Chapter 6: Problem 50
Verify that for \(n=4\), the formula given by the previous problem reduces to the usual formula for the area of a square.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 6: Problem 50
Verify that for \(n=4\), the formula given by the previous problem reduces to the usual formula for the area of a square.
All the tools & learning materials you need for study success - in one app.
Get started for free
Assume that \(f\) is the function defined by $$ f(x)=a \cos (b x+c)+d $$ Find values for \(a\) and \(d\), with \(a>0\), so that \(f\) has range [-8,6] .
Explain why a function of the form $$ a \cos (-7 x+c) $$ where \(a\) and \(c\) are constants, can be rewritten in the form $$ a \cos (7 x+\widetilde{c}) $$ where \(\tilde{c}\) is a constant. What is the relationship between \(\tilde{c}\) and \(c\) ?
Suppose \(-\frac{\pi}{2}<\theta<0\) and \(\cos \theta=0.3 .\) (a) Without using a double-angle formula, evaluate \(\cos (2 \theta)\). (b) Without using an inverse trigonometric function, evaluate \(\cos (2 \theta)\) again.
Show that $$ (\cos \theta+\sin \theta)^{2}(\cos \theta-\sin \theta)^{2}+\sin ^{2}(2 \theta)=1 $$ for all angles \(\theta\).
Without doing any algebraic manipulations, explain why $$ \left(2 \cos ^{2} \theta-1\right)^{2}+(2 \cos \theta \sin \theta)^{2}=1 $$ for every angle \(\theta\).
What do you think about this solution?
We value your feedback to improve our textbook solutions.