/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Find integers \(m\) and \(n\) su... [FREE SOLUTION] | 91Ó°ÊÓ

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Find integers \(m\) and \(n\) such that \(2^{m} \cdot 5^{n}=16000\).

Short Answer

Expert verified
The integers $m$ and $n$ satisfying the given equation \(2^m \cdot 5^n=16000\) are \(m = 7\) and \(n = 3\).

Step by step solution

01

Prime factorize 16000

To find the correct exponents for 2 and 5, we need to prime factorize the number 16000. When prime factorized, the number will be represented as a product of powers of prime factors. \( 16000 = 2^4 \cdot 1000 = 2^4 \cdot 2^3 \cdot 125 = 2^7 \cdot 5^3 \)
02

Match the prime factors to the given expression

Now that we have the prime factors, we can compare them to the given expression \(2^m \cdot 5^n\). We can see that in the factorization, \(2^7\) represents the first part of the expression, and \(5^3\) represents the second part.
03

Identify the values of m and n

Based on the prime factorization we obtained, we have \(2^7 \cdot 5^3 \). So we can deduce the values of m and n as follows: \( m = 7 \) \( n = 3 \) So the integers m and n satisfying the given equation \(2^m \cdot 5^n=16000\) are \(m = 7\) and \(n = 3\).

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