Chapter 3: Problem 11
Estimate the indicated value without using a calculator. \(\frac{e^{9}}{e^{8.997}}\)
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Chapter 3: Problem 11
Estimate the indicated value without using a calculator. \(\frac{e^{9}}{e^{8.997}}\)
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Find the number \(t\) that makes \(e^{t^{2}+6 t}\) as small as possible. $$ \text { [Here } e^{t^{2}+6 t} \text { means } e^{\left(t^{2}+6 t\right)} \text { .] } $$
Find a formula for the inverse function \(f^{-1}\) of the indicated function \(f\). $$ f(x)=6^{x}+7 $$
For \(x=1.1\) and \(y=5\), evaluate each of the following: (a) \(\ln (x y)\) (b) \((\ln x)(\ln y)\)
Find \(a\) formula for \((f \circ g)(x)\) assuming that \(f\) and \(g\) are the indicated functions. \(f(x)=\ln x\) and \(g(x)=e^{5 x}\)
Suppose \(f\) is the function defined by $$ f(x)=\cosh x $$ for every \(x \geq 0\). In other words, \(f\) is defined by the same formula as cosh, but the domain of \(f\) is the interval \([0, \infty)\) and the domain of cosh is the set of real numbers. Show that \(f\) is a one-to-one function and that its inverse is given by the formula $$ f^{-1}(y)=\ln \left(y+\sqrt{y^{2}-1}\right) $$ for every \(y \geq 1\).
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