Chapter 5: Problem 34
Explain why
$$
\sin ^{-1} t=\tan ^{-1} \frac{t}{\sqrt{1-t^{2}}}
$$
whenever \(-1
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These are the key concepts you need to understand to accurately answer the question.
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Chapter 5: Problem 34
Explain why
$$
\sin ^{-1} t=\tan ^{-1} \frac{t}{\sqrt{1-t^{2}}}
$$
whenever \(-1
These are the key concepts you need to understand to accurately answer the question.
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Find exact expressions for the indicated quantities, given that $$ \cos \frac{\pi}{12}=\frac{\sqrt{2+\sqrt{3}}}{2} \text { and } \sin \frac{\pi}{8}=\frac{\sqrt{2-\sqrt{2}}}{2} $$ [These values for \(\cos \frac{\pi}{12}\) and \(\sin \frac{\pi}{8}\) will be derived in Examples 4 and 5 in Section 6.3.] $$ \tan \frac{3 \pi}{8} $$
Show that $$ \frac{\sin x}{1-\cos x}=\frac{1+\cos x}{\sin x} $$ for every number \(x\) that is not an integer multiple of \(\pi\).
Evaluate \(\tan \left(\sin ^{-1} \frac{2}{5}\right)\)
Suppose a 25 -foot ladder is leaning against a wall, making a \(63^{\circ}\) angle with the ground (as measured from a perpendicular line from the base of the ladder to the wall). How high up the wall is the end of the ladder?
Find exact expressions for the indicated quantities, given that $$ \cos \frac{\pi}{12}=\frac{\sqrt{2+\sqrt{3}}}{2} \text { and } \sin \frac{\pi}{8}=\frac{\sqrt{2-\sqrt{2}}}{2} $$ [These values for \(\cos \frac{\pi}{12}\) and \(\sin \frac{\pi}{8}\) will be derived in Examples 4 and 5 in Section 6.3.] $$ \cos \frac{5 \pi}{12} $$
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