/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 67 Find a formula for \(\sin (4 \th... [FREE SOLUTION] | 91Ó°ÊÓ

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Find a formula for \(\sin (4 \theta)\) in terms of \(\cos \theta\) and \(\sin \theta\).

Short Answer

Expert verified
The formula for \(\sin(4\theta)\) in terms of \(\sin\theta\) and \(\cos\theta\) is: \(\sin(4\theta) = 4 \sin\theta \cos\theta (\cos^2\theta - \sin^2\theta)\)

Step by step solution

01

Write down the double-angle formulas for sine and cosine

Recall the double-angle formulas for sine and cosine: 1. \(\sin(2\alpha) = 2 \sin\alpha \cos\alpha\) 2. \(\cos(2\beta) = \cos^2\beta - \sin^2\beta\) We will be using these formulas in the next steps.
02

Apply the double-angle formula for sine to obtain an expression for sin(4θ)

Now, we can replace the angle α with 2θ in the double-angle formula for sine: \(\sin(2(2\theta)) = \sin(4\theta)\) Using the formula \(\sin(2\alpha) = 2 \sin\alpha \cos\alpha\): \(\sin(4\theta) = 2 \sin(2\theta) \cos(2\theta)\) Next, we need expressions for \(\sin(2\theta)\) and \(\cos(2\theta)\) using the double-angle formulas and the angle θ.
03

Find expressions for sin(2θ) and cos(2θ) using the double-angle formulas

Recalling the double-angle formulas, we replace α with θ and β with θ: 1. \(\sin(2\theta) = 2 \sin\theta \cos\theta\) 2. \(\cos(2\theta) = \cos^2\theta - \sin^2\theta\) Now we have expressions for \(\sin(2\theta)\) and \(\cos(2\theta)\) that only involve \(\sin\theta\) and \(\cos\theta\).
04

Substitute the expressions for sin(2θ) and cos(2θ) back into the expression for sin(4θ)

Substitute the expressions for \(\sin(2\theta)\) and \(\cos(2\theta)\) from Step 3 into the expression for \(\sin(4\theta)\): \(\sin(4\theta) = 2 (2 \sin\theta \cos\theta)(\cos^2\theta - \sin^2\theta)\)
05

Simplify the expression for sin(4θ)

Now, simplify the expression by distributing the factor 2: \(\sin(4\theta) = 4 \sin\theta \cos\theta (\cos^2\theta - \sin^2\theta)\) This is the formula for \(\sin(4\theta)\) in terms of the sine and cosine of θ.

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Show that $$\cos (2 \theta) \leq \cos ^{2} \theta$$ for every angle \(\theta\).

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