as straight lines and have no exponents or products of variables.
The process of solving them typically involves:
  • Isolating the variable on one side of the equation.
  • Performing the same operation on both sides to maintain equality.
For example, with \( h(x) = 3x - 5 \), if you solve for when \( h(x) = 0 \), you have \( 0 = 3x - 5 \). This simplifies to finding \( x \) by moving constants to one side and then dividing by the coefficient of \( x \). Solving effectively finds us intercepts and other pivotal points in the context of graphing.
x-axis and y-axis Intersections
The intersections on the x-axis and y-axis are crucial for understanding the behavior of linear functions.
These intercepts give valuable insights into where the line touches the coordinate axes, aiding in plotting the graph accurately. - **Y-axis intersection (vertical intercept):** - Occurs where \( x = 0 \).
It tells us the starting value of y if the x variable doesn’t contribute anything, i.e., is null.
- **X-axis intersection (horizontal intercept):** - Occurs where \( y = 0 \).
This point indicates when the function outputs zero.
Understanding these intersections helps visualize and solve practical problems easily. For \( h(x) = 3x - 5 \), the intersections are visually marked at specific points, \( (0, -5) \) for the vertical and \( \left( \frac{5}{3}, 0 \right) \) for the horizontal, forming key parts of the graph's framework.

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