Chapter 2: Problem 106
Find six distinct points whose distance from (3,1) equals 4
Short Answer
Expert verified
The six distinct points whose distance from (3,1) equals 4 are B鈧(7, 1), B鈧(-1, 1), B鈧(7, -1), B鈧(-7, 1), B鈧(-1, -1), and B鈧(1, 1).
Step by step solution
01
Apply the distance formula
According to the distance formula, the distance between A(3,1) and B(x鈧,y鈧) is given by:
\[4 = \sqrt{(x鈧 - 3)^2 + (y鈧 - 1)^2}\]
Square both sides to get rid of the square root symbol:
02
Simplify the equation
After squaring both sides, we get:
\[16 = (x鈧 - 3)^2 + (y鈧 - 1)^2\]
03
Find a point in the first quadrant
In the first quadrant, both x and y are positive. Assume x鈧 > 3 and y鈧 > 1. We can start by trying integer values for x鈧 greater than 3. Let's start with x鈧 = 7. Plugging this into the equation gives:
\[16 = (7 - 3)^2 + (y鈧 - 1)^2\]
\[16 = 4^2 + (y鈧 - 1)^2\]
\[16 - 16 = (y鈧 - 1)^2\]
\[0 = (y鈧 - 1)^2\]
Solving for y鈧,
\[y鈧 - 1 = 0\]
\[y鈧 = 1\]
This gives us our first point: B鈧(7, 1). Now, we will find a point in the other quadrants and then reflect them along the x and y axes to get a total of six distinct points.
04
Find a point in the second quadrant
In the second quadrant, x is negative and y is positive. Assume x鈧 < 3 and y鈧 > 1. Try an integer value for x鈧 less than 3, say x鈧 = -1. Plugging this into the equation gives:
\[16 = (-1 - 3)^2 + (y鈧 - 1)^2\]
\[16 = 4^2 + (y鈧 - 1)^2\]
\[16 - 16 = (y鈧 - 1)^2\]
\[0 = (y鈧 - 1)^2\]
Solving for y鈧,
\[y鈧 - 1 = 0\]
\[y鈧 = 1\]
This gives us our second point: B鈧(-1, 1).
05
Reflect points along x-axis and y-axis
Now, we can reflect B鈧(7,1) and B鈧(-1,1) to get four more points.
Reflection of B鈧 along the x-axis gives us B鈧(7, -1).
Reflection of B鈧 along the y-axis gives us B鈧(-7, 1).
Reflection of B鈧 along the x-axis gives us B鈧(-1, -1).
Reflection of B鈧 along the y-axis gives us B鈧(1, 1).
Now we have six distinct points:
B鈧(7, 1), B鈧(-1, 1), B鈧(7, -1), B鈧(-7, 1), B鈧(-1, -1), B鈧(1, 1)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coordinate Geometry
Coordinate geometry, also known as analytical geometry, combines algebra and geometry to define and study geometric shapes. It involves placing points on the coordinate plane using ordered pairs of numbers, typically representing the x (horizontal) and y (vertical) dimensions. These points, lines, and curves can be analyzed and manipulated using algebraic equations.
The ability to express geometric figures in an algebraic format lets us calculate distances, angles, and other properties. The equation of a line, circle, or any geometric shape can be derived using algebraic methods, offering a powerful way to solve geometric problems.
The ability to express geometric figures in an algebraic format lets us calculate distances, angles, and other properties. The equation of a line, circle, or any geometric shape can be derived using algebraic methods, offering a powerful way to solve geometric problems.
- Understanding exact locations with coordinates (e.g., A(3,1))
- Using the distance formula for determining the space between points
- Translating geometric figures using algebra
Quadrants
In the coordinate plane, the x and y axes divide the space into four quadrants. Each quadrant has distinct characteristics determined by the positivity or negativity of the x and y coordinates:
1. **First Quadrant**: Both x and y values are positive (x > 0, y > 0). Points like (7, 1) fit in this region.
2. **Second Quadrant**: Here, x is negative, and y is positive (x < 0, y > 0), as seen with points like (-1, 1).
3. **Third Quadrant**: Both x and y are negative (x < 0, y < 0), where points such as (-1, -1) reside.
4. **Fourth Quadrant**: In this area, x is positive, and y is negative (x > 0, y < 0), containing points like (7, -1).
1. **First Quadrant**: Both x and y values are positive (x > 0, y > 0). Points like (7, 1) fit in this region.
2. **Second Quadrant**: Here, x is negative, and y is positive (x < 0, y > 0), as seen with points like (-1, 1).
3. **Third Quadrant**: Both x and y are negative (x < 0, y < 0), where points such as (-1, -1) reside.
4. **Fourth Quadrant**: In this area, x is positive, and y is negative (x > 0, y < 0), containing points like (7, -1).
- Understanding how coordinates place a point in a specific quadrant.
- Use of quadrants in solving and mapping mathematical problems.
Reflection
Reflection in coordinate geometry is about creating mirror images of points concerning a line, usually the axes. This process is a transformation that can help in deriving new points from existing ones, effectively expanding our capability to explore geometric properties.
When reflecting a point across the x-axis:
When reflecting a point across the x-axis:
- The x-coordinate remains unchanged.
- The y-coordinate becomes negative if it is positive, and vice versa (e.g., (7, 1) becomes (7, -1)).
- The y-coordinate remains unchanged.
- The x-coordinate changes sign, positive to negative or vice versa (e.g., (7, 1) becomes (-7, 1)).