/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 A constant function is a functio... [FREE SOLUTION] | 91Ó°ÊÓ

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A constant function is a function whose value is the same at every number in its domain. For example, the function \(f\) defined by \(f(x)=4\) for every number \(x\) is a constant function. Suppose \(f\) is an even function and \(g\) is an odd function such that the composition \(f \circ g\) is defined. Show that \(f \circ g\) is an even function.

Short Answer

Expert verified
We can show that \(f \circ g\) is an even function by demonstrating that \(f\circ g(x) = f\circ g(-x)\) for all x. Given that \(f\) is even and \(g\) is odd, we have \(f(x) = f(-x)\) and \(g(x) = -g(-x)\). Then, \(f \circ g(-x) = f(g(-x)) = f(-g(x)) = f(g(x)) = f\circ g(x)\), proving that \(f \circ g\) is an even function.

Step by step solution

01

State the definition of an even function and an odd function

In order to begin this proof, we need to know the definitions of even and odd functions. An even function, \(f\), satisfies the equation: \(f(x) = f(-x)\) for all \(x\). An odd function, \(g\), satisfies the equation: \(g(x) = -g(-x)\) for all \(x\).
02

Write down the composite function f ∘ g(x)

Now, we need to analyze the composite function \(f \circ g(x)\). By definition, \(f \circ g(x) = f(g(x))\).
03

Replace x with -x in f ∘ g(x)

Next, let's find the expression for \(f \circ g(-x)\). By replacing \(x\) with \(-x\) in the definition of the composite function, we get: \(f \circ g(-x) = f(g(-x))\)
04

Use the properties of even and odd functions to simplify f ∘ g(-x)

Now we will use the properties of even and odd functions to simplify \(f(g(-x))\). Since \(g\) is an odd function, we can substitute \(-g(x)\) for \(g(-x)\): \(f \circ g(-x) = f(-g(x))\) Since \(f\) is an even function, we can substitute \(f(x)\) for \(f(-x)\): \(f \circ g(-x) = f(g(x))\)
05

Show that f ∘ g(x) is an even function

From step 4, we found that \(f \circ g(-x) = f(g(x))\), which is equal to \(f \circ g(x)\). Therefore, we demonstrated that \(f \circ g(x) = f \circ g(-x)\) for all \(x\), which means that \(f \circ g\) is an even function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant Function
Understanding a constant function is quite straightforward: it always expresses the same value, no matter what input you throw at it. If you imagine a graph, the constant function would simply be a straight horizontal line. This function is defined as some constant value that does not change, regardless of the input variable. For instance, if we consider the function \(f(x) = c\), where \(c\) is a constant number, the output value would be \(c\) for any and every input value \(x\). The constancy makes these functions predictable and easy to recognize. It's important to note that constant functions are indeed even functions. This is because they satisfy the fundamental criterion for even functions: \(f(x) = f(-x)\) for all \(x\) in the domain, as there is no change whether the input is positive or negative.
Function Composition
Think of function composition, denoted \( f \circ g \) or \( f(g(x)) \), as a two-step process where you first apply one function and then feed its result into another. It's like a functional conveyor belt: the output of one function becomes the input to the next. Imagine plugging in a number into \(g\), getting a result, and then plugging that result into \(f\). The final output you get represents the composite function \( f \circ g \) at your initial input. When you evaluate \( f \circ g \) at \( x \), you're essentially looking for \( f(g(x)) \)—what happens when \(g\) eats \(x\) and then \(f\) eats what comes out!
Properties of Even Functions
Even functions are like the mathematical version of a perfectly symmetrical object. They show symmetry about the y-axis on a graph. In other words, if you fold the graph along the y-axis, both halves will match up perfectly. This symmetry is not just visually appealing but also tells us something important: for every point \( (x, f(x)) \) on the graph, there is a mirror image point \( (-x, f(x)) \). Mathematically, the defining property of even functions is \(f(x) = f(-x)\) for every \(x\) within the function's domain. This means that if you input the opposite number, you'll end up with the same exact output.
Properties of Odd Functions
Now, let's talk about odd functions, which, much like even functions, have their own type of symmetry—but it's a bit different. Their graphs showcase rotational symmetry around the origin. Spin the graph 180 degrees, and it looks just the same as it did before the spin. Algebraically, they are characterized by the property \(g(x) = -g(-x)\) for every \(x\) in their domain. This essentially means that if you plug in the negative counterpart of an input, the output is simply the negative version of the original output. The takeaway is that odd functions are inherently linked to the concept of opposites.

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Most popular questions from this chapter

Suppose \(f\) and \(g\) are functions, each of whose domain consists of four numbers, with \(f\) and \(g\) defined by the tables below: $$ \begin{array}{c|c} {x} & {f}({x}) \\ \hline {1} & 4 \\ 2 & 5 \\ 3 & 2 \\ 4 & 3 \end{array} $$ $$ \begin{array}{c|c} x & g(x) \\ \hline 2 & 3 \\ 3 & 2 \\ 4 & 4 \\ 5 & 1 \end{array} $$ Give the table of values for \(f \circ g\).

Find two different functions whose domain is {3,8} and whose range is {-4,1}

The result box following Example 2 could have been made more complete by including explicit information about the domain and range of the functions \(g\) and \(h\). For example, the more complete result box might have looked like the one shown here: Shifting a graph up or down Suppose \(f\) is a function and \(a>0 .\) Define functions \(g\) and \(h\) by \(g(x)=f(x)+a\) and \(h(x)=f(x)-a\) Then \- \(g\) and \(h\) have the same domain as \(f\); \- the range of \(g\) is obtained by adding \(a\) to every number in the range of \(f\); \- the range of \(h\) is obtained by subtracting \(a\) from every number in the range of \(f\); the graph of \(g\) is obtained by shifting the graph of \(f\) up \(a\) units; \- the graph of \(h\) is obtained by shifting the graph of \(f\) down \(a\) units. Construct similar complete result boxes, including explicit information about the domain and range of the functions \(g\) and \(h,\) for each of the other three result boxes in this section that deal with function transformations.

Draw the graph of a function that is increasing on the interval [-2,0] and decreasing on the interval \([0,2] .\)

Give an example to show that the sum of two one-to-one functions is not necessarily a one to-one function.

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