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Use a graphing utility to graph the polar equation. Find an interval for \(\boldsymbol{\theta}\) for which the graph is traced only once. $$r^{2}=16 \sin 2 \theta$$

Short Answer

Expert verified
The graph is traced only once for \(\theta\) in the interval \([0, 2\pi]\).

Step by step solution

01

Rewrite the equation in x and y

The polar equation \(r^{2}=16 \sin 2 \theta\) can be rewritten using the Cartesian form \(x = r \cos \(\theta\) \) and \(y = r \sin \(\theta\)\) as \(x^2 + y^2 = 16y\).
02

Draw the Cartesian graph

Use a graphing utility to plot the equation \(x^2 + y^2 = 16y\) in a graph. This equation represents a circle with its center at (0, 8) and radius 8.
03

Find the interval for theta

Now, notice that the circle starts at the point (0,16) when \(\theta = 0\) and traces the circle until it reaches the starting point again when \(\theta\) equals one complete rotation, i.e., \(2\pi\). Thus, the interval for \(\theta\) where the graph is traced only once is \([0, 2\pi]\).

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