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Find the four smallest positive numbers \(\theta\) such that \(\cos \theta=\frac{1}{2}\)

Short Answer

Expert verified
The four smallest positive numbers θ such that \(\cos{\theta} = \frac{1}{2}\) are: 1. \(\theta_1 = \frac{\pi}{3}\) 2. \(\theta_2 = \frac{5\pi}{3}\) 3. \(\theta_3 = \frac{7\pi}{3}\) 4. \(\theta_4 = \frac{11\pi}{3}\)

Step by step solution

01

Identify Quadrants With Cosine Equal to 1/2

Since cosine is positive in the first and fourth quadrants, we'll first find the angles in those quadrants whose cosine values equal 1/2.
02

Use Reference Angles

The reference angle for which \(\cos{\theta} = \frac{1}{2}\) is 60 degrees or \(\frac{\pi}{3}\) radians in the first and fourth quadrants. To find the corresponding angles in both the first and fourth quadrants in radians, we can use the formulas: 1. θ in first quadrant: \(\theta = \frac{\pi}{3}\) 2. θ in fourth quadrant: \(\theta = 2\pi - \frac{\pi}{3}\)
03

Calculate The Two Smallest Positive Angles

Calculate the angles in the first and fourth quadrants using the formulas from Step 2: 1. θ in first quadrant: \(\theta_1 = \frac{\pi}{3} = \frac{\pi}{3} \text{ radians}\) 2. θ in fourth quadrant: \(\theta_2 = 2\pi - \frac{\pi}{3} = \frac{5\pi}{3} \text{ radians}\) These are the two smallest positive angles that satisfy \(\cos{\theta} = \frac{1}{2}\).
04

Use Periodicity of Cosine Function

As the cosine function has a period of \(2\pi\), we can obtain the next smallest solutions by adding multiples of \(2\pi\) to the angles found in Step 3: 3. Third smallest angle: \(\theta_3 = \theta_1 + 2\pi = \frac{\pi}{3} + 2\pi = \frac{7\pi}{3} \text{ radians}\) 4. Fourth smallest angle: \(\theta_4 = \theta_2 + 2\pi = \frac{5\pi}{3} + 2\pi = \frac{11\pi}{3} \text{ radians}\)
05

Write the Solution

The four smallest positive numbers θ such that \(\cos{\theta} = \frac{1}{2}\) are: 1. \(\theta_1 = \frac{\pi}{3}\) 2. \(\theta_2 = \frac{5\pi}{3}\) 3. \(\theta_3 = \frac{7\pi}{3}\) 4. \(\theta_4 = \frac{11\pi}{3}\)

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