Chapter 5: Problem 37
Show that \(\sin 75^{\circ}=\frac{\sqrt{6}+\sqrt{2}}{4}\)
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Chapter 5: Problem 37
Show that \(\sin 75^{\circ}=\frac{\sqrt{6}+\sqrt{2}}{4}\)
These are the key concepts you need to understand to accurately answer the question.
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Find the smallest positive number \(x\) such that $$ \sin ^{2} x-3 \sin x+1=0 $$
Show (without using a calculator) that $$ \sin 10^{\circ} \cos 20^{\circ}+\cos 10^{\circ} \sin 20^{\circ}=\frac{1}{2} $$
Explain why
$$
\sin ^{-1} t=\tan ^{-1} \frac{t}{\sqrt{1-t^{2}}}
$$
whenever \(-1
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Show that in an isosceles triangle with two sides of length \(b\) and a side of length \(c,\) the angle between the two sides of length \(b\) is $$ 2 \sin ^{-1} \frac{c}{2 b} $$
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