Chapter 5: Problem 6
The next two exercises emphasize that \(\cos \frac{\theta}{2}\) does not equal \(\frac{\cos \theta}{2}\). For \(\theta=-80^{\circ},\) evaluate each of the following: (a) \(\cos \frac{\theta}{2}\) (b) \(\frac{\cos \theta}{2}\)
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Chapter 5: Problem 6
The next two exercises emphasize that \(\cos \frac{\theta}{2}\) does not equal \(\frac{\cos \theta}{2}\). For \(\theta=-80^{\circ},\) evaluate each of the following: (a) \(\cos \frac{\theta}{2}\) (b) \(\frac{\cos \theta}{2}\)
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Show that $$\tan \frac{x}{4}=\frac{\sqrt{2-2 \cos x}-\sin x}{1-\cos x}$$ for all \(x\) in the interval \((0,2 \pi)\). [Hint: Start with a half-angle formula for tangent to express \(\tan \frac{x}{4}\) in terms of \(\sin \frac{x}{2}\) and \(\cos \frac{x}{2}\). Then use half-angle formulas for cosine and sine, along with algebraic manipulations.]
Evaluate the indicated expressions assuming that $$ \begin{array}{ll} \cos x=\frac{1}{3} & \text { and } \sin y=\frac{1}{4} \\ \sin u=\frac{2}{3} & \text { and } \cos v=\frac{1}{5} \end{array} $$ Assume also that \(x\) and \(u\) are in the interval \(\left(0, \frac{\pi}{2}\right),\) that \(y\) is in the interval \(\left(\frac{\pi}{2}, \pi\right),\) and that \(v\) is in the interval \(\left(-\frac{\pi}{2}, 0\right) .\) $$\tan (x-y)$$
Find angles \(u\) and \(v\) such that \(\sin (2 u)=\sin (2 v)\) but \(|\sin u| \neq|\sin v|\).
Show that \(\sin \frac{\pi}{18}\) is a zero of the polynomial \(8 x^{3}-6 x+1\) [Hint: Use the identity from the previous problem.]
Do not make the mistake of thinking that $$\frac{\cos (2 \theta)}{2}=\cos \theta$$ is a valid identity. (a) Show that the equation above is false whenever \(0<\theta<\frac{\pi}{2}\) (b) Show that there exists an angle \(\theta\) in the interval \(\left(\frac{\pi}{2}, \pi\right)\) satisfying the equation above.
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