Chapter 6: Problem 28
Evaluate the geometric series. $$ \sum_{k=1}^{90} \frac{5}{7^{k}} $$
Short Answer
Expert verified
The sum of the geometric series is given by \( S = \frac{35}{6}(1-(\frac{1}{7})^{90}) \).
Step by step solution
01
Find the first term (a)
The first term, \(a\), is simply the value of the series when k=1. So, when \(k=1\):
$$
a=\frac{5}{7^{1}} = \frac{5}{7}
$$
02
Find the common ratio (r)
The common ratio, \(r\), is the factor at which each term multiplies to get the next term. In this case:
$$
r=\frac{1}{7}
$$
03
Find the number of terms (n)
The number of terms, \(n\), is simply the difference between the upper and lower bounds of the summation plus 1. So in this case:
$$
n = 90 - 1 +1 = 90
$$
04
Apply the sum formula
Now that we have the values for \(a\), \(r\), and \(n\), we can apply the formula to evaluate the sum of the geometric series:
$$
S = \frac{a(1-r^n)}{1-r} = \frac{\frac{5}{7}(1-(\frac{1}{7})^{90})}{1-\frac{1}{7}}
$$
05
Simplify the expression
Now we simplify the expression:
$$
S = \frac{\frac{5}{7}(1-(\frac{1}{7})^{90})}{\frac{6}{7}}
$$
Next, we can cancel out the common factors in the numerator and the denominator:
$$
S = 5(1-(\frac{1}{7})^{90}) \cdot \frac{7}{6}
$$
06
Final answer
Finally, we get the sum of the geometric series:
$$
S = \frac{35}{6}(1-(\frac{1}{7})^{90})
$$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sum of a Series
When trying to find the sum of a geometric series, it helps to understand the structure of the series itself. A geometric series is a series of terms that have a constant ratio between consecutive terms.
In this case, we are working with the series \( \sum_{k=1}^{90} \frac{5}{7^{k}} \). Finding the sum of this series essentially means adding up all the terms from when \( k = 1 \) to \( k = 90 \).
The formula for the sum of the first \( n \) terms of a geometric series is given by:
In this case, we are working with the series \( \sum_{k=1}^{90} \frac{5}{7^{k}} \). Finding the sum of this series essentially means adding up all the terms from when \( k = 1 \) to \( k = 90 \).
The formula for the sum of the first \( n \) terms of a geometric series is given by:
- \[ S = \frac{a(1 - r^n)}{1 - r} \]
Common Ratio
The "common ratio" is key to understanding a geometric series. In a geometric series, the common ratio is the factor by which we multiply each term to get to the next term.
For example, in the series \( \sum_{k=1}^{90} \frac{5}{7^{k}} \), the common ratio \( r \) is \( \frac{1}{7} \).
This means that each term is \( \frac{1}{7} \) of the previous term. Knowing the common ratio is crucial because it allows us to use the formula for the sum of the series.
Quick Tips:
For example, in the series \( \sum_{k=1}^{90} \frac{5}{7^{k}} \), the common ratio \( r \) is \( \frac{1}{7} \).
This means that each term is \( \frac{1}{7} \) of the previous term. Knowing the common ratio is crucial because it allows us to use the formula for the sum of the series.
Quick Tips:
- Identify the pattern of multiplication in the sequence.
- Divide a subsequent term by its preceding term to find the common ratio.
First Term in a Sequence
To evaluate any sequence, identifying the first term is crucial. The first term, often denoted as \( a \), is the starting point from which all other terms are derived.
In our series \( \sum_{k=1}^{90} \frac{5}{7^{k}} \), the first term is found by substituting \( k = 1 \) into the general term.
So, \( a = \frac{5}{7^1} = \frac{5}{7} \). This first term serves as the foundation for calculating the series sum using the formula.
Finding \( a \) is usually straightforward:
In our series \( \sum_{k=1}^{90} \frac{5}{7^{k}} \), the first term is found by substituting \( k = 1 \) into the general term.
So, \( a = \frac{5}{7^1} = \frac{5}{7} \). This first term serves as the foundation for calculating the series sum using the formula.
Finding \( a \) is usually straightforward:
- Locate the first term in a series, which means the smallest index (here, \( k = 1 \)).
- Evaluate the expression for this first term.
Series Evaluation Method
Understanding the series evaluation method is crucial for solving geometric series problems effectively. When you evaluate a geometric series, like \( \sum_{k=1}^{90} \frac{5}{7^{k}} \), here's a practical approach to follow. First, identify the common ratio \( r \) and the first term \( a \) as fundamental components.
In our series, \( r = \frac{1}{7} \) and \( a = \frac{5}{7} \).
Next, determine the number of terms, \( n \), which is the count of terms you are summing. Here, the series runs from \( k = 1 \) to \( k = 90 \), giving us \( n = 90 \). Once you have \( a \), \( r \), and \( n \), plug them into the sum formula:
In our series, \( r = \frac{1}{7} \) and \( a = \frac{5}{7} \).
Next, determine the number of terms, \( n \), which is the count of terms you are summing. Here, the series runs from \( k = 1 \) to \( k = 90 \), giving us \( n = 90 \). Once you have \( a \), \( r \), and \( n \), plug them into the sum formula:
- \[ S = \frac{a(1 - r^n)}{1 - r} \]