/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Evaluate the geometric series. ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate the geometric series. $$ \sum_{k=1}^{90} \frac{5}{7^{k}} $$

Short Answer

Expert verified
The sum of the geometric series is given by \( S = \frac{35}{6}(1-(\frac{1}{7})^{90}) \).

Step by step solution

01

Find the first term (a)

The first term, \(a\), is simply the value of the series when k=1. So, when \(k=1\): $$ a=\frac{5}{7^{1}} = \frac{5}{7} $$
02

Find the common ratio (r)

The common ratio, \(r\), is the factor at which each term multiplies to get the next term. In this case: $$ r=\frac{1}{7} $$
03

Find the number of terms (n)

The number of terms, \(n\), is simply the difference between the upper and lower bounds of the summation plus 1. So in this case: $$ n = 90 - 1 +1 = 90 $$
04

Apply the sum formula

Now that we have the values for \(a\), \(r\), and \(n\), we can apply the formula to evaluate the sum of the geometric series: $$ S = \frac{a(1-r^n)}{1-r} = \frac{\frac{5}{7}(1-(\frac{1}{7})^{90})}{1-\frac{1}{7}} $$
05

Simplify the expression

Now we simplify the expression: $$ S = \frac{\frac{5}{7}(1-(\frac{1}{7})^{90})}{\frac{6}{7}} $$ Next, we can cancel out the common factors in the numerator and the denominator: $$ S = 5(1-(\frac{1}{7})^{90}) \cdot \frac{7}{6} $$
06

Final answer

Finally, we get the sum of the geometric series: $$ S = \frac{35}{6}(1-(\frac{1}{7})^{90}) $$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.