/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Evaluate \(\lim _{n \rightarrow ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate \(\lim _{n \rightarrow \infty}\left(1+\frac{3}{n}\right)^{n}\)

Short Answer

Expert verified
The limit \(\lim_{n\to\infty} \left(1+\frac{3}{n}\right)^n = e^3\).

Step by step solution

01

Rewrite the expression with a substitution#

In order to manipulate the expression into a more convenient form, let's define a new variable \(x = \frac{3}{n}\). Then, we have \(n = \frac{3}{x}\). Now, rewrite the expression as: \(\lim _{x \rightarrow 0}\left(1+x\right)^{\left(\frac{3}{x}\right)}\). We can see that as \(n\) approaches infinity, \(x\) approaches 0.
02

Rewriting the power of the expression#

Recall that \(a^{bc} = (a^b)^c\). By using this rule, we can rewrite the expression as: \(\lim _{x \rightarrow 0}\left[\left(1+x\right)^{\left(\frac{1}{x}\right)}\right]^3\). Now, the expression inside the square brackets is reminiscent of the definition of the number \(e\).
03

Evaluate the limit#

We know that \(\lim _{x\rightarrow 0}\left(1+x\right)^{\frac{1}{x}} = e\). So our expression becomes: \[\lim _{x \rightarrow 0}\left[\left(1+x\right)^{\left(\frac{1}{x}\right)}\right]^3 = e^3.\] Therefore, the limit we were looking for is equal to \(e^3\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.