Chapter 2: Problem 131
Show that \(\sqrt{9-4 \sqrt{5}}=\sqrt{5}-2\).
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Chapter 2: Problem 131
Show that \(\sqrt{9-4 \sqrt{5}}=\sqrt{5}-2\).
These are the key concepts you need to understand to accurately answer the question.
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Suppose \(a, b,\) and \(c\) are integers and that $$ p(x)=a x^{3}+b x^{2}+c x+9 $$ Explain why every zero of \(p\) that is an integer is contained in the set \\{-9,-3,-1,1,3,9\\}.
Explain why the polynomial \(p\) defined by $$ p(x)=x^{6}+100 x^{2}+5 $$ has no real zeros.
Write the domain of the given function \(r\) as a union of intervals. $$ r(x)=\frac{5 x^{3}-12 x^{2}+13}{x^{2}-7} $$
Without doing any calculations or using a calculator, explain why $$ x^{2}+87559743 x-787727821 $$ has no integer zeros. [Hint: If \(x\) is an odd integer, is the expression above even or odd? If \(x\) is an even integer, is the expression above even or odd?]
Write the indicated expression as a ratio of polynomials, assuming that $$ r(x)=\frac{3 x+4}{x^{2}+1}, \quad s(x)=\frac{x^{2}+2}{2 x-1}, \quad t(x)=\frac{5}{4 x^{3}+3} $$. $$ (4 r+5 s)(x) $$
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