/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Simplify the given expression by... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify the given expression by writing it as a power of a single variable. $$ y^{4}\left(y^{3}\right)^{5} $$

Short Answer

Expert verified
The simplified expression for the given problem is \(y^{19}\).

Step by step solution

01

Identify the power rule

In our given expression, we have a power raised to another power: \((y^{3})^{5}\). We will apply the power rule, which states that \((a^m)^n = a^{mn}\). In our case, the base is 'y', m is 3, and n is 5.
02

Apply the power rule

Applying the power rule to the given expression: \[ (y^3)^5 = y^{(3 * 5)} \]
03

Simplify exponent

Multiply 3 by 5 to simplify the exponent: \[ y^{(3 * 5)} = y^{15} \] Now the original expression becomes: \[ y^{4}\left(y^{3}\right)^{5} = y^4 \cdot y^{15} \]
04

Apply the product rule of exponents

When two exponential expressions with the same base are multiplied, we can add their exponents. This is called the product rule of exponents, which states that \(a^m \cdot a^n = a^{m+n}\). In our case, the base is 'y', m is 4, and n is 15. Apply the product rule: \[ y^4 \cdot y^{15} = y^{(4 + 15)} \]
05

Simplify the final expression

Add 4 and 15: \[ y^{(4 + 15)} = y^{19} \] Therefore, the simplified expression for the given problem is \(y^{19}\).

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Most popular questions from this chapter

Let \(p\) be the polynomial defined by $$p(x)=x^{6}-87 x^{4}-92 x+2$$. (a)Evaluate \(p(-2), p(-1), p(0),\) and \(p(1)\). (b) Explain why the results from part (a) imply that \(p\) has a zero in the interval (-2,-1) and \(p\) has a zero in the interval (0,1) . (c) Show that \(p\) has at least four zeros in the interval [-10,10] . [Hint: We already know from part ( \(b\) ) that \(p\) has at least two zeros is the interval [-10,10] . You can show the existence of other zeros by finding integers \(n\) such that one of the numbers \(p(n)\), \(p(n+1)\) is positive and the other is negative.]

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