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Use the dot product to find the angle between the vectors (2,3) and (3,4) .

Short Answer

Expert verified
The angle between the vectors (2,3) and (3,4) is approximately \(26.4^{\circ}\).

Step by step solution

01

Find the dot product

Calculate the dot product of the two given vectors (2,3) and (3,4) using the formula \((a_1b_1+a_2b_2)\), where \((a_1,a_2)\) and \((b_1,b_2)\) are the components of the vectors: \[\text{Dot product} = (2 \times 3) + (3 \times 4)\]
02

Calculate the dot product

Use the formula from Step 1 to find the dot product of vectors (2,3) and (3,4): \[\text{Dot product} = (2 \times 3) + (3 \times 4) = 6+12 =18\]
03

Find the magnitudes of each vector

Calculate the magnitude of each vector, (2,3) and (3,4), using the formula \(||\vec{a}|| = \sqrt{a_1^2+a_2^2}\): \[||\vec{a}|| = \sqrt{2^2+3^2} = \sqrt{4+9} = \sqrt{13}\] \[||\vec{b}|| = \sqrt{3^2+4^2} = \sqrt{9+16} = \sqrt{25} = 5\]
04

Use the dot product formula to find the cosine of the angle

Use the dot product formula to find the cosine of the angle between the two vectors: \[\cos(\theta) = \frac{\text{Dot product}}{||\vec{a}|| \times ||\vec{b}||} = \frac{18}{\sqrt{13} \times 5}\]
05

Find the angle

To find the angle between the two vectors, apply the arccosine function to the cosine value calculated in Step 4: \[\theta = \arccos(\frac{18}{\sqrt{13} \times 5})\] Now, use a calculator to find the approximate value of the angle in degrees: \[\theta \approx 26.4^{\circ}\] Therefore, the angle between the vectors (2,3) and (3,4) is approximately 26.4 degrees.

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